## RS Aggarwal Solutions Class 10 Chapter 7 Trigonometric Ratios of Complementary Angles Ex 7

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 7 Trigonometric Ratios of Complementary Angles Ex 7.

**Other Exercises**

**Question 1.**

**Solution:
**(i)

(ii)

(iii)

(iv)

(v)

(vi)

**Question 2.**

**Solution:
**(i) LHS = cos81° – sin9°

= cos(90° -9°)- sin9° = sin9° – sin9°

= 0 = RHS

(ii) LHS = tan71° – cot19°

=tan(90° – 19°) – cot19° =cot19° – cot19°

=0 = RHS

(iii) LHS = cosec80° – sec10°

= cosec(90° – 10°) – sec(10°)

= sec10° – sec10° = 0

= RHS

(iv) LHS = cosec^{2 }72° − tan^{2 }18°

(v) LHS = cos^{2 }75° + cos^{2 }15°

(vi) LHS = tan^{2 }66° − cot^{2 }24°

(vii) LHS = sin^{2 }48° + sin^{2 }42°

(viii) LHS = cos^{2 }57° − sin^{2 }33°

(ix) LHS = (sin 65° + cos 25°)(sin 65° − cos 25°)

**Question 3.**

**Solution:
**(i)

(ii)

(iii)

(iv)

(v)

(vi)

**Question 4.**

**Solution:
**(i)

(ii)

(iii)

(iv)

(v)

**Question 5.**

**Solution:**

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

**Question 6.**

**Solution:
**(i)

(ii)

(iii)

(iv)

(v)

**Question 7.**

**Solution:
**(i) LHS = sin (70° + θ) − cos (20° − θ)

(ii) LHS = tan (55° − θ) − cot (35° + θ)

(iii) LHS = cosec (67° + θ) − sec (23° − θ)

(iv) LHS = cosec (65 °+ θ) sec (25° − θ) − tan (55° − θ) + cot (35° + θ)

(v) LHS = sin (50° + θ ) − cos (40° − θ) + tan 1° tan 10° tan 80° tan 89°

**Question 8.**

**Solution:
**(i)

(ii)

(iii)

(iv)

**Question 9.**

**Solution:
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**Question 10.**

**Solution:
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**Question 11.**

**Solution:
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**Question 12.**

**Solution:
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**Question 13.**

**Solution:
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**Question 14.**

**Solution:
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**Question 15.**

**Solution:
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