NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2.

- Practical Geometry Class 6 Ex 14.1
- Practical Geometry Class 6 Ex 14.3
- Practical Geometry Class 6 Ex 14.4
- Practical Geometry Class 6 Ex 14.5
- Practical Geometry Class 6 Ex 14.6

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 14.2 |

Number of Questions Solved |
5 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Question 1.

Draw a line segment of length 7.3 cm. using a ruler.

Solution :

Using ruler, we mark two points A and B which are 7.3 cm apart. Join A and B and get AB. \(\overline { AB }\) is a line segment of length 7.3 cm.

Question 2.

Construct a line segment of length 5.6 cm using ruler and compasses.

Solution :

**Step 1.** Draw a line l. Mak a point A on line l.

**Step 2.** Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 5.6 cm mark.

**Step 3.** Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.

**Step 4.** AB is a line segment of required length.

Question 3.

Construct \(\overline { AB }\) of length 7.8 cm. From this cut off \(\overline { AC }\) of length 4.7 cm. Measure \(\overline { BC }\).

Solution :

**Steps of Construction**

**Step 1.** Draw a line l. Mark a point A on line l.

**Step 2.** Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 7.8 cm mark.

**Step 3.** Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.

**Step 4.** \(\overline { AB }\) is a line segment of length 7.8 cm.

**Step 5.** Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto 4.7 cm mark.

**Step 6.** Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at C.

**Step 7.** \(\overline { AC }\) is a line segment of length 4.7 cm. On measurement. \(\overline { BC }\) =3.1 cm.

Question 4.

Given \(\overline { AB }\) of length 3.9 cm, construct \(\overline { PQ }\) such that the length of \(\overline { PQ }\) is twice that of AB Verify by measurement.

(**Hint :** Construct \(\overline { PX }\) such that length of PX = length of \(\overline { AB }\); then cut off \(\overline { XQ }\) such that \(\overline { XQ }\) also has the length of \(\overline { AB }\)).

Solution :

**Steps of Construction**

**Step 1.** Draw a line I. Mark a point P on line l.

**Step 2.** Place the compasses pointer on the A mark of the given line segment \(\overline { AB }\) . Open it to place the pencil point upto B mark of the given line segment \(\overline { AB }\).

**Step 3.** Without changing the opening of the compasses, place the pointer on P and swing an arc to cut l at X.

**Step 4.** Again without changing the opening of the compasses place the compasses pointer on the X mark of line / and swing an arc to cut / at Q.

**Step 5.** \(\overline { PQ }\) is a line segment of length twice that of \(\overline { AB }\). Please verify yourself by measurement.

Question 5.

Given \(\overline { AB }\) of length 7.3 cm and \(\overline { CD }\) of length 3.4 cm, construct a line segment \(\overline { XY }\) such that the length of \(\overline { XY }\) is equal to the difference between the lengths of \(\overline { AB }\) and \(\overline { CD }\) . Verify by measurement.

Solution :

**Steps of Construction**

**Step 1.** Draw a line l. Mark a point X on line l.

**Step 2.** Place the compasses pointer on the A mark of the given line segment \(\overline { AB }\). Open it to place the pencil point upto B mark of the given line segment \(\overline { AB }\).

**Step 3.** Without changing the opening of the compasses, place the pointer of compasses on X and swing an arc to cut / at ∠.

**Step 4.** Place the compasses pointer on the C mark of the given line segment \(\overline { CD }\). Open it to place the pencil point upto D mark of the given line segment \(\overline { CD }\).

**Step 5.** Without changing the opening of the compasses, place the pointer of compasses on ∠ and swing an arc towards X to cut l at Y.

**Step 6.** \(\overline { XY }\) is a required line segment of length = the difference between the lengths of \(\overline { AB }\) and \(\overline { CD }\).

Please verify yourself by measurement.

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