RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 6 Operations on Algebraic Expressions Ex 6A.

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Question 1.
Solution:
8ab + ( – 5ab) + (3ab) + ( – ab)
= 8ab – 5ab + 3ab – ab = 11 ab – 6ab
= 5ab Ans.

Question 2.
Solution:
7x + ( – 3x) + 5x + ( – x) + ( – 2x)
= 7x – 3x + 5x – x – 2x
= 12x – 6x = 6x Ans.

Question 3.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 3.1

Question 4.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 4.1

Question 5.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 5.1

Question 6.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 6.1

Question 7.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 7.1

Question 8.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 8.1

Subtarct:

Question 9.
Solution:
-5a²b – 3a²b = – 8a²b Ans.

Question 10.
Solution:
6pq – ( – 8pq) = 6pq + 8pq

Question 11.
Solution:
– 8abc – ( – 2abc)
= – 8abc + 2abc
= – 6abc Ans.

Question 12.
Solution:
– 11p – ( – 16p)
= – 11p + 16p
= 5p Ans.

Question 13.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 13.1

Question 14.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 14.1

Question 15.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 15.1

Question 16.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 16.1

Question 17.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 17.1

Question 18.
Solution:
RS Aggarwal Class 8 Solutions Chapter 6 Operations on Algebraic Expressions Ex 6A 18.1

Question 19.
Solution:
Let length of rectangle = 5x2 – 3y2
and breadth = x2 + 2xy
Perimeter = 2(Length + Breadth)
= 2(5x2 – 3y2 + x2 + 2xy)
= 2(6x2 – 3y2 + 2xy)
= 12x2 – 6y2 + 4xy Ans.

Question 20.
Solution:
Perimeter of a triangle = 6p2 – 4p + 9
Sum of two sides of it = 3p2 – 5p + 3 + p2 – 2p + 1 = 4p2 – 7p – 4
Third side = (6p2 – 4p + 9) – (4p2 – 7p + 4)
= 6p2 – 4p + 9 – 4p2 + 7p – 4
= 2p2 + 3p + 5 Ans

 

Hope given RS Aggarwal Solutions Class 8 Chapter 6 Operations on Algebraic Expressions Ex 6A are helpful to complete your math homework.

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