## ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion MCQS

These Solutions are part of ML Aggarwal Class 10 Solutions for ICSE Maths. Here we have given ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion MCQS

**More Exercises**

- ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion Ex 7.1
- ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion Ex 7.2
- ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion Ex 7.3
- ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion MCQS
- ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion Chapter Test

**Choose the correct answer from the given options (1 to 10):**

**Question 1.**

**The ratio of 45 minutes to \(5 \frac { 3 }{ 4 } \) hours is**

**(a) 180:23**

**(b) 3:23**

**(c) 23:3**

**(d) 6:23**

**Solution:**

ratio of 45 minutes to \(5 \frac { 3 }{ 4 } \) hours is

45 minutes to : \(5 \frac { 3 }{ 4 } \) hours

**Question 2.**

**The ratio of 4 litres to 900 mL is**

**(a) 4 : 9**

**(b) 40 : 9**

**(c) 9 : 40**

**(d) 20 : 9**

**Solution:**

4l : 900 ml

= 4000 ml : 900 ml

= 4000 : 900

= 40 : 9 (b)

**Question 3.**

**When the number 210 is increased in the ratio 5 : 7, the the new number is**

**(a) 150**

**(b) 180**

**(c) 294**

**(d) 420**

**Solution:**

210 is increased in the ratio 5 : 7, then

New increased number will be

= 210 × \(\\ \frac { 7 }{ 5 } \)

= 294 (c)

**Question 4.**

**Two numbers are in the ratio 7 : 9. If the sum of the numbers is 288, then the smaller number is**

**(a) 126**

**(b) 162**

**(c) 112**

**(d) 144**

**Solution:**

Ratio in two number = 7 : 9

Sum of numbers = 288

Sum of ratios = 7 + 9

= 16

Smaller number = \(\\ \frac { 288\times 7 }{ 16 } \)

= 126 (a)

**Question 5.**

**A ratio equivalent to the ratio \(\\ \frac { 2 }{ 3 } \) : \(\\ \frac { 5 }{ 7 } \) is**

**(a) 4:6**

**(b) 5:7**

**(c) 15:14**

**(d) 14:15**

**Solution:**

\(\\ \frac { 2 }{ 3 } \) : \(\\ \frac { 5 }{ 7 } \)

Multiply and divide \(\\ \frac { 2 }{ 3 } \) by 7 and

Multiply and divide \(\\ \frac { 5 }{ 7 } \) by 3

**Question 6.**

**The ratio of number of edges of a cube to the number of its faces is**

**(a) 2 : 1**

**(b) 1 : 2**

**(c) 3 : 8**

**(d) 8 : 3**

**Solution:**

No. of edges of the cube = 12

No. of faces = 6

Ratio in edges a cube to the number of faces = 12 : 6

= 2 : 1 (a)

**Question 7.**

**If x, 12, 8 and 32 are in proportion, then the value of x is**

**(a) 6**

**(b) 4**

**(c) 3**

**(d) 2**

**Solution:**

x, 12, 8, 32 are in proportion, then

x × 32 = 12 × 8 (∵ ad = bc)

⇒ x = \(\\ \frac { 12\times 8 }{ 32 } \) = 3

x = 3 (c)

**Question 8.**

**The fourth proportional to 3, 4, 5 is**

**(a) 6**

**(b) \(\\ \frac { 20 }{ 3 } \)**

**(c) \(\\ \frac { 15 }{ 4 } \)**

**(d) \(\\ \frac { 12 }{ 5 } \)**

**Solution:**

The fourth proportion to 3, 4, 5 will be

= \(\\ \frac { 4\times 5 }{ 3 } \)

= \(\\ \frac { 20 }{ 3 } \) (b)

**Question 9.**

**The third proportional to \(6 \frac { 1 }{ 4 } \) and 5 is**

**(a) 4**

**(b) \(8 \frac { 1 }{ 2 } \)**

**(c) 3**

**(d) none of these**

**Solution:**

The third proportional to \(6 \frac { 1 }{ 4 } \) and 5 is

⇒ \(6 \frac { 1 }{ 4 } \) : 5 :: 5 : x

⇒ \(\\ \frac { 25 }{ 4 } \) : 5 :: 5 : x

⇒ x = \(\\ \frac { 5\times 5 }{ 25 } \) × 4

⇒ 4 (a)

**Question 10.**

**The mean proportional between \(\\ \frac { 1 }{ 2 } \) and 128 is**

**(a) 64**

**(b) 32**

**(c) 16**

**(d) 8**

**Solution:**

The mean proportional between \(\\ \frac { 1 }{ 2 } \) and 128 is

= \(\sqrt { \frac { 1 }{ 2 } \times 128 } \)

= √64

= 8 (d)

Hope given ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 7 Ratio and Proportion MCQS are helpful to complete your math homework.

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