## NCERT Solutions for Class 9 Maths Chapter 8 Linear Equations in Two Variables Ex 8.1

NCERT Solutions for Class 9 Maths Chapter 8 Linear Equations in Two Variables Ex 8.1 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths Chapter 8 Linear Equations in Two Variables Ex 8.1.

 Board CBSE Textbook NCERT Class Class 9 Subject Maths Chapter Chapter 8 Chapter Name Linear Equations in Two Variables Exercise Ex 8.1 Number of Questions Solved 2 Category NCERT Solutions

## NCERT Solutions for Class 9 Maths Chapter 8 Linear Equations in Two Variables Ex 8.1

Question 1.
The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.
(Take the cost of a notebook to be ₹ x and that of a pen to be ₹ y)
Solution:
Let the cost of a notebook = ₹ x
and the cost of a pen = ₹ y
According to question,
Cost of a notebook = 2(cost of a pen)
∴ x = 2y
⇒ x- 2y = 0

Question 2.
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case.
(i) 2x + 3y = 9.$$\overline { 35 }$$
(ii) x – $$\frac { y }{ 5 }$$ – 10 = 0
(iii) – 2x + 3y = 6
(iv) x = 3y
(v) 2x = – 5y
(vi) 3x + 2 = 0
(vii) y – 2 = 0
(viii) 5 = 2x
Solution:
(i) 2x + 3y = 9.$$\overline { 35 }$$
⇒ 2x + 3y – 9..$$\overline { 35 }$$ = 0
On comparing with ax+by+c = 0.
Then, the values of a = 2, b = 3 and c = 9..$$\overline { 35 }$$

(ii) x- $$\frac { y }{ 5 }$$ -10= 0
On comparing with ax + by + c = 0, then the values of
a = 1, b = $$\frac { -1 }{ 5 }$$ andc = – 10

(iii) – 2x+ 3y = 6
⇒ -2x + 3y – 6=0
On comparing with ax + by + c = 0, then the values of a = – 2, b = 3 and c = – 6

(iv) x = 3y ⇒ x-3y+0=0
On comparing with ax + by + c = 0, then the values of a = 1, b = – 3 and c = 0.

(v) 2x = -5y
⇒ 2x + 5y + 0=0
On comparing with ax + by + c = 0, then the values of a = 2, b = 5 and c = 0.

(vi) 3x + 2 = 0
⇒ 3x + 0y + 2 = 0
On comparing with ax + by + c = 0, then the values of a = 3, b = 0 and , c= 2.

(vii) y – 2 = 0
⇒0x+y-2 = 0
On comparing with ax + by + c = 0, then the values of a = 0, b = 1 and c = – 2.

(viii) 5 = 2x ⇒ 2x + 0y – 5 = 0
On comparing with ax + by + c = 0, then the values of a = 2, b = 0 and c = – 5.

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