NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.1 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.1.

- Simple Equations Class 7 Ex 4.2
- Simple Equations Class 7 Ex 4.3
- Simple Equations Class 7 Ex 4.4
- Simple Equations Class 7 MCQ

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Simple Equations |

Exercise |
Ex 4.1 |

Number of Questions Solved |
6 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.1

**Question 1.**

Complete the last column of the table.

**Solution:
**

**Question 2.**

Check whether the value given in the brackets is a solution to the given equation or not.

**(a)** n + 5 = 19 (n = 1)

**(b)** 7n + 5 = 19 (n = – 2)

**(c)** 7n + 5 = 19 (n = 2)

**(d)** 4p – 3 = 13 (p = 1)

**(e)** 4p – 3 = 13 (p = – 4)

**(f)** 4p – 3 = 13 (p = 0).

**Solution:**

**(a) n + 5 = 19 (n = 1)**

L.H.S. = n + 5 = 1 + 5 | when n = 1 = 5

R.H.S. = 19

∵ L.H.S. ≠ R.H.S.

∴ n = 1 is not a solution to the given equation n + 5 = 19.

**(b) 7n + 5 = 19 (n = – 2)**

L.H.S. = 7n + 5 = 7(- 2) + 5 | when n = – 2 = – 14 + 5 = – 9

R.H.S. = 19

∵ L.H.S. ≠ R.H.S.

∴ n = – 2 is not a solution to the given equation 7n + 5 = 19.

**(c) 7n + 5 = 19 (n = 2)**

L.H.S. = In + 5 = 7(2) + 5 | when n = 2 = 14 + 5 = 19 = R.H.S.

∴ n = 2 is a solution to the given equation 7n + 5 = 19.

**(d) 4p – 3 = 13 (p = 1)**

L.H.S. = 4p – 3 = 4(1) – 3 | when p = 1 = 4 – 3 = 1

R.H.S. = 13

∵ L.H.S. ≠ R.H.S.

∴ p = 1 is not a solution to the given equation 4p – 3 = 13.

**(e) 4p – 3 = 13 (p = – 4)**

L.H.S. = 4p – 3 = 4(- 4) – 3 , | when p = – 4 = – 16 – 3 = – 19

R.H.S. = 13

∵ L.H.S. ≠ R.H.S.

∴ p = – 4 is not a solution to the given equation

4p – 3 = 13.

**(f) 4p – 3 = 13 (p = 0)**

L.H.S. = 4 (p) – 3 = 4(0) – 3 | when p = 0 = 0 – 3 = – 3

R.H.S. = 13

∵ L.H.S. ≠ R.H.S.

∴ p = 0 is not a solution to the given equation 4p – 3 = 13.

**Question 3.**

Solve the following equations by trial and error method.

- 5p + 2 = 17
- 3m – 14 = 4.

**Solution:**

**(i) 5p + 2 = 17
**

So, p = 3 is the solution of the given equation 5p + 2 = 17.

**(ii) 3m – 14 = 4
**

So, m = 6 is the solution of the given equation 3m – 14 = 4.

**Question 4.**

Write equations for the following statements.

- The sum of numbers x and 4 is 9.
- 2 subtracted from y is 8.
- Ten times a is 70.
- The number b divided by 5 gives 6.
- Three-fourth oft is 15.
- Seven times m plus 7 gets you 77.
- One-fourth of a number x minus 4 gives 4.
- If you take away 6 from 6 times y, you get 60.
- If you add 3 to one-third of z, you get 30.

**Solution:**

- x + 4 = 9
- y – 2 = 8
- 10 a = 70
- b ÷ 5 = 6
- \(\frac { 3 }{ 4 } \) × t = 15
- 7m + 7 = 77
- \(\frac { 1 }{ 4 } \) × x – 4 = 4
- 6y – 6 = 60
- \(\frac { 1 }{ 3 } \) × z + 3 = 30

**Question 5.**

Write the following equations in statement forms:

- p + 4 = 15
- m – 7 = 3
- 2m = 7
- \(\frac { m }{ 5 } \) = 3
- \(\frac { 3m }{ 5 } \) = 6
- 3p + 4 = 25
- 4p – 2 = 18
- \(\frac { p }{ 2 } \) + 2 = 8.

**Solution:**

- The sum of p and 4 is 15.
- 7 subtracted from m is 3.
- Twice a number m is 7.
- One-fifth of a number m is 3.
- Three-fifth of a number m is 6.
- Three times a number p, when added to 4, gives 25.
- 2 subtracted from four times a number p is 18.
- Add 2 to half of a number p to get 8.

**Question 6.**

Set up an equation in the following cases:

- Irfan says that he has 7 marbles more than five times the marbles Permit has. Irfan has 37 marbles. (Take m to be the number of Permit’s marbles.)
- Laxmi’s father is 49 years old. He is 4 years older than three times Laxmi’s age. (Take Laxmi’s age to be y years.)
- The teacher tells the class that the highest marks obtained by a student in her class are twice the lowest marks plus 7. The highest score is 87. (Take the lowest score to be l.)
- In an isosceles triangle, the vertex angle is twice either base angle. (Let the base angle be b in degrees. Remember that the sum of angles of triangle is 180 degrees).

**Solution:
**

**(i)**Let the number of marbles with Parmit be m.

Then, 7 added to 5 times mis 5m + 7

It is given that 7 marbles more than five times the marble is 37. Thus, the equation obtained is 5m + 7 = 37.

**(ii)** Let Laxmi’s age be y years. Then, 4 added to 3 times y is 3y + 4

It is given that the father is 4 years older than 3 times Laxmi’s age. His age is 49years.

Then, we have the following equation : 3y + 4 = 49

**(iii)** Let the lowest marks be l. Then, twice the lowest marks plus 7 is 2l +7

It is given that, the highest marks 87 obtained by a student is twice the lowest marks plus 7.

So, we have the following equation : 2l + 7 = 87

**(iv)** Let the base angle be b. Then, the vertex angle = 2b.

Since, sum of the angles of a triangle is 180°

∴ b + b + 2b = 180°

⇒ 4b = 180°

which is the required equation.

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