NCERT Solutions for Class 8 Maths Chapter 15 Introduction to Graphs Ex 15.3 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 15 Introduction to Graphs Ex 15.3.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 15 |

Chapter Name |
Introduction to Graphs |

Exercise |
Ex 15.3 |

Number of Questions Solved |
2 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 15 Introduction to Graphs Ex 15.3

**Question 1.**

**Draw the graphs for the following tables of values, with suitable scales on the axes.**

**(a)** Cost of apples

**(b)** Distance travelled by a car

**(i)** How much distance the car cover during the period 7.30 a.m. to 8 a.m.?

**(ii)** What was the time when the car had covered a distance of 100 km since it starts?

**(c)** Interest on deposits for a year.

**(i)** Does the graph pass through the origin?

**(ii)** Use the graph to find the interest on? 2500 for a year.

**(iii)** To get an interest of ? 280 per year, how much money should be deposited?

**Solution.**

**(a)**

**Scale:**

On horizontal axis: 2 units = 1 apple

On vertical axis: 1 unit = ₹ 5

**•** Mark number of apples on the horizontal axis.

**•** Mark cost (in ?) on the vertical axis.

**•** Plot the points: (1, 5), (2, 10), (3, 15), (4, 20) and (5, 25)

**•** Join the points.

We get a linear graph.

**(b)**

**Scale:**

On horizontal axis: 2 units = 1 hour

On vertical axis: 2 units = 40 km

**•** Mark time (in hours) on the horizontal axis.

**•** Mark distances (in km) on the vertical axis.

**•** Plot the points (6 a.m., 40), (7 a.m., 80) (8 a.m., 120) and (9 a.m., 160).

**•** Join the points.

We get a linear graph.

**(i)** Distance covered during 7.30 a.m. to 8 a.m.

= 120 km – 100 km = 20 km

**(ii)** The time when the car had covered a distance of 100 km since its start was 7.30 a.m.

**(c)**

**Scale:**

On horizontal axis: 2 units = ₹ 1000

On vertical axis: 2 units = ₹ 80

**•** Mark deposit (in ₹ on the horizontal axis.

**•** Mark simple interest (in ₹) on the vertical axis.

**•** Plot the points (1000, 80), (2000, 160), (3000, 240) (4000, 320) and (5000, 400).

**•** Join the points.

We get a linear graph.

**(i)** Yes! The graph passes through the origin.

**(ii)** Interest on ₹ 2500 for a year = ₹ 200

**(iii)** To get an interest of ₹ 280 per year, ₹ 3500 should be deposited.

**Question 2.**

**Draw a graph for the following:**

**(i)**

Is it a linear graph?

**(ii)**

Is it a linear graph?

**Solution.**

**(i)**

**Scale:**

On horizontal axis: 1 unit = 1 cm

On vertical axis: 1 unit = 4 cm

**•** Mark side of the square (in cm) on the horizontal axis.

**•** Mark perimeter (in cm) on the vertical axis.

**•** Plot the points (2, 8), (3, 12), (3.5. 14) (5, 20) and (6, 24).

**•** Join the points.

Yes ; it is a linear graph.

**(ii)**

**• Scale:**

On horizontal axis: 2 units = 2 cm

On vertical axis: 1 unit = 2 cm

**•** Mark side of the square (in cm) on the horizontal axis.

**•** Mark area (in cm ) on the vertical axis.

**•** Plot the points (2, 4) (3, 9), (4, 16), (5, 25) and (6, 36).

**•** Join the points.

The graph we get is not linear.

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