On this page, you will find Constructions Class 10 Notes Maths Chapter 11 Pdf free download. CBSE NCERT Class 10 Maths Notes Chapter 11 Constructions will seemingly help them to revise the important concepts in less time.

## CBSE Class 10 Maths Chapter 11 Notes Constructions

### Constructions Class 10 Notes Understanding the Lesson

Division of a line segment internally in the given ratio.

Let AB be a line segment of certain length. We need a point P on AB dividing it internally in the ratio m : n

Steps of Construction: Let m = 4, n = 3.

- Draw a line segment AB of given length.
- Make an acute ∠BAX with AB
- Use a compass of any radius and mark 7(i.e. m + n) points A
_{1}, A_{2},…… , A_{7}

such that AA_{1}= A_{1}A_{2}= A_{2}A_{3}=………………= A_{6}A_{7 } - Join BA
_{7} - Through the point A
_{4}[m = 4], draw a line parallel to BA_{7}by making an angle equal to AA_{7}B at A_{4}intersecting AB at P. Then AP : PB = 4 : 3.

Construction of a Triangle similar to a given Triangle as per given scale factor.

1. Scale Factor \(\frac{m}{n}\)(where m < n)

Steps of construction: Let \(\frac{m}{n}=\frac{3}{4}\)

- Construct a triangle ABC by using given data.
- Make an acute angle ∠BAX below the base AB.
- Along AX, mark 4 points [the greater of 3 and 4 in \(\frac{3}{4}\)] as A
_{1}, A_{2},A_{3}, A_{4}such that

AA_{1}= A_{1}A_{2}= A_{2}A_{3}= A_{3}A_{4}. - Join A
_{4 }B

- From A
_{3}, draw A_{g}B’ || A_{4}B, meeting AB at B’.

From B’, draw B’C’ || BC, meeting AC at C’.

Thus, ΔAB’C’ is the required triangle each of whose sides is \(\frac{3}{4} \)of the corresponding side of ΔABC.

2. Scale Factor \(\frac{m}{n} \) (where m > n)

Steps of construction:

Let \(\frac{m}{n}=\frac{5}{3}\)

- Construct ΔABC using given data.
- Make an acute angle ∠BAX below the base AB. Extend AB to AY and AC to AZ.

- Along AX, mark 5 points [the greater of 5 and 3 in \(\frac{5}{3} \)

such that AA_{1}= A_{1}A_{2 }=………. = A_{4}A_{5}. - Join A
_{3}B. - From A
_{g}, draw A_{5}B’ || A_{3}B, meeting AY produced at B’. - From B’, draw B’C’ || BC, meeting AZ produced at C’.

Thus, ΔAB’C’ is the required triangle, each of whose sides is \(\frac{5}{3}\) of the corresponding side of ΔABC.

Construction of the pair of tangents from an external point to a circle.

Let O is the centre of the circle and a point A is external point to a circle.

Steps of construction

- Join AO and bisect it. Let M be the mid-point of AO.
- Taking M as centre and MO as radius, draw a circle.

Let it intersects the given circle at the points B and C. - Join AB and AC.

Thus, AB and AC are the required tangents.