NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds

NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds

In this chapter, students will learn about bonding in carbon –The Covalent Bond, versatile nature of Carbon, saturated and unsaturated carbon compounds, chemical properties of carbon compound, soaps and detergents.

These Solutions are part of NCERT Solutions for Class 10 Science. Here we have given NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds. Learn Insta provides you the Free PDF download of NCERT Solutions for Class 10 Science (Chemistry) Chapter 4 – Carbon and Its Compounds solved by Expert Teachers as per NCERT (CBSE) Book guidelines. All Chapter 4 – Carbon and Its Compounds Exercise Questions with Solutions to help you to revise complete Syllabus and Score More marks.

NCERT Questions

In Text Book Questions

Question 1.
What would be the electron dot structure of carbon dioxide which has the formula CO₂ ?
Answer:
The atomic number (Z) for carbon is six and its electronic configuration is 2, 4. Carbon has four valence
electrons. Each oxygen atom (Z = 8) has six valence electrons (2, 6). In order to complete its octet, the carbon atom shares its four valence electrons with the four electrons of the two oxygen atoms as follows :

Thus, in carbon dioxide molecule, the carbon atom is linked to two oxygen atoms on both sides by two shared pairs of electrons resulting in double bonds on either sides. Both carbon and oxygen atoms complete their octet as a result of electron sharing.

More Resources

• NCERT Solutions for Class 10 Science
• NCERT Exemplar Solutions for Class 10 Science
• HOTS Questions for Class 10 Science
• Value Based Questions in Science for Class 10
• Previous Year Question Papers for CBSE Class 10 Science

Question 2.
What would be the electron dot structure of a molecule of sulphur which is made up of eight atoms of sulphur ?
Answer:
The atomic number (Z) of sulphur is sixteen and its electronic configuration is 2, 8, 6. The sulphur atom has six valence electrons. The chemical formula of sulphur molecule is S₈. Each sulphur atom is linked to similar atoms on either sides by single covalent bonds and thus, completes its octet. The molecule is in the form of a ring also represented by crown shape.
Ring structure of S₈ molecule Crown shape of S₈ molecule

Question 3.
How many structural isomers you can you draw for pentane ?
Answer:
Pentane (C₅H₁₂) has a skeleton of five carbon atoms. It can exist as a straight chain as well as two branched chains. There are three structural isomers for the hydrocarbon which is an alkane.

Question 4.
What are the two properties of carbon which lead to the huge number of carbon compounds we see around us ?
Answer:

1. Catenation: Carbon has the unique property of self linking which is known as catenation. In fact, any number of carbon atoms can be linked to one another by covalent bonds. This is on account of the stability of C—C bonds since the size of the carbon atom is quite small.
2. Linking of carbon with other atoms. Carbon is tetravalent in nature and can readily unite with atoms like hydrogen, oxygen, nitrogen, sulphur etc. by electron sharing.

Question 5.
What will be the formula and electron dot structure of cyclopentane ? (CBSE 2013)
Answer:
Cyclopentane is a cyclic compound with formula C₅H₁₂ The structure of the compound may be represented as :

Question 6.
Draw the structures of the following compounds :
(i) Ethanoic acid
(ii) Bromopentane
(iii) Butanone Are structural isomers possible for bromopentane ?
Answer:

Bromopentane has a chain of five carbon atoms. It can exist in a number of forms which are structural isomers.

The structural isomers (i), (ii) and (iii) which differ in the position of the Br atom are known as position isomers.
The structural isomers (iv), (v) and (vi) which differ in the arrangement of carbon atoms in the chain are called chain isomers.
In writing the IUPAC name, the name of prefix bromo is written before that of prefix methyl. In fact, alphabetical order is followed while naming the different prefixes.

Question 7.
How would you name the following compounds ?

Answer:
(i) Bromoethane
(ii) Hex-l-yne
(iii) Methanal

Question 8.
Why is the conversion of ethanol into ethanoic acid an oxidation reaction ?
Answer:
Ethanoic acid (CH₃COOH) has one oxygen atom more and two hydrogen atoms less than ethanol (C₂H₅OH). In general,

• Loss of hydrogen is known as oxidation.
• Gain of oxygen is known as oxidation.

Therefore, it is an oxidation reaction.

Question 9.
A mixture of ethyne and oxygen is used for welding. Can you tell why a mixture of ethyne and air is not used ?
Answer:
When ethyne is burnt in oxygen, large quantity of heat alongwith light is produced. The heat evolved can be used for gas welding which is usually carried to weld small broken pieces of articles made up of iron.

Air mainly contains a mixture of nitrogen (4 parts) and oxygen (1 part). As we know, nitrogen gas does not support combustion. This means that in air, only oxygen will help in the combustion of ethyne. Therefore, it is always better to use oxygen for the combustion of ethyne.

Question 10.
How would you distinguish experimentally between an alcohol and a carboxylic acid ?
Answer:
The distinction can be made by the following tests :

1. Dip a strip of blue litmus separately in both alcohol and carboxylic add taken in two glass tubes. The colour will change to red in the tube containing carboxylic acid and not in the tube which contains alcohol.
2. Add a small amount of solid sodium hydrogen carbonate (NaHCO₃) in both the tubes. A brisk effervescence accompanied by bubbles will be noticed in the tube containing carboxylic acid and not in the tube containing alcohol.

Question 11.
What are oxidising agents ?
Answer:
Oxidising agents are the substances which either their own or on reacting with another substance release
oxygen in order to carry oxidation reactions. The commonly used oxidising agents are : Ozone, bromine
water, a mixture of potassium dichromate and sulphuric acid or a mixture of potassium permanganate and sulphuric acid etc.

Question 12.
Would you be able to check if water is hard by using a detergent ?
Answer:
No, it is not possible. Actually detergents produce foam in any type of water ; whether hard or soft.
Therefore, a distinction between the two cannot be made. However, soaps can be used for this purpose.

Question 13.
People use a variety of methods to wash clothes. Usually after adding soap, they beat the clothes on a stone or beat them with a paddle, scrub with a brush or the mixture is agitated in a washing machine Why is this agitation necessary to get clean clothes ?
Answer:
The purpose of soap or detergent in washing is to reduce friction between oil drops carrying dirt particles and water so that they may mix with each other. All the methods that have been suggested loosen the bonds between the dust or oil particles and fabrics of clothes. The agitation helps in washing the clothes.

NCERT End Exercise

Question 1.
Ethane, with the molecular formula C₂H₆ has :
(a) G covalent bonds
(b) 7 covalent bonds
(c) 8 covalent bonds
(d) 9 covalent bonds
Answer:

(b). The molecule has seven covalent bonds.

Question 2.
Butanone is a four carbon compound with the functional group
(a) carboxylic acid
(b) aldehyde
(c) ketone
(d) alcohol.
Answer:
(c). The functional group is ketone (>C=0) also known as one.

Question 3.
While cooking, if the bottom of the vessel is getting blackened on the outside, it means that
(a) the food is not cooked completely
(b) the fuel is not burning completely
(c) the fuel is wet
(d) the fuel is burning completely.
Answer:
(b). The fuel is not burning completely. The unburnt particles present in smoke blacken the vessel from outside.

Question 4.
Explain the nature of the covalent bond using the bond formation in CH₃Cl.
Answer:
The molecule of chloromethane (CH₃Cl) consists of three elements i.e., carbon (Z = 6) hydrogen (Z = 1) and chlorine (Z = 17). Carbon atom has four valence electrons (2, 4) ; hydrogen has one (1) while chlorine has seven electrons in the valence shell (2, 8, 7). In order to complete its octet, carbon shares three valence electrons with three hydrogen atoms while one is shared with the electron of chlorine atom. The structure of covalent molecule may be written as follows :

Question 5.
Draw the electron dot structures for
(i) ethanoic acid
(ii) H₂S
(iii) propanone
(iv) F₂.
Answer:

Question 6.
What is homologous series ? Explain with an example.
Answer:
A series of similarly constituted compounds in which the members present have the same functional group, same chemical properties and any two successive members in a particular series differ in their molecular formula by —CH₂ group and molecular mass by 14 u.
For example, the boiling points of members in the family of alkanes follow the order :

Question 7.
How can ethanol and ethanoic acid be differentiated on the basis of their physical and chemical properties ?
(CBSE Delhi 2011)

Answer:
Distinction based on physical properties :

1. Smell. Ethanol has a characteristic smell known as alcoholic smell which is pleasant. Ethanoic acid has vinegar like smell.
2. Boiling points. Boiling point of ethanol (351 K) is less than that of ethanoic acid (391 K).
3. Litmus test. Ethanol is neutral in nature and does not bring any change in the colour of litmus whether blue or red. Ethanoic acid is acidic and changes the colour of a blue litmus strip to red when dipped in it.

Distinction based on chemical properties :

1. Action with sodium hydrogen carbonate. On adding a small amount of sodium hydrogen carbonate to ethanoic acid, carbon dioxide gas is evolved with brisk effervescence. However, no such reaction is noticed in case of ethanol.
   CH₃COOH + NaHCO₃ ———> CH₃COONa + CO₂ + H₂O
2. Action with caustic alkalies. Ethanoic reacts with both sodium hydroxide (NaOH) and potassium hydroxide (KOH) to form corresponding salt and water. Ethanol fails to react with either of these.
   

Question 8.
Why does micelle formation take place when soap is added to water ? Will a micelle be formed in other solvents such as ethanol also ? (CBSE Delhi 2011)
Answer:
Soap may be represented by the formula RCOO^–Na⁺ where R is an alkyl group which represents long chain of carbon with fifteen or more atoms. Now, oil drops containing dirt particles and water donot mix. Soap helps in their mixing by reducing interfacial tension or friction. Actually it forms a sort of bridge between oil drops and water in which the alkyl portion (hydrophobic end) points towards oil drop while other portion COONa (hydrophilic end) is directed towards water. This is known as micelle formation. Thus, soap helps in the formation of a stable emulsion between oil and water. Ethanol and other similar solvents which are of organic nature, donot help in micelle formation because soap is soluble in them.

Question 9.
Why are carbon and its compounds used as fuels in most cases ?
Answer:
Carbon burns in oxygen or air to form carbon dioxide gas. The reaction is highly exothermic. That is why different forms of coal are used as fuels. The most important compounds of carbon are hydrocarbons. Just like carbon, hydrogen also readily burns in oxygen or air to form water producing heat. The hydrocarbon methane (CH₄) is a constituent of natural gas. Propane (C₃H₈) and butane (C₄H₁₀) are present in liquid petroleum gas (L.P.G.). Petrol and kerosene also contain different hydrocarbons. Therefore, these are used as fuels.

Question 10.
Explain the formation of scum when hard water is treated with soap. (CBSE Delhi 2011)
Answer:
Soap is basically sodium or potassium salt of higher fatty acids. Hard water contains in it Ca²⁺ and Mg²⁺ ions as their salts. When soap is added to hard water, the corresponding calcium and magnesium salts are formed. These are in the form of precipitates, also called ‘scum’.

Question 11.
What change will you observe by testing soap with litmus paper (blue or red) ?
Answer:
When soap is dissolved in water, the solution is alkaline in nature due to the formation of alkali NaOH or KOH. The solution changes the colour of red litmus to blue. However, the solution does not change the colour of blue litmus.

Question 12.
What is hydrogenation ? What is its industrial application ?
Answer:
The addition of hydrogen to unsaturated hydrocarbon in the presence of a metal catalyst is also known as catalytic hydrogenation.
The reaction is extremely useful in the hydrogenation of vegetable oils also called edible oils e.g. ground nut oil, cotton seed oil etc. These are also called cooking oils and are unsaturated in the sense that their molecules contain atleast one C=C bond in their structures. Upon passing hydrogen gas through oil in the presence of nickel catalyst, the double bond changes to single bond. As a result, the unsaturated oil changes to solid fat which is of saturated nature. Vegetable ghees such as Dalda, are of saturated nature and are formed by catalytic hydrogenation reaction.

Question 13.
Which of the listed hydrocarbons undergo addition reactions : C₂H₆, C₃H₈, C₃H₆, C₂H₂ and CH₄ ?
Answer:
In order that a hydrocarbon may undergo addition reaction, it must be unsaturated in nature. It must be either an alkene (C=C) with general formula C_nH_2n or an alkyne (C = C) with general formula C_nH_2n-2. Out of the list of the hydrocarbons given :

• C₃H₆ (Propene) is an alkene with C=C bond. It corresponds to general formula C_nH_2n (n = 3)
• C₂H₂ (Ethyne) is an alkyne with C = C bond. It corresponds to general formula C_nH_2n-2 (n = 2).

Both these hydrocarbons take part in addition reactions. For example, they react with hydrogen upon heating to 473 K in the presence of Nickel catalyst to form corresponding alkanes.

Question 14.
Give a test that can be used to differentiate between butter and cooking oil.
Answer:
Butter is saturated in nature while cooking oil is unsaturated. This means that cooking oil has atleast one C=C bond present in the constituting compounds while butter does not have any such bond. The distinction between them can be made by reacting with bromine water or bromine dissolved in carbon tetrachloride. Cooking oil will discharge the yellow colour of bromine while butter will not.

Question 15.
Explain the mechanism of cleansing action of soap.
Answer:
Cleansing action of Soaps and Detergents
Both soaps and detergents resemble in their cleansing action. They have two main parts. These are non—polar hydrocarbon chain which is water repellent or hydrophobic (phobic or phobia stands for repulsion or hatred) and the polar carboxyl group as its salt which is attracted towards water or is hydrophilic (philic stands for love or attraction). The former is called the tail of the molecule and the latter is regarded as the head.

In order to understand the cleansing action of both soaps and detergents, let us try to analyse how the clothes become dirty. They first become oily because of the perspiration coming out of the skin and also from the organic matter dispersed in the atmosphere. Dust particles stick to oil drops and the clothes become dirty. In order to wash these, they are dipped in water and soap or detergent is applied. In solution, it dissociates to give carboxylate ions (RCOO ) or sulphonate ions (RSO₃^–) and the cations (Na⁺). In the carboxylate ion, the alkyl portion which contains a long chain of hydrocarbons is a tail pointing towards the oil drops while the COO^– portion is the head directed towards water. In a detergent it is the SO₃^– portion which points towards water. This is quite evident from the figure where the solid circles (•) represent the polar groups and the wavy lines (^^^) represent the alkyl portions. The molecules of soap or detergent have a unique orientation in water. They actually form a cluster of molecules in which the hydrophobic or alkyl portion is in the interior while the ionic or polar portion is on the surface of the cluster as shown in the figure. This formation is known as micellear formation or simply micelle. Soaps or detergent thus help in forming a stable emulsion of oil and water by acting as a bridge between the two. The oil droplets alongwith the particles of the dirt get detached from the fibres of the clothes and pass into the emulsion. In this manner, the clothes become free from dust or dirt.

NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds

Hope given NCERT Solutions for Class 10 Science Chapter 4 helpful to you.