RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A

These Solutions are part of RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A.

Question 1.
Solution:
Base of the triangle (b) = 24cm and height (h) = 14.5 cm
∴ Area = \(\frac { 1 }{ 2 } \) x b x h = \(\frac { 1 }{ 2 } \) x 24 x 14.5 cm²
= 174 cm² Ans.

Question 2.
Solution:
Let the length of altitude of the triangular field = x then its base = 3x.
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q2.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q2.2

Question 3.
Solution:
Sides of a triangle = 42cm, 34cm and 20cm
Let a = 42cm, b = 34cm and c = 20 cm
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q3.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q3.2

Question 4.
Solution:
Sides of the triangle = 18cm, 24cm and 30cm
Let a = 18 cm, b = 24 cm and c = 30cm
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q4.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q4.2

Question 5.
Solution:
Sides of triangular field ABC arc 91m, 98m and 105m
Let AC be the longest side
∴ BD⊥AC
Here a = 98m, b = 105m and c = 91m
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q5.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q5.2

Question 6.
Solution:
Perimeter of triangle = 150m
Ratio in the sides = 5:12:13
Let sides be 5x, 12x and 13x
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q6.1

Question 7.
Solution:
Perimeter of a triangular field = 540m
Ratio is its sides = 25 : 17 : 12
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q7.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q7.2

Question 8.
Solution:
Perimeter of the triangular field = 324 m
Length of the sides are 85m and 154m
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q8.1

Question 9.
Solution:
Length of sides are
13 cm, 13 cm and 20cm
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q9.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q9.2

Question 10.
Solution:
Base of the isosceles triangle ABC = 80cm
Area = 360 cm²
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q10.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q10.2

Question 11.
Solution:
Perimeter of the triangle
ABC = 42 cm.
Let length of each equal sides = x
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q11.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q11.2
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q11.3

Question 12.
Solution:
Area of equilateral triangle = 36√3 cm².
Let length of each side = a
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q12.1

Question 13.
Solution:
Area of equilateral triangle = 81√3 cm²
Let length of each side = a
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q13.1

Question 14.
Solution:
∆ ABC is a right angled triangle, right angle at B.
∴ BC 48cm and AC = 50cm
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q14.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q14.2

Question 15.
Solution:
Each side of equilateral triangle
(a) = 8cm.
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q15.1

Question 16.
Solution:
Let a be the each side of
the equilateral triangle.
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q16.1

Question 17.
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q17.1
Solution:
The given umbrella has 12 triangular pieces of the size 50cm x 20cm x 50cm. We see that each piece is of an isosceles triangle shape and we have to find firstly area of one such triangle.
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q17.2
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q17.3

Question 18.
Solution:
The given floral design is made of 16 tiles
The size of each tile is 16cm 12cm, 20cm
Now we have to find the area of firstly one tile
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q18.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q18.2
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q18.3

Question 19.
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q19.1
Solution:
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q19.2
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q19.3

Question 20.
Solution:
In the figure, ABCD is a quadrilateral
AB = 42 cm, BC = 21 cm, CD = 29 cm,
DA = 34 cm and ∠CBD = 90°
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q20.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q20.2

Question 21.
Solution:
from the figure
∆DAB
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q21.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q21.2

Question 22.
Solution:
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q22.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q22.2

Question 23.
Solution:
from the figure,
We know that
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q23.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q23.2

Question 24.
Solution:
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q24.1
RS Aggarwal Class 9 Solutions Chapter 7 Areas Ex 7A Q24.2

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