RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment Ex 18a

RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment Ex 18a

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment Ex 18a.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment Ex 18a
• RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment Ex 18b
• RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment MCQ
• RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment Test Yourself

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Question 5.
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Since square circumscribes a circle of radius a cm, we have
Side of the square = 2 ⨯ radius of circle = 2a cm
Then, Perimeter of the square = (4 ⨯ 2a) = 8a cm

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Length of the pendulum = radius of sector = r cm

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Angle described by the minute hand in 60 minutes = 360°
Angle described by minute hand in 20 minutes

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Question 23.
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Let sector of circle is OAB
Perimeter of a sector of circle = 31 cm
OA + OB + length of arc AB = 31 cm

Question 24.
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Length of arc of circle = 44 cm
Radius of circle = 17.5 cm

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Question 48.
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Area of flower bed = (area of quadrant OPQ) – (area of the quadrant ORS)

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Hope given RS Aggarwal Solutions Class 10 Chapter 18 Areas of Circle, Sector and Segment Ex 18a are helpful to complete your math homework.

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