NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 10 |

Subject |
Maths |

Chapter |
Chapter 8 |

Chapter Name |
Introduction to Trigonometry |

Exercise |
Ex 8.2 |

Number of Questions Solved |
4 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2

**Class 10 Ex 8.2 Question 1.**

Evaluate the following:

**Solution:**

**Ex 8.2 Class 10 Question 2.**

Choose the correct option and justify your choice:

**Solution:**

**Exercise 8.2 Class 10 Question 3.**

If tan (A + B) = √3 and tan (A – B) = \(\frac { 1 }{ \surd 3 }\); 0° < A + B ≤ 90°; A > B, find A and B.

**Solution:**

tan (A + B) = √3

⇒ tan (A + B) = tan 60°

⇒ A + B = 60° ……(i)

tan (A – B) = \(\frac { 1 }{ \surd 3 }\)

⇒ tan (A – B) = tan 30°

⇒ A – B = 30° ……..(ii)

Adding equation (i) and (ii), we get

2A = 90° ⇒ A = 45°

From (i), 45° + B = 60° ⇒ B = 60° – 45° = 15°

Hence, ∠A = 45°, ∠B = 15°

**Exercise 8.2 Class 10 NCERT Solution Question 4.**

State whether the following statements are true or false. Justify your answer.

(i) sin (A + B) = sin A + sin B.

(ii) The value of sin θ increases as θ increases.

(iii) The value of cos θ increases as θ increases.

(iv) sin θ = cos θ for all values of θ.

(v) cot A is not defined for A = 0°.

**Solution:**

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