NCERT Solutions for Class 7 Science Chapter 5 Acids, Bases and Salts

NCERT Solutions for Class 7 Science Chapter 5 Acids, Bases and Salts are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 5 Acids, Bases and Salts.

Board CBSE
Textbook NCERT
Class Class 7
Subject Science
Chapter Chapter 5
Chapter Name Acids, Bases and Salts
Number of Questions Solved 11
Category NCERT Solutions

NCERT Solutions for Class 7 Science Chapter 5 Acids, Bases and Salts

Question 1.
State differences between acids and bases.
Answer:

Acids Bases
1. Acids are sour to taste 1. Bases are bitter to taste.
2. Acids turn blue litmus red. 2. Bases turn red litmus blue.
3. Acid is defined as a substance which contains hydrogen ion. 3. A base is defined as a substance which contains hydroxyl ion.

 Question 2.
Ammonia is found in many household products, such as window cleaners. It turns red litmus blue. What is its nature?
Answer:
Ammonia has basic nature.

Question 3.
Name the source from which litmus solution is obtained. What is the use of this solution?
Answer:
The extraction of litmus solution takes place from Lichens (a symbiotic association of algae and fungi). It is used to determine whether the given solution is acidic or basic.

Question 4.
Is the distilled water acidic, basic, or neutral? How would you verify it?
Answer:
Distilled water is neutral. We can verify it by showing that neither blue nor red litmus paper changes its colour when dipped in it.

Question 5.
Describe the process of neutralization with the help of an example.
Answer:
The process in which an acid reacts with a base to form salt and water is known as a neutralization reaction. For example,
NCERT Solutions for Class 7 Science Chapter 5 Acids, Bases and Salts Ans.5

Question 6.
Mark ‘T’ if the statement is true and ‘F’ if it is false :
(i) Nitric acid turns red litmus blue. (T/F)
(ii) Sodium hydroxide turns blue litmus red. (T/F)
(iii) Sodium hydroxide and hydrochloric acid neutralize each other and form salt and water. (T/F)
(iv) Indicator is a substance which shows different colours in acidic and basic solutions. (T/F)
(v) Tooth decay is caused by the presence of a base. (T/F)
Answer:
(i) F
(ii) F
(iii) T
(iv) T
(v) F

Question 7.
Dorji has a few bottles of soft drink in his restaurant. But, unfortunately, these are not labelled. He has to serve the drinks on the demand of customers. One customer wants acidic drink, another wants basic and third one wants a neutral drink. How will Dorji decide which drink is to be served to whom?
Answer:
He can decide by the use of an indicator. If the sample of drink turns red litmus blue, it is basic. If it turns blue litmus red, it is acidic. If it does not affect litmus, it is neutral.

Question 8.
Explain why :
(a) An antacid tablet is taken when you suffer from acidity.
(b) Calamine solution is applied on the skin when an ant bites.
(c) Factory waste is neutralised before disposing it into the water bodies.
Answer:
(a) To relieve indigestion, we take an antacid such as milk of magnesia. It neutralizes the effect of excessive acid.
(b) When an ant bites, it injects the acidic liquid into the skin. This acidic liquid is formic acid, which leads to inflammation to the skin. The effect of the sting can be neutralised by rubbing calamine solution which contains zinc carbonate. The zinc carbonate is a weak base and causes no harm to the skin.
(c) The wastes of many factories usually contain acids. If they are allowed to flow into the water bodies without neutralising it properly, then the acids will kill fish and other aquatic organisms. So factory wastes must be neutralised by adding some basic substances into the wastes before disposing these into water bodies.

Question 9.
Three liquids are given to you. One is hydrochloric acid, another is sodium hydroxide and third is a sugar solution. How will you identify them? You have only a turmeric indicators.
Answer:

S.No. Name of substance Effect on turmeric indicator
1. Hydrochloric acid The yellow colour of turmeric turns blue
2. Sodium hydroxide The yellow colour of turmeric turns red
3. Sugar solution No change in turmeric colour

Question 10.
Blue litmus paper is dipped in a solution. It remains blue. What is the nature of the solution? Explain.
Answer:
The solution may be neutral or basic. Both types of substances have no effect on blue litmus. Put a drop of this solution on a red litmus paper. If it turns blue, then the above solution is basic in nature and if no colour change occurs, then it is neutral.

Question 11.
Consider the following statements:
(a) Both acids and bases change colour of all indicators.
(b) If an indicator gives a colour change with an acid, it does not give a change with a base.
(c) If an indicator changes colour with a base, it does not change colour with an acid.
(d) Change of colour in acid, and a base depends on the type of the indicator.
Which of these statements are correct?
(i) All four
(ii) (a) and (d)
(iii) (b) and (c)
(iv) Only (d)
Answer:
(ii) (a) and (d)

We hope the NCERT Solutions for Class 7 Science Chapter 5 Acids, Bases and Salts help you. If you have any query regarding NCERT Solutions for Class 7 Science Chapter 5 Acids, Bases and Salts, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Science Chapter 4 Heat

NCERT Solutions for Class 7 Science Chapter 4 Heat are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 4 Heat.

Board CBSE
Textbook NCERT
Class Class 7
Subject Science
Chapter Chapter 4
Chapter Name Heat
Number of Questions Solved 11
Category NCERT Solutions

NCERT Solutions for Class 7 Science Chapter 4 Heat

Question 1.
State similarities and differences between the laboratory thermometer and the clinical thermometer.
Answer:
Similarities:

  1. Both contain mercury in bulbs.
  2. Both use the Celsius scale on a glass tube.

Differences:

  1. The temperature on the laboratory thermometer falls by itself, but not so in the clinical thermometer.
  2. The range of a laboratory thermometer is much higher than a clinical thermometer.

Question 2.
Give two examples each of conductors and insulators of heat.
Answer:

  • Conductors of heat: Copper, iron.
  • Insulators: Plastic, wood (dry).

Question 3.
Fill in the blanks:

  1. The hotness of an object is determined by its …….
  2. The temperature of boiling water cannot be measured by a ………. thermometer.
  3. Temperature is measured in degree …………
  4. No medium is required for transfer of heat by the process of ………..
  5. A cold steel spoon is dipped in a cup of hot milk. It transfers heat to its other end by the process of ………
  6. Clothes of ……….. colours absorb heat better than clothes of light colours.

Answer:

  1. temperature
  2. clinical
  3. Celsius
  4. radiation
  5. conduction
  6. dark

Question 4.
Match the following:

(i) Land breeze blows during (a) summer
(ii) Sea breeze blows during (b) winter
(iii) Dark-coloured clothes are preferred during (c) day
(iv) Light-coloured clothes are preferred during (d) night

Answer:

(i) Land breeze blows during (d) night
(ii) Sea breeze blows during (c) day
(iii) Dark-coloured clothes are preferred during (b) winter
(iv) Light-coloured clothes are preferred during (a) summer

Question 5.
Discuss why wearing more layers of clothing during winter keeps us warmer than wearing just one thick piece of clothing.
Answer:
If there are more than one layer of clothes, air would be trapped in between them. Air is a poor conductor of heat. This increases the insulation and thus comfortability of the clothes as a whole.

Question 6.
Look at Fig., mark where the heat is being transferred by conduction, by convection, and by radiation.
Chapter 4 Heat Q.6
Fig. Heat transferred by conduction, by convection and by radiation
Answer:
In this figure, the heat is transferred at three points in different ways:

  • by radiation: from the flame to the bottom of the pan.
  • by conduction: from lower surface to upper surface of the pan.
  • by convection: from the base to the upper region of pan water.

Question 7.
In places of the hot climate, it is advised that the outer walls of houses be painted white. Explain.
Answer:
Objects with white surfaces reflect more heat and absorb less. So, less heat from outside would enter the house.

Question 8.
One liter of water at 30°C is mixed with one liter of water at 50°C. The temperature of the mixture will be
(a) 80°C
(b) more than 50°C but less than 80°C
(c) 20°C
(d) between 30°C and 50°C
Answer:
(d) between 30°C and 50°C.

Question 9.
An iron ball at 40°C is dropped in a mug containing water at 40°C. The heat will
(a) flow from the iron ball to water.
(b) not flow from iron ball to water or from water to iron ball.
(c) flow from water to iron ball.
(d) increase the temperature of both.
Answer:
(b) not flow from iron ball to water or from water to iron ball.

Question 10.
A wooden spoon is dipped in a cup of ice cream. Its other end
(a) becomes cold by the process of conduction.
(b) becomes cold by the process of convection.
(c) becomes cold by the process of radiation.
(d) does not become cold,
Answer:
(d) does not become cold.

Question 11.
Stainless steel pans are usually provided with copper bottoms. The reason for this could be that
(a) copper bottom makes the pan more durable.
(b) such pans appear colourful.
(c) copper is a better conductor of heat than stainless steel.
(d) copper is easier to clean than stainless steel.
Answer:
(c) copper is a better conductor of heat than stainless steel.

We hope the NCERT Solutions for Class 7 Science Chapter 4 Heat help you. If you have any query regarding NCERT Solutions for Class 7 Science Chapter 4 Heat, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1.

Board CBSE
Textbook NCERT
Class Class 7
Subject Maths
Chapter Chapter 2
Chapter Name Fractions and Decimals
Exercise Ex 2.1
Number of Questions Solved 8
Category NCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 1.
Solve :
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 1
Solution:
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 2
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 3

Question 2.
Arrange the following in descending order
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 4
Solution:
(i) Converting the given fractions into like fractions, we have
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 5
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 6
(ii) Converting the given fractions into like fractions, we have
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 7

Question 3.
In a “magic square”, the sum of the numbers in each row, in each column and along the diagonals is the same. Is this a magic square?
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 8
Solution:
Yes ! this is a magic square.

Question 4.
A rectangular sheet of paper is 12 \(\frac { 1 }{ 2 } \) cm long 10 \(\frac { 2 }{ 3 } \) cm wide. find its perimeter
Solution:
Perimeter of the rectangular sheet of paper
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 9

Question 5.
Find the perimeters of (i) A ABE (ii) the rectangle BCDE in this figure. Whose perimeter is greater?
Solution:
(i) Perimeter of ∆ ABE = AB + BE + EA
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 10
(ii) Perimeter of the rectangle BCDE = BC + CD + DE + EB
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 11
So, the perimeter of A ABE is greater than the perimeter of the rectangle BCDE.

Question 6.
Salil wants to put a picture in a frame. The picture is 7 \(\frac { 3 }{ 5 } \) cm wide. To fit in the frame the picture cannot be more than 7 \(\frac { 3 }{ 10 } \) cm wide. How much should the picture be trimmed?
Solution:
The picture should be trimmed by
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 12

Question 7.
Ritu are \(\frac { 3 }{ 5 } \) part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat? Who had the larger share? By how much?
Solution:
Part of the apple ate by Somu
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 13

Question 8.
Michael finished colouring a picture in \(\frac { 7 }{ 12 } \) hour. Vaibhav finished colouring the same picture in \(\frac { 3 }{ 4 } \) hour. Who worked longer? By what fraction was it longer?
Solution:
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 14

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NCERT Solutions for Class 7 Science Chapter 3 Fibre to Fabric

NCERT Solutions for Class 7 Science Chapter 3 Fibre to Fabric are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 3 Fibre to Fabric.

Board CBSE
Textbook NCERT
Class Class 7
Subject Science
Chapter Chapter 3
Chapter Name Fibre to Fabric
Number of Questions Solved 9
Category NCERT Solutions

NCERT Solutions for Class 7 Science Chapter 3 Fibre to Fabric

Question 1.
You must be familiar with the following nursery rhymes:
(i) ‘Baa baa black sheep, have you any wool.
(ii) ‘Mary had a little lamb, whose fleece was white as snow.
Answer the following:
(a) Which parts of the black sheep have wool?
(b) What is meant by the white fleece of the lamb?
Answer:
(a) The hairy skin – called fleece, has wool in black sheep.
(b) White fleece means hairy skin which is white in colour.

Question 2.
The silkworm is (a) a caterpillar, (b) a larva. Choose the correct option.
(i) (a)
(ii) (b)
(iii) both (a) and (b)
(iv) neither (a) nor (b)
Answer:
(iii) both (a) and (b)

Question 3.
Which of the following does not yield wool?
(i) Yak
(ii) Camel
(iii) Goat
(iv) Woolly dog
Answer:
(iv) Woolly dog

Question 4.
What is meant by the following terms?

  1. Rearing
  2. Shearing
  3. Sericulture

Answer:

  1. Rearing: Bringing up and looking after the sheep is called rearing.
  2. Shearing: To obtain wool, the fleece of the sheep along with a thin layer of skin is removed from its body. This process is called shearing.
  3. Sericulture: The rearing of silkworms for obtaining silk is called sericulture.

Question 5.
Given below is a sequence of steps in the processing of wool. Which are the missing steps? Add them.
Shearing, ……., sorting ………, ………., ……….
Answer:
Shearing, scouring, sorting, picking out burrs, colouring, rolling.

Question 6.
Make sketches of the two stages in the life history of the silk moth which are directly related to the production of silk.
Answer:
Chapter 3 Fibre to Fabric Q.6

Question 7.
Out of the following, which are the two terms related to silk production?
Sericulture, floriculture, moriculture, apiculture and silviculture.
Hints:
(i) Silk production involves the cultivation of mulberry leaves and rearing silkworms.
(ii) Scientific name of mulberry is Morus alba.
Answer:
Sericulture, Moriculture.

Question 8.
Match the words of Column I with those given in Column II:

Column I Column II
1. Scouring (a) Yields silk fibres
2. Mulberry leaves (b) Wool yielding animal
3. Yak (c) Food of silkworm
4. Cocoon (d) Reeling
(e) Cleaning sheared skin

Answer:

Column I Column II
1. Scouring (e) Cleaning sheared skin
2. Mulberry leaves (c) Food of silkworm
3. Yak (b) Wool yielding animal
4. Cocoon (a) Yields silk fibres

Question 9.
Given below is a crossword puzzle based on this lesson. Use hints to fill in the blank spaces with letters that complete the words.
Chapter 3 Fibre to Fabric Q.9.1
Down
(D) 1 : Thorough washing
2 : Animal fibre
3 : Long thread like structure
Across
(A) 1 : Keeps warm
2 : Its leaves are eaten by silkworms
3 : Hatches from egg of moth
Answer:
Chapter 3 Fibre to Fabric Q.9.2

We hope the NCERT Solutions for Class 7 Science Chapter 3 Fibre to Fabric help you. If you have any query regarding NCERT Solutions for Class 7 Science Chapter 3 Fibre to Fabric, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Science Chapter 2 Nutrition in Animals

NCERT Solutions for Class 7 Science Chapter 2 Nutrition in Animals are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 2 Nutrition in Animals.

Board CBSE
Textbook NCERT
Class Class 7
Subject Science
Chapter Chapter 2
Chapter Name Nutrition in Animals
Number of Questions Solved 13
Category NCERT Solutions

NCERT Solutions for Class 7 Science Chapter 2 Nutrition in Animals

Question 1.
Fill in the blanks:

  1. The main steps of nutrition in humans are ……., ………., ………., ………, and ………….
  2. The largest gland in the human body is ………..
  3. The stomach releases hydrochloric acid and ……… juices which act on the food.
  4. The inner wall of the small intestine has many finger-like outgrowths called ……….
  5. Amoeba digests its food in the ………..

Answer:

  1. ingestion, digestion, absorption, assimilation, and egestion.
  2. liver
  3. digestive
  4. villi
  5. food vacuole.

Question 2.
Mark ‘T’ if the statement is true and ‘F’ if it is false:

  1. Digestion of starch starts in the stomach. (T/F)
  2. The tongue helps in mixing food with saliva. (T/F)
  3. The gall bladder temporarily stores bile. (T/F)
  4. The ruminants bring back swallowed grass into their mouth and chew it for some time. (T/F)

Answer:

  1. F
  2. T
  3. T
  4. T

Question 3.
Tick (√) mark the correct answer in each of the following:
(a) Fat is completely digested in the
(i) stomach
(ii) mouth
(iii) small intestine
(iv) large intestine

(b) Water from the undigested food is absorbed mainly in the
(i) stomach
(ii) food pipe
(iii) small intestine
(iv) large intestine
Answer:
(a) (iii) Small intestine
(b) (iv) Large intestine.

Question 4.
Match the items of Column I with those given in Column II:

Column I Column II
Food components Product(s) of digestion
Carbohydrates Fatty acids and glycerol
Proteins Sugar
Fats Amino acids

Answer:

Column I

Column II

Food components Product(s) of digestion
Carbohydrates Sugar
Proteins Amino acids
Fats Fatty acids and glycerol

Question 5.
What are villi? What are their location and function?
Answer:
The inner walls of the small intestine have thousands of finger-like outgrowths. These are called villi. Villi are located in the small intestine. The villi increase the surface area for absorption of the digested food. Each villus has a network of thin and small blood vessels close to its surface. The surface of the villi absorbs the digested food materials.

Question 6.
Where is the bile produced? Which component of the food does it help to digest?
Answer:
Bile is produced in the liver. The bile juice is stored in a sac called the gall bladder. Bile plays an important role in the digestion of fats.

Question 7.
Name the type of carbohydrate that can be digested by ruminants but not by humans. Give the reason also.
Answer:
Cellulose is a type of carbohydrate that can be digested by ruminants but not by humans. Ruminants have a large sac-like structure called rumen which is present in between the small intestine and large intestine. The cellulose is digested here by the action of certain bacteria which are not present in humans.

Question 8.
Why do we get instant energy from glucose?
Answer:
Because glucose can easily breakdown in the cell with the help of oxygen and gives carbon dioxide, water, and energy.

Question 9.
Which part of the digestive canal is involved in:

  1. absorption of food ……..
  2. chewing of food …….
  3. the killing of bacteria …….
  4. complete digestion of food ………
  5. formation of faeces ……..

Answer:

  1. Small intestine
  2. Mouth
  3. Stomach
  4. Small intestine
  5. Large intestine.

Question 10.
Write one similarity and one difference between the nutrition in amoeba and human beings.
Answer:

  1. Similarity: Both amoeba and humans use digestive juices to digest food.
  2. Difference: Human needs to chew food, whereas, an amoeba, there is no chewing.

Question 11.
Match the items of Column I with suitable items in Column II

Column I Column II
(a) Salivary gland (i) Bile juice secretion
(b) Stomach (ii) Storage of undigested food
(c) Liver (iii) Saliva secretion
(d) Rectum (iv) Acid release
(e) Small intestine (v) Digestion is completed
(f) Large intestine (vi) Absorption of water
(Vii) Release of faeces

Answer:

Column I Column II
(a) Salivary gland (iii) Saliva secretion
(b) Stomach (iv) Acid release
(c) Liver (i) Bile juice secretion
(d) Rectum (ii) Storage of undigested food
(e) Small intestine (v) Digestion is completed
(f) Large intestine (vi) Absorption of water

 Question 12.
Label figure of the digestive system.
Answer:
NCERT Solutions for Class 7 Science Chapter 2 Nutrition in Animals Q.12
Fig. Human digestive system

Question 13.
Can we survive only on raw, leafy vegetables/grass? Discuss.
Answer:
No. Because to live a healthy life, we need a complete balance of all nutrients. Raw leafy vegetables/grass may have cellulose which can not be digested by us. So, we cannot survive only on raw, leafy vegetables/grass.

We hope the NCERT Solutions for Class 7 Science Chapter 2 Nutrition in Animals help you. If you have any query regarding NCERT Solutions for Class 7 Science Chapter 2 Nutrition in Animals, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1.

Board CBSE
Textbook NCERT
Class Class 7
Subject Maths
Chapter Chapter 3
Chapter Name Data Handling
Exercise Ex 3.1
Number of Questions Solved 9
Category NCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1

Question 1.
Find the range of heights of any ten students of your class.
Solution:
Let the heights (in cm) of 10 students in the class be 150, 152, 151, 148, 149, 149, 150, 152, 153, 146.
Arranging the heights in ascending order, we have 146, 148, 149, 149, 150, 150, 151, 152, 152, 153.
Range of height of students = 153 – 146 = 7

Question 2.
Organize the following marks in a class assessment, in a tabular form.
4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7
(i) Which number is the highest?
(ii) Which number is the lowest?
(iii) What is the range of the data?
(iv) Find the arithmetic mean.
Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1
(i) Highest number is 9.
(ii) Lowest number is 1.
(iii) Range of the data = Highest observation – Lowest observation
= 9 – 1
= 8
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.2

Question 3.
Find the mean of the first five whole numbers.
Solution:
The first 5 whole numbers are 0, 1, 2, 3, and 4.
Their arithmetic mean
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3

Question 4.
A cricketer scores the following runs in eight innings:
58, 76, 40, 35, 46, 45, 0, 100.
Find the mean score.
Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4

Question 5.
Following table shows the points of each player scored in four games:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.5
Now answer the following questions:

  1. Find the mean to determine A’s average number of points scored per game.
  2. To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why?
  3. B played in all four games. How would you find the mean?
  4. Who is the best performer?

Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.6
So, A’s average number of points scored per game is 12.5.
(ii) To find the mean number of points per game for C, we shall divide the total points by 3 because the number of games under consideration is 4 but ‘C’ did not play game 3.
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.7
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.8

Question 6.
The marks (out of 100) obtained by a group of students in a science test are 85, 76, 90, 85, 39, 48, 56, 95, 81 and 75. Find the:

  1. Highest and the lowest marks obtained by the students.
  2. Range of the marks obtained.
  3. Mean marks obtained by the group.

Solution:

  1. Highest marks obtained by the students = 95
    Lowest marks obtained by the students = 39
  2. Range of the marks obtained = Highest marks – Lowest marks = 95 – 39 = 56
  3. Mean marks obtained by the group
    NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.9

Question 7.
The enrolment of a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820.
Find the mean enrolment of the school for this period.
Solution:
Mean enrolment of the school for this period.
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.10

Question 8.
The rainfall (in mm) in a city on 7 days of a certain week was recorded as follows:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.11
(i) Find the range of the rainfall in the above data.
(ii) Find the mean rainfall for the week.
(iii) On how many days was the rainfall less than the mean rainfall?
Solution:
(i) Range of the rainfall = Highest rainfall – Lowest rainfall = 20.5 mm – 0.0 mm = 20.5 mm
(ii) Mean rainfall for the week
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.12
(iii) The rainfall was less than the mean rainfall on 5 days.

Question 9.
The heights of 10 girls were measured in cm and the results are as follows:
135, 150, 139, 128, 151, 132, 146, 149, 143, 141.
(i) What is the height of the tallest girl?
(i) What is the height of the shortest girl?
(iii) What is the range of the data?
(iv) What is the mean height of the girls?
(v) How many girls have heights more than the mean height?

Solution:
(i) Height of the tallest girl = 151 cm
(ii) Height of the shortest girl = 128 cm
(iii) Range of the data
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.13
(v) 5 girls have heights more than the mean height.

We hope the NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1 helps you. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Science Chapter 9 Soil

NCERT Solutions for Class 7 Science Chapter 9 Soil are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 9 Soil.

Board CBSE
Textbook NCERT
Class Class 7
Subject Science
Chapter Chapter 9
Chapter Name Soil
Number of Questions Solved 10
Category NCERT Solutions

NCERT Solutions for Class 7 Science Chapter 9 Soil

Tick the most suitable answer in questions 1 and 2.
Question 1.
In addition to the rock particles, the soil contains
(i) air and water
(ii) water and plants
(iii) minerals, organic matter, air and water
(iv) water, air and plants
Answer:
(iii) minerals, organic matter, air and water

Question 2.
The water holding capacity is the highest in
(i) sandy soil
(ii) clayey soil
(iii) loamy soil
(iv) mixture of sand and loam
Answer:
(ii) clayey soil

Question 3.
Match the items in Column I with those in Column II :

Column I Column II
(i) A home for living organisms (a) Large particles
(ii) Upper layer of the soil (b) All kinds of soil
(iii) Sandy soil (c) Dark in colour
(iv) Middle layer of the soil (d) Small particles and packed tight
(v) Clayey soil (e) Lesser amount of humus

Answer:

Column I Column II
(i) A home for living organisms (b) All kinds of soil
(ii) Upper layer of the soil (c) Dark in colour
(iii) Sandy soil (a) Large particles
(iv) Middle layer of the soil (e) Lesser amount of humus
(v) Clayey soil (d) Small particles and packed tight

Question 4.
Explain how soil is formed?
Answer:

  1.  The big and heavy rocks are broken into smaller pieces that come on the surface of the earth.
  2. Soil is formed by breaking down of rocks by the action of wind, water, and climate. This process is called weathering.
  3.  The smaller particles of the rocks obtained due to weathering get further decomposed on long exposure to air and moisture.
  4.  Finally, the decomposed parts of dead plants and animals get mixed up with soil formed by the above processes. This gives the soil enough energy in the form of organic matter.

Question 5.
How is clayey soil useful for crops?
Answer:
Clayey soil retains water to a great extent. Thus the crops which require more water grow well in clayey soil.

Question 6.
List the differences between clayey soil and sandy soil.
Answer:

Clayey Soil Sandy Soil
1.Proportion of fine particles is large. 1.Proportion of big particles is large.
2. Has least percolation rate of water. 2. Has largest percolation rate of water.
3. Has good water holding capacity. 3. Has poor water holding capacity.

Question 7.
Sketch the cross-section of soil and label the various layers.
Answer:
NCERT Solutions for Class 7 Science Chapter 9 Soil Q.7
Fig. A soil profile. Various horizontal zones indicate the stages in soil formation

Question 8.
Razia conducted an experiment in the field related to the rate of percolation. She observed that it took 40 min for 200 mL of water to percolate through the soil sample. Calculate the rate of percolation.
Answer:
Given, amount of water = 200 mL
Time taken = 40 min
Rate of percolation (mL/min) = \(\frac { Amount of water(mL) }{ Amount of water(mL) }\)
= \(\frac { 200 ml}{ 40 Min }\)
= 5 mL / min .

Question 9.
Explain, how soil pollution and soil erosion could be prevented.
Answer:
Prevention of soil pollution:

  1. There should be a ban on polythene bags and plastics.
  2. Waste products and chemicals should be treated before they are released into the soil.
  3. The use of pesticides should be minimized

Prevention of soil erosion:

  1. By growing trees.
  2. Avoid deforestation.
  3. Maintaining the porous structure of the soil.
  4. Control and reclamation of ravines and shifting of cultivation.

Question 10.
Solve the following crossword puzzle with the clues given below:
NCERT Solutions for Class 7 Science Chapter 9 Soil Q.10.1
Across
2. Plantation prevents it.
5. Use should be banned to avoid soil pollution.
6. Type of soil used for making pottery.
7. Living organism in the soil.
Down
1. In desert, soil erosion occurs through.
3. Clay and loam are suitable for cereals like.
4. This type of soil can hold very little water.
5. Collective name for layers of soil.
Answer:
NCERT Solutions for Class 7 Science Chapter 9 Soil Q.10.2

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NCERT Solutions for Class 7 Science Chapter 1 Nutrition in Plants

NCERT Solutions for Class 7 Science Chapter 1 Nutrition in Plants are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 1 Nutrition in Plants.

Board CBSE
Textbook NCERT
Class Class 7
Subject Science
Chapter Chapter 1
Chapter Name Nutrition in Plants
Number of Questions Solved 13
Category NCERT Solutions

NCERT Solutions for Class 7 Science Chapter 1 Nutrition in Plants

Question 1.
Why do organisms need to take food?
Answer:
Organisms need to take food to

  1. get the energy to do work.
  2.  build up the body.
  3. repair damages in the body.
  4.  maintain the functions of the body.

Question 2.
Distinguish between a parasite and a saprotroph.
Answer:

Parasite Saprotroph

1. A parasite takes the food from the organism on which it survives.

1. They secrete digestive juices on the dead and decaying matter and convert it into a solution

2. They feed on a living organism. 2. They feed on dead and decaying matter.
3. The organism on which it survives is called host. 3. They do not feed on a living organism.
4. It deprives the host of valuable nutrients. 4. There is no host at all.

 Question 3.
How would you test the presence of starch in leaves?
Answer:

  1. Take two healthy green potted plants of the same kind in order to remove all the starch from the leaves.
  2.  Keep one in the darkroom (or in a black box) for 72 hours and the other in the sunlight.
  3.  Now, take one leaf from each of the plants.
  4. Put few drops of iodine solution on each of the leaves.
  5.  The leaf kept in the sunlight will turn blue-black due to the presence of starch.
  6. The leaf kept in the dark will not turn blue-black because of the absence of starch.

Question 4.
Give a brief description of the process of synthesis of food in green plants.
Answer:
The leaves of a plant have a green pigment called chlorophyll. In the presence of sunlight, they use carbon dioxide and water to synthesize carbohydrates.
Carbon dioxide + Water \(\xrightarrow [ Sunlight ]{ Chlorophyll } \) Carbohydrade + Water + Oxygen
During the process, oxygen is released. The carbohydrates ultimately get converted into starch.
Carbon dioxide from the air is taken through stomata. Water and minerals are absorbed by the roots and transported to the leaves.

Question 5.
Show with the help of a sketch that plants are the ultimate source of food.
Answer:
NCERT Solutions for Class 7 Science Chapter 1 Nutrition in Plants Q.5

Fig. Plants capture solar energy by a unique process called photosynthesis

Question 6.
Fill in the blanks:

  1. Green plants are called …….. since they synthesize their own food.
  2. The food synthesized by the plants is stored as ………
  3. In photosynthesis solar energy is captured by the pigment called ……….
  4. During photosynthesis plants take in ……… and release ……….

Answer:

  1. autotrophs
  2. starch
  3. chlorophyll
  4. carbon dioxide, oxygen

Question 7.
Name the following:

  1. A parasitic plant with a yellow, slender, and branched stem.
  2. A plant that is partially autotrophic.
  3. The pores through which leave exchange gases.

Answer:

  1. Cuscuta
  2. Insectivorous plants
  3. Stomata

Question 8.
Tick the correct answer:
(a) Amarbel is an example of:
(i) Autotroph
(ii) Parasite
(iii) Saprotroph
(iv) Host
(b) The plant which traps and feeds on insects is:
(i) Cuscuta
(ii) China rose
(iii) Pitcher plant
(iv) Rose
Answer:
(ii) Parasite
(iii) Pitcher plant

Question 9.
Match the items given in Column I with those in Column II.

Column I Column II
Chlorophyll Bacteria
Nitrogen Heterotrophs
Cuscuta Pitcher plant
Animals Leaf
Insects Parasite

Answer:

Column I Column II
Chlorophyll Leaf
Nitrogen Bacteria
Cuscuta Parasite
Animals Heterotrophs
Insects Pitcher plant

 Question 10.
Mark T if the statement is true and ‘F’ if it is false:
(i) Carbon dioxide is released during photosynthesis. (T/F)
(ii) Plants which synthesize their food are called saprotrophs. (T/F)
(iii) The product of photosynthesis is not a protein. (T/F)
(iv) Solar energy is converted into chemical energy during photosynthesis. (T/F)
Answer:
(i) F
(ii) F
(iii) T
(iv) T

Question 11.
Choose the correct option from the following:
Which part of the plant takes in carbon dioxide from the air for photosynthesis?
(i) Root hair
(ii) Stomata
(iii) Leaf veins
(iv) Petals
Answer:
(ii) Stomata

Question 12.
Choose the correct option from the following:
Plants take carbon dioxide from the atmosphere mainly through their:
(i) roots
(ii) stem
(iii) flowers
(iv) leaves
Answer:
(iv) leaves

Question 13.
Why do farmers grow many fruits and vegetable crops inside large greenhouses? What are the advantages to the farmers?
Answer:
Most of the crops require a lot of nitrogen to make protein. After the harvest, the soil becomes deficient in nitrogen. Though nitrogen gas is available in the air, plants cannot use it directly. They need nitrogen in a soluble form. The bacterium called Rhizobium can take atmospheric nitrogen and convert it into soluble nitrogenous components. Rhizobium is present in the roots of some fruits and vegetables and legumes plants which provides nitrogen to them. By crop rotation, farmers increase the nitrogenous compounds in soil. So there is no need to add nitrogenous fertilizers to the soil in which leguminous plants are grown. By this practice, farmers provide good quality crops and save money.

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NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones

NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones.

Board CBSE
Textbook NCERT
Class Class 7
Subject Science
Chapter Chapter 8
Chapter Name Winds, Storms and Cyclones
Number of Questions Solved 9
Category NCERT Solutions

NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones

Question 1.
Fill the missing word in the blank spaces in the following statements :

  1. The wind is ……… air.
  2. Winds are generated due to ……….. heating on the earth.
  3. Near the earth’s surface …………. air rises up whereas ………. air comes down.
  4. Air moves from a region of ……….. pressure to a region of ……….. pressure.

Answer:

  1. moving
  2. uneven
  3. warm, comparatively cooler
  4. high air, low air

Question 2.
Suggest two methods to find out wind direction at a given place.
Answer:
Two methods to find out wind directions are:
(i) using weathercock (Fig.).
(ii) one simple method used by common people is to hold some dust and release in the air. Dust will fly in the direction of air.
NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones Q.2
Fig. A weathercock

Question 3.
State two experiences that made you think that air exerts pressure (other than those given in the text).
Answer:
Experiment 1: When we fill the air in a balloon it flattens due to pressure exerted by air. Also when it is overfilled with air it bursts due to excess air pressure
NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones Q.3
Fig. Air exerts pressure
Experiment 2: When we hang a banner in a place of moving fast air, it tears due to the pressure exerted by the air.

Question 4.
You want to buy a house. Would you like to buy a house having windows but no ventilators? Explain your answer.
Answer:
No, a house which has no ventilators is not a safe or healthy house to live in. The air circulation is not present in such a house. So, it has no fresh air. Because warm air rises up and goes out through ventilators and fresh air comes in through windows.

Question 5.
Explain why holes are made in hanging banners and hoardings.
Answer:
We know that air exerts pressure. If there are no holes in the banners and hoardings they will be damaged. To make them safe, holes are made to give the air safe passage.

Question 6.
How will you help your neighbours in case a cyclone approaches your village/ town?
Answer:
I will help by following ways :

  1. Warning everyone about the coming danger.
  2.  Searching for shelter.
  3. Keeping storage of water and food.
  4. Setting up a first-aid facility.

Question 7.
What planning is required in advance to deal with the situation created by a cyclone?
Answer:
To deal with the situation created by a cyclone we must do the following planning in advance.
On the part of the government:

  • Rapid communication of warnings to the government agencies, the ports, fishermen, ships, and to the general public must be ensured.
  • There must be the construction of cyclone shelters in cyclone-prone areas and administrative arrangements for moving people fast to safer places.

On the part of the public following actions must be taken:

  • keep ready the phone numbers of all emergency services like police, fire brigade, and medical centres.
  • make necessary arrangements to shift the essential household goods, domestic animals and vehicles, etc., to safer places.

Question 8.
Which one of the following places is unlikely to be affected by a cyclone?
(i) Chennai
(ii) Mangaluru (Mangalore)
(iii) Amritsar
(iv) Puri
Answer:
(iii) Amritsar

Question 9.
Which of the statements given below is correct?
(i) In winter the winds flow from the land to the ocean.
(ii) In summer the winds flow from the land towards the ocean.
(iii) A cyclone is formed by a very high-pressure system with very high-speed winds revolving around it.
(iv) The coastline of India is not vulnerable to cyclones.
Answer:
(i) In winter the winds flow from the land to the ocean.

We hope the NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones help you. If you have any query regarding NCERT Solutions for Class 7 Science Chapter 8 Winds, Storms and Cyclones, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1

NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1.

Board CBSE
Textbook NCERT
Class Class 7
Subject Maths
Chapter Chapter 1
Chapter Name Integers
Exercise Ex 1.1
Number of Questions Solved 10
Category NCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1

Question 1.
Following number line shows the temperature in degree Celsius (°C) at different places on a particular day:
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 1
(a) Observe this number line and write the temperature of the places marked on it.
(b) What is the temperature difference between the hottest and the coldest places among the above?
(c) What is the temperature difference between Lahul-Spiti and Srinagar?
(d) Can we say temperature of Srinagar and Shimla taken together is less than the temperature at Shimla? Is it also less than the temperature at Srinagar?
Solution:
(a)
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 2
(b) The hottest place is Bangalore (22 °C) and the coldest place is Lahulspiti (-8°C). The temperature difference between the hottest and the coldest places
= 22 °C – (-8 °C)
= 22 °C + 8 °C
= 30 °C

(c) Temperature difference between Lahul-Spiti and Srinagar
= Temperature of Srinagar
– Temperature of Lahul-Spiti
= – 2°C – (- 8°C)
= – 2°C + 8°C
= 6°C

(d) Yes, we can say that the temperature of Srinagar and Shimla took together is less than the temperature at Shimla as -2 + 5 = 3 and 3 < 5.
This temperature is not less than the temperature at Srinagar.

Question 2.
In a quiz, positive marks are given for correct answers and negative marks are given for incorrect answers. If Jack’s scores in five successive rounds were 25, -5, -10, 15 and 10, what was his total at the end?
Solution:
Total at the end
= 25 + (- 5) + (- 10) + 15 + 10
= (25 + 15 + 10) + {(- 5) + (- 10))
= 50 + (- 15) = 35

Question 3.
At Srinagar, the temperature was – 5°C on Monday and then it dropped by 2°C on Tues¬day. What was the temperature of Srinagar on Tuesday? On Wednesday, it rose by 4°C. What was the temperature on this day?
Solution:
At Srinagar, the temperature was on Monday = -5 °C
Since the temperature was dropped by 2 °C on Tuesday, therefore, the temperature was on Tuesday = (-5-2) °C = -7°C
Also, on Wednesday the temperature rose by 4 °C.
∴ Temperature on Wednesday= (-7 + 4) °C = -3 °C

Question 4.
A plane is flying at the height of 5000 m above sea level. At a particular point, it is e×actly above a submarine floating 1200 m below sea level. What is the vertical distance between them?
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 3
Solution:
The vertical distance between the plane and submarine.
= 5000 m – (- 1200 m)
= 5000 m + 1200 m
= 6200 m.

Question 5.
Mohan deposits ₹ 2,000 in his bank account and withdraws ₹1,642 from it, the next day. If the withdrawal of the amount from the account is represented by a negative integer, then how will you represent the amount deposited?
Find the balance in Mohan’s account after the withdrawal.
Solution:
The amount deposited will be represented by a positive integer.
Balance in Mohan’s account after withdrawal
= (+ ₹ 2000) + (- ₹ 1642)
= ₹ (2000-1642)
= ₹ 358

Question 6.
Rita goes 20 km towards the east from point A to point B. From B, she moves 30 km towards the west along the same road. If the distance towards the east is represented by a positive integer then, how will you represent the distance travelled towards the west? By which integer will you represent her final position from A?
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 4
Solution:
The distance towards the west = -30 km
Her final position from A
= + 20 km + (- 30) km
= – (30 – 20) km
= – 10 km.

Question 7.
In a magic square each row, column, and diagonal have the same sum. Check which of the following is a magic square.
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 5
Solution:
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 6
I. Row, Sum = 5 + (- 1) + (- 4)
= 5 + (- 5) = 0
II. Row, Sum = (- 5) + (- 2) + 7
= (- 7) + 7 = 0
III. Row, Sum = 0 + 3 + (- 3)
= 0 + 0 = 0
I. Column, Sum = 5 + (- 5) + 0
= 0 + 0 = 0
II. Column, Sum = (- 1) + (- 2) + 3
= (- 3) + 3 = 0
III. Column, Sum = (- 4) + 7 + (- 3)
= 7 + (- 4) + (- 3)
= 7 + (- 7) = 0
One Diagonal, Sum = 5 + (- 2) + (- 3) = 5 + (- 5) = 0
Other Diagonal, Sum = 0 + (- 2) + (- 4) = 0 + (- 6) = -6 ≠ 0
Therefore, the given square is not a magic square.
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 7
I. Row, Sum = 1 + (- 10) + 0 = – 9
II. Row, Sum = (- 4) + (- 3) + (- 2) = – 9
III. Row, Sum = (- 6) + 4 + (- 7)
= 4 + (- 6) + (- 7)
= 4 + (- 13)
= – (13-4) = -9
I. Column, Sum = 1 + (- 4) + (- 6)
= 1 + (- 10)
= -(10 – 1) = – 9
II. Column, Sum = (- 10) + (- 3) + 4
= (-13)+ 4
= – (13-4) = -9
III. Column, Sum = 0 + (- 2) + (- 7)
= 0 + (- 9) = – 9
One Diagonal, Sum = 1 + (- 3) + (- 7)
= 1 + (- 10)
= -(10-1) = -9
Other Diagonal, Sum = (- 6) + (- 3) + 0
= (- 9) + 0 = – 9
Since each row, column, and diagonal ‘ have the same sum, therefore, the given square is a magic square.

Question 8.
Verify a – (- b) = a + b for the following values of a and b.
(i) a = 21, b = 18
(ii) a = 118, b = 125
(iii) a = 75, b = 84
(iv) a = 28, b = 11.
Solution:
(i) a = 21, b = 18
L.H.S. = a – (- b) = 21 – (- 18) = 21 + 18 = 39 …..(1)
R.H.S. = a + b = 21 + 18 = 39 …..(2)
From (1) and (2), we get a -(-b) = a + b

(ii) a = 118, b = 125
L.H.S. = a – (- b) = 118 – (- 125) = 118 + 125 = 243 …(1)
R.H.S. = a + b = 118 + 125 = 243 …(2)
From (1) and (2), we get a -(- b) = a + b

(iii) a = 75, b = 84
L.H.S. = a – (- b) = 75 – (- 84) = 75 + 84 = 159 …(1)
R.H.S. = a + b = 75 + 84 = 159 …(2)
From (1) and (2), we get a – (- b) = a + b

(iv) a = 28, b = 11
L.H.S. = a – (- b) = 28 -(-11) = 28 + 11 = 39 …(1)
R.H.S. = a + b = 28 + 11 = 39 …(2)
From (1) and (2), we get a – (- b) = a + b.

Question 9.
Use the sign of >, < or = in the bo× to make the statements true.
(a) (- 8) + (-4) …… (- 8) – (- 4)
(b) (-3) +7 – (19) …… 15-8 +(-9)
(c) 23 – 41 + 11 …… 23-41- 11
(d) 39 + (-24) – (15) …… 36+ (-52) – (- 36)
(e) – 231 + 79 + 51 …… -399 + 159 + 81.
Solution:
(a) L.H.S. = (- 8) + (- 4)
= – (8 + 4) = – 12
R.H.S. = (- 8) – (- 4)
= – 8 + 4 = – (8 – 4) = – 4
∴ (-8) + (-4) < (-8)-(-4)

(b) L.H.S. = (-3) + 7 – (19)
= + 4 – (19)
= + 4 – 19
= -15
R.H.S. = 15 – 8 + (- 9)
= 7 + (-9) = 7- 9 = -2
∴ (- 3) + 7 – (19) < 15 – 8 + (- 9)

(c) L.H.S. = 23 – 41 + 11
= 23 + 11- 41
= 34 – 41 = – (41 – 34)
= – 7
R.H.S. = 23 – 41 – 11
= 23 – (41 + 11)
= 23 – 52
= – (52 – 23)
= – 29
∴ 23 – 41 + > 23 – 41 – 11

(d) L.H.S. = 39 + (- 24) – (15)
= 39 – 24 – (15)
= 15 – (15) = 0
R.H.S. = 36 + (- 52) – (- 36)
= – (52 – 36) – (- 36)
= – 16 – (- 36)
= – 16 + 36 = 20
∴ 39 + (- 24) – (15) < 36 + (- 52) – (- 36)

(e) L.H.S. = – 231 + 79 + 51
= – 231 + 130
= – (231 – 130) = – 101
R.H.S. = – 399 + 159 + 81
= – 399 + 240
= – (399 – 240)
= – 159
∴ – 231 + 79 + 51 > – 399 + 159 + 81.

Question 10.
A water tank has stepped inside it. A monkey is sitting on the topmost step (i.e., the first step The water level is at the ninth step.
NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 8
(i) He jumps 3 steps down and 2 steps up. In how many jumps will he reach the water level?
(ii) After drinking water he wants to go back. For this, he jumps 4 steps up and then jumps back 2 steps down in every move. In how many jumps will he reach back the top step?
(iii) If the number of steps moved down is represented by negative integers and the number of steps moved up by positive integers, represent his moves in part (i) and (ii) by completing the following;
(a) -3 + 2 – …………. = -8
(b) 4 – 2 + = 8.
In (a) the sum (-8) represents going down by eight steps. So, what will the sum 8 in (b) represent?
Solution:
(i) While going down the monkey jumps 3 steps down and then jumps back 2 steps up. To reach the water level he is to jump as under:
-3+ 2 -3 + 2 – 3 +2 – 3 + 2 – 3 + 2 – 3 = -8 Hence, he takes 11 jumps to reach the water level.
(ii) After drinking water, he jumps back as under to reach the top step as under : 4 – 2+ 4 – 2+ 4 = 8
Hence, he takes 5 jumps to reach back the top.
(iii) (a) – 3 + 2 – 3 + 2 – 3 + 2 – 3 + 2 – 3 + 2 – 3 = -8
(b) 4 – 2 + 4 – 2 + 4 = 8
In (b) the sum 8 represents going up 8 steps.

We hope the NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1 help you. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1.

Board CBSE
Textbook NCERT
Class Class 7
Subject Maths
Chapter Chapter 10
Chapter Name Practical Geometry
Exercise Ex 10.1
Number of Questions Solved 3
Category NCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1

Question 1.
Draw a line, say, AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only.
Solution:
Steps of Construction

  1. Draw a line AB.
  2. Take a point C outside it.
  3. Take any point D on AB.
  4. Join C to D.
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1 1
  5. with D as centre and a convenient radius, draw an arc cutting AB at F and CD at E.
  6. Now with C as centre and the same radius as in step 5, draw an arc GH cutting CD at I.
  7. Place the pointed tip of the compasses at F and adjust the opening so that the pencil tip is at E.
  8. With the same opening as in step 7 and with I as centre, draw an arc cutting the arc GH at J.
  9. Now join CJ to draw a line ‘KL’. Then KL is the required line.

Question 2.
Draw a line l. Draw a perpendicular to l at any point on l. On this perpendicular choose a point X, 4 cm away from l. Through X, draw a line m parallel to l.
Solution:
Steps of Construction

  1. Draw a line l.
  2. Take any point A on line l.
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1 2
  3. Construct an angle of 90° at point A of line l and draw a line AL perpendicular to line l.
  4. Mark a point X on AL such that AX = 4 cm.
  5. At X construct an angle of 90° and draw a line XC perpendicular to line AL.
  6. Then line XC (line m) is the required line through X such that m || l.

Question 3.
Let l be a line and P be a point not on l. Through P, draw a line m parallel to l. Now join P to any point Q on l. Choose any other point R on m. Through R, draw a line parallel to PQ. Let this meet l at S. What shape do the two sets of parallel lines enclose?
Solution:
Steps of Construction

  1. Draw a line l and take a point P not on it.
  2. Take any point Q on l.
  3. Join Q to P.
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1 3
  4. Draw a line m parallel to line l, as shown in the figure. Then line m || line l.
  5. Join P to any point Q on l.
  6. Choose any point R on m.
  7. Join R to Q.
  8. Through R, draw a line n parallel to the line PQ.
  9. Let the line n meet the line l at S.
  10. Then, the shape enclosed by the two sets of parallel lines is a parallelogram.

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