NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 10 |

Subject |
Maths |

Chapter |
Chapter 7 |

Chapter Name |
Coordinate Geometry |

Exercise |
Ex 7.1 |

Number of Questions Solved |
10 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1

**Question 1.**

Find the distance between the following pairs of points:

(i) (2, 3), (4, 1)

(ii) (-5, 7), (-1, 3)

(iii) (a, b), (-a, -b)

**Solution:**

**Question 2.**

Find the distance between the points (0, 0) and (36, 15).

**Solution:**

Let points be A (0, 0) and B (36, 15)

The distance between two points is

**Question 3.**

Determine if the points (1, 5), (2, 3) and (-2, -11) are collinear.

**Solution:**

Let points be A (1, 5), B (2, 3) and C (-2, -11)

AB + BC ≠ AC

Hence, the given points are not collinear.

**Question 4.**

Check whether (5, -2), (6, 4) and (7, -2) are the vertices of an isosceles triangle.

**Solution:**

Let points be A(5, -2), B (6, 4) and C (7, -2)

Here, AB = BC

ΔABC is an isosceles triangle.

**Question 5.**

In a classroom, 4 friends are seated at the points A, B, C and D as shown in given figure. Champa and Chameli walk into the class and after observing for a few minutes Champa asks Chameli, “Don’t you think ABCD is a square?” Chameli disagrees. Using distance formula, find which of them is correct.

**Solution:**

Points A (3, 4), B (6, 7), C (9, 4) and D (6, 1)

Here, AB = BC = CD = DA and AC = BD

ABCD is a square.

Hence, Champa is correct.

**Question 6.**

Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer.

(i) (-1, -2), (1, 0), (-1, 2), (-3, 0)

(ii) (-3, 5), (3, 1), (0, 3), (-1, -4)

(iii) (4, 5), (7, 6), (4, 3), (1, 2)

**Solution:**

(i) Let points be A (-1, -2), B (1, 0), C (-1, 2) and D (-3, 0)

Here, AC = BD, AB = BC = CD = AD

Hence, the quadrilateral ABCD is a square.

(ii) Let points be A (-3, 5), B (3, 1), C (0, 3) and D (-1, -4)

The given points do not form any quadrilateral.

(iii) Let points be A(4, 5), B (7, 6), C (4, 3) and D (1, 2)

Here, AB = CD, BC = AD

and AC ≠ BD

The quadrilateral ABCD is a parallelogram.

**Question 7.**

Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).

**Solution:**

Let points be A (2, -5) and B (-2, 9)

Let P (x, 0) be the point on x-axis.

AP = BP

**Question 8.**

Find the values of y for which the distance between the points P (2, -3) and Q (10, y) is 10 units.

**Solution:**

Points P (2, -3), Q (10, y) and PQ = 10 units

The distance between two points is

**Question 9.**

If Q (0, 1) is equidistant from P (5, -3), and R (x, 6), find the values of x. Also find the distances QR and PR.

**Solution:**

Points are P (5, -3) and R (x, 6)

Point Q (0, 1) is equidistant from points P (5, -3) and R (x, 6).

**Question 10.**

Find a relation between x and y such that the point (x, y) is equidistant from the points (3, 6) and (-3, 4).

**Solution:**

Points A(3, 6) and B(-3, 4) are equidistant from point P(x, y)

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