Category: CBSE Class 6

NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.3.

• Data Handling Class 6 Ex 9.1
• Data Handling Class 6 Ex 9.2
• Data Handling Class 6 Ex 9.4

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 9
Chapter Name	Data Handling
Exercise	Ex 9.3
Number of Questions Solved	3
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.3

Question 1.
The bar graph given alongside shows the amount of wheat purchased by the government during the years 1998-2002:
Read the bar graph and write down your observations. In which year was
(a) the wheat production maximum?
(b) the wheat production minimum?

Solution.
(a) The wheat production was maximum in the year 2002.
(b) The wheat production was minimum in the year 1998.

Question 2.
Observe this bar graph which is showing the sale of shirts in a ready made shop from Monday to Saturday.

Now answer the following questions:
(a) What information does the above bar graph give?
(b) What is the scale chosen on the horizontal line representing a number of shills?
(c) On which day were the maximum number of shirts sold? How many shirts were sold on that day?
(d) On which day were the minimum number of shirts sold?
(e) How many shirts were sold on Thursday?
Solution.
(a) This bar graph shows the number of shirts sold from Monday to Saturday.
(b) 1 unit = 5 shirts
(c) Saturday, 60
(d) Tuesday
(e) 35 shirts.

Question 3.
Observe this bar graph which shows the marks obtained by Aziz in half-yearly examination in different subjects.
Answer the given questions.
(a) What information does the bar graph give ?
(b) Name the subject in which Aziz scored maximum marks.
(c) Name the subject in which he has scored minimum marks.
(d) State the name of the subjects and marks obtained in each of them

Solution.
(a) This bar graph shows the marks obtained by Aziz in different subjects.
(b) Hindi
(c) Social Studies
(d) Hindi-80, English-60, Mathematics-70, Science-50 and Social Studies -40.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.3 help you. If you have any query regarding. NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.3, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.2.

• Data Handling Class 6 Ex 9.1
• Data Handling Class 6 Ex 9.3
• Data Handling Class 6 Ex 9.4

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 9
Chapter Name	Data Handling
Exercise	Ex 9.2
Number of Questions Solved	2
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.2

Question 1.
Total number of animals in five villages are as follows:
Village A : 80
Village B  : 120
Village C  : 90
Village D  : 40
Village E  : 60
Prepare a pictograph of these animals using one symbol ⊗ to represent 10 animals and answer the following questions:
(i) How many symbols represent animals of village E?
(ii) Which village has the maximum number of animals?
(iii) Which village has more animals: Village A or village C?
Solution.

(i) 6 symbols represent animals of village E.
(ii) Village B has the maximum number of animals.
(iii) Village C has more animals than village A.

Question 2.
The total number of students in a school in different years is shown in the following table:

Year	Number of students
1996	400
1998	535
2000	472
2002	600
2004	623

A. Prepare a pictograph of students using one symbol to represent 100 students and answer the following questions:
(i) How many symbols represent total number of students in the year 2002?
(ii) How many symbols represent total number of students for the year 1998?
B. Prepare another pictograph of students using any other symbol each representing 50 students. Which pictograph do you find more informative?
Solution.
(A)

(i) 6 symbols represent total number of students in the year 2002.
(ii) 0 5 complete and 1 incomplete symbols represent total number of students for the year 1998.

(B)

Pictograph B is more informative because it gives better approximations.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.2 help you. If you have any query regarding. NCERT Solutions for Class 6 Maths Chapter 9 Data Handling Ex 9.2 drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.6 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.6.

• Decimals Class 6 Ex 8.1
• Decimals Class 6 Ex 8.2
• Decimals Class 6 Ex 8.3
• Decimals Class 6 Ex 8.4
• Decimals Class 6 Ex 8.5

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 8
Chapter Name	Decimals
Exercise	Ex 8.6
Number of Questions Solved	7
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.6

Question 1.
Subtract
(a) ₹ 18.25 from ₹ 20.75
(b) ₹ 25from ₹ 20.75
(c) 54 mfrom 250 m
(d) ₹ 36 from ₹ 8.40
(e) 2.051 km from 5.206 km
(f) 0.314 kg from 2.107 kg.
Solution.

Question 2.
Find the value of:
(a) 9.756 – 6.28
(b) 21.05 – 15.27
(c) 18.5 – 6.79
(d) 11.6- 9.847.
Solution.

Question 3.
Raju bought a book for ₹ 35.65. Did he give? 50 to the shopkeeper. How much money did he get back from the shopkeeper?
Solution.
Book bought for = ₹ 35.65
Money is given to the shopkeeper = ₹ 50
∴ Money got back from the shopkeeper
= ₹ 50 – ?35.65
= ₹ 14.35

Question 4.
Rani had ₹ 18.50. She bought one ice-cream for ₹ 11.75. How much money does she have now?
Solution.
Money Rani had = ₹ 18.50
Ice-cream bought for = ₹ 11. 75
∴ Money she has now = ₹ 18.50 – ₹ 11. 75
= ₹ 6.75

Question 5.
Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?
Solution.
Length of cloth Tina had

Question 6.
Namita travels 20 km 50 m everyday. Out of this, she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?
Solution.
Distance travelled everyday
= 20 km 50 m = 20 km + 50 m
= 20 km +\(\frac { 50 }{ 1000 } \) km

Question 7.
Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?
Solution.
Weight of vegetables bought = 10 kg
Weight of onions = 3 kg 500 g = 3 kg + 500 g

We hope the NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.6 help you. If you have any query regarding. NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.6, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.5 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.5.

• Decimals Class 6 Ex 8.1
• Decimals Class 6 Ex 8.2
• Decimals Class 6 Ex 8.3
• Decimals Class 6 Ex 8.4
• Decimals Class 6 Ex 8.6

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 8
Chapter Name	Decimals
Exercise	Ex 8.5
Number of Questions Solved	7
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.5

Question 1.
Find the sum in each of the following:
(a) 0.007+8.5+30.08
(b) 15 + 0.632 + 13.8
(c) 27.076 + 0.55 + 0.004
(d) 25.65 + 9.005 + 3.7
(e) 0.75 + 10.425 + 2
(f) 280.69 + 25.2 + 38.
Solution.

Question 2.
Rashid spent Rs.35.75 for Maths book and Rs.32.60 for Science book. Find the total amount spent by Rashid.
Solution.
Money spent for Maths book = Rs. 35.75
Money spent for Science book = Rs. 32.60
Total amount spent by Rashid = Rs. 35.75 +Rs.32.60
= Rs. 68.35.

Question 3.
Radhika’s mother gave her ? 10.50 and her father gave her ? 15.80, find the total amount given to Radhika by the parents.
Solution.
Money given by mother = Rs. 10.50
Money given by father = Rs. 15.80
Total amount given to Radhika by parents = Rs. 10.50 +Rs.15.80 =Rs. 26.30

Question 4.
Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.
Solution.
Cloth bought for her shirt

Question 5.
Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?
Solution.
Distance walked by Naresh in the morning

Question 6.
Sunita travels 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?
Solution.

Question 7.
Ravi purchased 5 kg 400 grice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.
Solution.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.5 help you. If you have any query regarding. NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.5, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.4 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.4.

• Decimals Class 6 Ex 8.1
• Decimals Class 6 Ex 8.2
• Decimals Class 6 Ex 8.3
• Decimals Class 6 Ex 8.5
• Decimals Class 6 Ex 8.6

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 8
Chapter Name	Decimals
Exercise	Ex 8.4
Number of Questions Solved	5
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.4

Question 1.
Express as rupees using decimals.
(a) 5 paise
(b) 75 paise
(c) 20 paise
(d) 50 rupees 90paise
(e) 725 paise.
Solution.

Question 2.
Express as meters using decimals.
(a) 15 cm
(b) 6 cm
(c) 2 m 45 cm
(d) 9 m 7cm
(e) 419 cm.
Solution.

Question 3.
Express as cm using decimals.
(a) 5 mm
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 93mm.
Solution.

Question 4.
Expresc as km using decimals.
(a) 8m
(b) 88m
(c) 8888 m
(d) 70 km 5 m.
Solution.

Question 5.
Express as kg using decimals.
(a) 2g
(b) 100g
(c) 3750g
(d) 5kg8g
(e) 26 kg 50g
Solution.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.4 help you. If you have any query regarding. NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.4, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.3.

• Decimals Class 6 Ex 8.1
• Decimals Class 6 Ex 8.2
• Decimals Class 6 Ex 8.4
• Decimals Class 6 Ex 8.5
• Decimals Class 6 Ex 8.6

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 8
Chapter Name	Decimals
Exercise	Ex 8.3
Number of Questions Solved	2
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.3

Question 1.
Which is greater?
(a) 0.3 or 0.4
(b) 0.07 or 0.02
(c) 3 or 0.8
(d) 0.5 or 0.05
(e) 1.23 or 1.2
(f) 0.099 or 0.19
(g) 1.5 or 1.50
(h) 1.431 or 1.490
(i) 3.3 or 3.300
(j) 5.64 or 5.603
Solution.
(a) 0.3 or 0.4
Whole part for both is 0.
Tenth part for 0.3 is 3 and for 0.4 is 4
∵ 4>3
∴ 0.4 > 0.3

(b) 07 or 0.02
Whole part for both is 0.
Tenth part for both is 0.
Hundredth part for 0.07 is 7 and for 0.02 is 2.
∵ 7>2
∴  0.07 > 0.02

(c) 3 or 0.8
Whole part for 3 is 3 and for 0.8 is 0.
∵ 3 >0
∴ 3 >0.8

(d) 5 or 0.05
Whole part for both is 0.
Tenth part for 0.5 is 5 and for 0.05 is 0.
∵ 5 >0
∴ 0.5 > 0.05

(e) 23 or 1.2
Whole part for both is 1.
Tenth part for both is 2.
Hundredth part for 1.23 is 3 and for 1.2 is 0 (as 1.2= 1.20)

(f) 0.099 or 0.19
Whole part for both is 0.
Tenth part for 0.099 is 0 and for 0.19 is 1.
∵ 1>0
∴ 0.19 >0.099

(g)1.5 or 1.50
Whole part for both is 1.
Tenth part for both is 5.
Hundredth part for both is 0 (as 1.5 = 1.50).
∴ 1.5=1.50

(h) 1431 or 490
Whole part for both is 1.
Tenth part for both is 4.
Hundredth part for 1.431 is 3 and for 1.490 is 9
∵ 9>3
∴ 1.490 >1.431

(i) 3 or 3.300
Whole part for both is 3.
Tenth part for both is 3.
Hundredth part for both is 0 (as 3.3 = 3.30).
Thousandth part for both is 0 (as 3.3 = 3.300).
∴ 3.3 = 3.300

(J) 5.64 or 5.603 
Whole part for both is 5.
Tenth part for both is 6.
Hundredth part for 5.64 is 4 and for 5.603 is 0.
∵ 4>0
∴ 5.64 > 5.603

Question 2.
Make five more examples and find the greater number from them.
Solution.
Five more examples are as follows:
Which is greater?
Ex. 1. 0.4 or 0.5
Ex. 2. 0.06 or 0.04
Ex. 3. 4 ox 0.9
Ex. 4. 0.6 or 0.06
Ex. 5. 0.063 or 0.22
Solution.
1.
0.4 or 0.5
Whole part for both = 0
Tenth part for 0.4 = 4
Tenth part for 0.5 = 5
∵ 5 >4
∴ 0.5 > 0.4

2.
0.06 or 0.04
Whole part for both = 0
Tenth part for both = 0
Hundredth part for 0.06 = 6
Hundredth part for 0.04 = 4
∵ 6 >4
∴ 0.06 > 0.04

3.
4 or 0.9
Whole part for 4 = 4
Whole part for 0.9 = 0
∵ 4 > 0
∴ 4 > 0.9

4.
0.6 or 0.06
Whole part for both = 0
Tenth part for 0.6 = 6
Tenth part for 0.06 = 0
∵  6 > 0
∴ 0.6 > 0.06

5.
0.063 or 0.22
Whole part for both = 0
Tenth part for 0.063 = 0
Tenth part for 0.22 = 2
∵  2 > 0
∴ 0.22 > 0.063.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.3 help you. If you have any query regarding. NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.3, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2.

• Decimals Class 6 Ex 8.1
• Decimals Class 6 Ex 8.3
• Decimals Class 6 Ex 8.4
• Decimals Class 6 Ex 8.5
• Decimals Class 6 Ex 8.6

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 8
Chapter Name	Decimals
Exercise	Ex 8.2
Number of Questions Solved	7
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2

Question 1.
Complete the table with the help of these boxes and use decimals to write the number.

	Ones	Tenths	Hundredths	Number
(a)
(b)
(c)

Solution.

	Ones	Tenths	Hundredths	Number
(a)	0	2	6	0.26
(b)	1	3	8	1.38
(c)	1	2	8	1.28

Question 2.
Write the numbers in the following place value table in decimal form:

	Hundreds (100)	Tens (10)	ones (1)	Tenths (Tenths \(\frac { 1 }{ 10 } \))	Hundredths (Tenths \(\frac { 1 }{ 100 } \))	Thousandths (Tenths \(\frac { 1 }{ 1000 } \))
(a)	0	0	3	2	5	0
(b)	1	0	2	6	3	0
(c)	0	3	0	0	2	5
(d)	2	1	1	9	0	2
(e)	0	1	2	2	4	1

Solution.

Question 3.
Write the following decimals in the place value table:
(a) 0.29
(b) 2.08
(c) 19.60
(d) 148.32
(e) 200.812
Solution.

DecimalNumber	Hundreds	Tens	Ones	Tenths	Hundredths	Thousandths
(a) 0.29	0	0	0	2	9	0
(b) 2.08	0	0	2	0	8	0
(c) 19.60	0	1	9	6	0	0
(d) 148.32	1	4	8	3	2	0
(e) 200.812	2	0	0	8	1	2

Question 4.
Write each of the following as decimals: 
(a) 20+9+\(\frac { 4 }{ 10 } \)+\(\frac { 1 }{ 100 } \)
(b) 30+\(\frac { 4 }{ 10 } \) + \(\frac { 8 }{ 100 } \)
(c)137+ \(\frac { 5 }{ 100 } \)
(d) \(\frac { 7 }{ 10 } \) + \(\frac { 6 }{ 100 } \) + \(\frac { 4 }{ 1000 } \)
(e) 23+\(\frac { 2 }{ 10 } \) + \(\frac { 6 }{ 1000 } \)
(f)700+20+5+\(\frac { 9 }{ 100 } \)
Solution.

Question 5.
Write each of the following decimals in words:
(a) 0.03
(b) 1.20
(c) 108.56
(d) 10.07
(e) 0.032
(f) 5.008.
Solution.
(a) Zero point zero three
(b) One point two zero
(c) One hundred eight point five six
(d) Ten point zero seven
(e) Zero point zero three two
(f) Five point zero eight.

Question 6.
Between which two numbers in tenths place on the number line does each of the given number lie?
(a) 06
(b) 0.45
(c) 19
(d) 0.66
(e) 92
(f) 0.57.
Solution.
Each of the given numbers lies between the two whole numbers 0 and 1 on the number line.
(a) 0 and 0.1
(b) 4 and 0.5
(c) 1 and 0.2
(d)  0.6 and 0.7
(e) 9 and 1.0
(f)  0.5 and 0.6.

Question 7.
Write as fractions in lowest terms:
(a) 0.60
(b) 0.05
(c) 75
(d) 0.18
(e) 25
(f) 0.125.
Solution.
(a) 0.60
\(0.60 =\frac { 60 }{ 100 } =\frac { 60\div 20 }{ 100\div 20 } \)
∵  H.C.F.(60,100) = 20
= \(\frac { 3 }{ 5 } \)

(b) 0.05
\(0.05=\frac { 5 }{ 100 } =\frac { 5\div 5 }{ 100\div 5 } \)
∵  H.C.F.(5,100) = 5
= \(\frac { 1 }{ 20 } \)

(c) 0.75
\(0.75=\frac { 75 }{ 100 } =\frac { 75\div 25 }{ 100\div 25 } \)
∵  H.C.F.(75,100) = 25
= \(\frac { 3 }{ 4 } \)

(d) 0.18
\(0.018 =\frac {18 }{ 100 } =\frac { 18\div 2 }{ 100\div 2 } \)
∵  H.C.F.(18,100) = 2
= \(\frac { 9 }{ 50 } \)

(e) 0.25
\(0.25 =\frac { 25 }{ 100 } =\frac { 125\div 125 }{ 100\div 25 } \)
∵  H.C.F.(25,100) = 25
= \(\frac { 1 }{ 4 } \)

(f) 0.125
\(0.125 =\frac { 125 }{ 1000 } =\frac { 125\div 125 }{ 1000\div 125 } \)
∵  H.C.F.(125,1000) =125
= \(\frac { 1 }{ 8 } \)

 

We hope the NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2 help you. If you have any query regarding. NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6.

• Fractions Class 6 Ex 7.1
• Fractions Class 6 Ex 7.2
• Fractions Class 6 Ex 7.3
• Fractions Class 6 Ex 7.4
• Fractions Class 6 Ex 7.5

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Fractions
Exercise	Ex 7.6
Number of Questions Solved	9
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6

Question 1.
Solve:

Solution :






Question 2.
Sarita bought \(\frac { 2 }{ 5 }\) metre of ribbon and Lalita bought \(\frac { 3 }{ 4 }\) metre of ribbon. What was the total 4 length of the ribbon they bought?
Solution :
Ribbon bought by Sarita = \(\frac { 2 }{ 5 }\) m
Ribbon bought by Lalita = \(\frac { 3 }{ 4 }\) m
∴ Total length of the ribbon they bought

Question 3.
Naina was given \(1\frac { 1 }{ 2 }\) piece of cake and Najma was given \(1\frac { 1 }{ 3 }\) piece of cake. Find the total amount of care given to both of them.
Solution :
Cake given to naina = \(1\frac { 1 }{ 2 }\) piece = \(\frac { \left( 1\times 2 \right) +1 }{ 2 }\) piece

Question 4.
Fill in the boxes:

Solution :

Question 5.
Complete the addition-subtraction box.


Solution :

Question 6.
A piece of wire \(\frac { 7 }{ 8 }\) meter long broke into two pieces. One piece was \(\frac { 1 }{ 4 }\) metre long. How long is the other piece?
Solution :
Length of the original piece of wire = \(\frac { 7 }{ 8 }\) metre
∴ Length of one piece = \(\frac { 1 }{ 4 }\) metre
Length of the other piece = \(\frac { 7 }{ 8 }\) metre – \(\frac { 1 }{ 4 }\) metre = \(\left( \frac { 7 }{ 8 } -\frac { 1 }{ 4 } \right)\) metre

Question 7.
Nandini’s house is ~ km from her school. She walked some distance and then took a bus for km to reach the school. How far did she walk?
Solution :
The distance of Nandini’s house from school

Question 8.
Asha and Samuel have bookshelves of the 5 same size. Asha’s shelf is \(\frac { 5 }{ 6 }\) the full of book and Samuel’s shelf is \(\frac { 2 }{ 5 }\)th full. Whose bookshelf is more full? By what fraction?
Solution :

Question 9.
Jaidev takes \(2\frac { 1 }{ 5 }\) minutes to walk across 5 the school ground. Rahul takes \(\frac { 7 }{ 4 }\) minutes to do the same. Who takes less time and by what fraction?
Solution :
Time taken by Jaidev to walk across the school ground = \(2\frac { 1 }{ 5 }\) minutes

We hope the NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5.

• Fractions Class 6 Ex 7.1
• Fractions Class 6 Ex 7.2
• Fractions Class 6 Ex 7.3
• Fractions Class 6 Ex 7.4
• Fractions Class 6 Ex 7.6

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Fractions
Exercise	Ex 7.5
Number of Questions Solved	5
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5

Question 1.
Write these fractions appropriately as additions or subtractions:

Solution :


Question 2.
Solve

Solution :

Question 3.
Shubham painted \(\frac { 2 }{ 3 }\) of the wall space in his room. Her sister Madhavi helped and painted \(\frac { 1 }{ 3 }\) of the wall space. How much did they paint together?
Solution :

Hence, they painted together with the complete wall space. ,

Question 4.
Fill in the missing fractions :


Solution :


Question 5.
Javed was given \(\frac { 5 }{ 7 }\) of a basket of oranges. What fraction of oranges was left in the basket?
Solution :

Hence, fraction \(\frac { 2 }{ 7 }\) of oranges was left in the basket.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4.

• Fractions Class 6 Ex 7.1
• Fractions Class 6 Ex 7.2
• Fractions Class 6 Ex 7.3
• Fractions Class 6 Ex 7.5
• Fractions Class 6 Ex 7.6

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Fractions
Exercise	Ex 7.4
Number of Questions Solved	10
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4

Question 1.
Write shaded portion as a fraction. Arrange them in ascending and descending order using correct sign ‘<‘, ‘=’, ‘>’ between the fraction:
(a)

(b)


appropriate signs between the fractions  given

Solution:

(i) In ascending order, these are

(ii) In descending order, these are

(b)

(i) In ascending order, these are

(ii) In descending order, these are

(c)

Question 2.
Compare the fractions and put an appropriate sign.

Solution :

Question 3.
Make five more such pairs and make appropriate signs.

Question 4.
Look at the figures and write ‘<’ or ‘>’, ‘=’ between the pairs of fractions.
Solution :


Make five more such problems and solve them with your friends.
Solution:

For the remaining part, please try yourself.

Question 5.
How quickly can you do this? Fill appropriate sign (<, =,>)

Solution :


Question 6.
The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.

Solution :


Question 7.
Find answers to the following. Write and indicate how you solved them.

Solution :
(a) Equivalent fraction of \(\frac { 5 }{ 9 }\) are

Equivalent fraction of \(\frac { 4 }{ 5 }\) are

(b) Equivalent fraction of \(\frac { 9 }{ 16 }\) are

Question 8.
Ila reads 25 pages of a book containing 100 pages. Lalita reads \(\frac { 1 }{ 2 }\) of the same book. Who read less?

Question 9.
Rafiq exercised for \(\frac { 3 }{ 6 }\) of an hour, while 6 Rohit exercised for \(\frac { 3 }{ 4 }\) of an hour. Who exercised for a longer time?
Solution :
∴ \(\frac { 3 }{ 4 }\) > \(\frac { 3 }{ 6 }\)
∴ Rohit exercised for a longer time.

Question 10.
In class A of 25 students, 20 passed in first class; in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?
Solution :

Hence, in both the classes the same fraction \(\left( \frac { 4 }{ 5 } \right)\)of total students got first class.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3.

• Fractions Class 6 Ex 7.1
• Fractions Class 6 Ex 7.2
• Fractions Class 6 Ex 7.4
• Fractions Class 6 Ex 7.5
• Fractions Class 6 Ex 7.6

Board	CBSE
Textbook	NCERT
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Fractions
Exercise	Ex 7.3
Number of Questions Solved	9
Category	NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3

Question 1.
Write the fractions. Are all these fractions equivalent?
(a)

(b)

Solution :
(a)


(b)

No ! all these fractions ae not equivalent.

Question 2.
Write the fractions and pair up the equivalent fractions from each row.

Solution:


Equivalent fractions are
(a), (ii);
(b), (,iv);
(c), (i);
(d), (v);
(e), (iii).

Question 3.
Replace in each of the following by the correct number:

Solution :



Question 4.
Find the equivalent fraction of \(\frac { 3 }{ 5 }\) having
(a) denominator 20
(b) numerator 9
(d) numerator 27
(c) denominator 30
Solution :


Question 5.
Find the equivalent fraction of \(\frac { 36 }{ 48 }\) with
(a) numerator 9
(b) denominator 4.
Solution :


Question 6.
Check whether the given fractions are equivalent :
(a) \(\frac { 5 }{ 9 }\), \(\frac { 30 }{ 54 }\)
(b) \(\frac { 3 }{ 10 }\), \(\frac { 12 }{ 50 }\)
(c) \(\frac { 7 }{ 13 }\), \(\frac { 5 }{ 11 }\)
Solution :

∴ The given fractions \(\frac { 5 }{ 9 }\) and \(\frac { 30 }{ 54 }\) are equivalent.

∴ The given fractions \(\frac { 3 }{ 10 }\) and \(\frac { 12 }{ 50 }\) are not equivalent.

∴ The given fractions \(\frac { 7 }{ 3 }\) and \(\frac { 5 }{ 11 }\) are not equivalent.

Question 7.
Reduce the following fractions to simplest form:

Solution :
(a) \(\frac { 48 }{ 60 }\)
Factors of 48 are 1, 2, 3,4, 6, 8, 12, 16, 24 and 48.
Factors of 60 are 1, 2, 3,4, 5, 6, 10,12, 15, 20, 30 and 60.
∴ Common factors of 48 and 60 are 1, 2, 3, 4, 6 and 12. Highest of these common factors is 12.
∴ H.C.F. of 48 and 60 is 12.

(b) \(\frac { 150 }{ 60 }\)
Factors of 150 are 1,2,3,5,6.10,15,25,30,50, 75 and 150.
Factors of 60 are 1, 2. 3, 4. 5, 6, 10, 12, 15, 20, 30 and 60.
∴ Common factors of 150 and 60 are 1, 2, 3, 5,6, 10, 15 and 30.
Highest of these common factors is 30.
∴ H.C.F. of 150 and 60 is 30.

(c) \(\frac { 84 }{ 98 }\)
Factors of 84 are 1, 2, 3,4, 6, 7, 12, 14, 21, 28, 42 and 84.
Factors of 98 are 1, 2, 7, 14,49 and 98.
∴ Common factors of 84 and 98 are 1,7 and 14. Highest of these common factors is 14.
∴ H.C.F. of 84 and 98 is 14.

(d) \(\frac { 12 }{ 52 }\)
Factors of 12 are 1, 2, 3,4, 6 and 12.
Factors of 52 are 1, 2, 4, 13, 26 and 52.
∴ Common factors of 12 and 52 are 1,2 and 4. Highest of these common factors is 4.
∴ H.C.F. of 12 and 52 is 4.

(e) \(\frac { 7 }{ 28 }\)
Factors of 7 are 1 and 7.
Factors of 28 are 1, 2,4, 7, 14 and 28.
∴ Common factors of 7 and 28 are 1 and 7. Highest of these common factors is 7.
∴ H.C.F. of 7 and 28 is 7.

Question 8.
Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of his/her pencils?
Solution :
For Ramesh
Number of pencils he had = 20 Number of pencils used by him =10

For Sheelu
Number of pencils she had = 50 Number of pencils used by her = 25

For Jamaal
Number of pencils he had = 80 Number of pencils used by him = 40

Yes ! each has used up an equal fraction of his/her pencils.

Question 9.
Match the equivalent fractions and write another two more for each :

Solution :
(i) \(\frac { 250 }{ 400 }\)
Factors of 250 are 1, 2, 5, 10, 25, 50, 125 and 250.
Factors of 400 are 1,2,4,5,8,10,16,20,25,40, 80, 100, 200 and 400.
∴ Common factors of 250 and 400 are 1,2,5, 10, 25 and 50.
Highest of these common factors is 50.
∴ H.C.F. of 250 and 400 is 50.

(ii) \(\frac { 180 }{ 200 }\)
Factors of 180 are 1,2, 3,4, 5, 6,9,10,12,15, 18, 20, 30, 36, 45, 60, 90 and 180.
Factors of 200 are 1,2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 200.
∴ Common factors of 180 and 200 are 1,2, 4, 5, 10 and 20.
Highest of these common factors is 20.
∴ H.C.F. of 180 and 200 is 20.

(iii) \(\frac { 600 }{ 990 }\)
Factors of 660 are 1,2,3,4,5,6,10,12,22,30, 66, 110, 132, 165, 220, 330 amd 660.
Factors of 990 are 1,2,3,5,6,9,10,11,30,33, 90, 99, 110, 165, 198, 330, 495 and 990.
∴ Common factors of 660 and 990 are 1,2,3, 5,6, 10, 30, 110 and 330.
Highest of these common factors is 330.
∴ H.C.F. of 660 and 990 is 330.

(iv) \(\frac { 180 }{ 360 }\)
Factors of 180 are 1, 2, 3,4, 5, 6, 9, 10, 12,15, 18, 20, 30, 36,45, 60, 90 and 180.
Factors of 360 are 1, 2, 3,4, 5, 6,9,10, 12, 15, 18, 20, 24, 30, 36,40, 60, 72, 90, 120, 180 and 360.
∴ Common factors of 180 and 360 are 1,2, 3,4,5,6,9,10,12,15,18.20, 30, 36,60,90 and 180.
Highest of these common factors is 180.
∴ H.C.F. of 180 and 360 is 180.

(v) \(\frac { 220 }{ 550 }\)
Factors of 220 are 1,2,4, 5,10,11, 20, 22,44, 55, 110 and 220.
Factors of 550 are 1, 2, 5, 10, 22, 25, 55, 110, 275 and 550.
∴ Common factors of 220 and 550 are 1,2,5, 10, 20 and 110.
Highest of these common factors is 110.
∴ H.C.F. of 220 and 550 is 110.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3, drop a comment below and we will get back to you at the earliest.