NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 16 |

Chapter Name |
Playing with Numbers |

Exercise |
Ex 16.2 |

Number of Questions Solved |
4 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.2

**Question 1.**

If 21y5 is a multiple of 9, where y is a digit, what is the value of y?

**Solution.**

Since 21y5 is a multiple of 9, its sum of digits 2 + 1+ y + 5 = 8+ y isa multiple of 9; so 8 + y is one of these numbers: 0, 9, 18, 27, 36, 45,… .

But since y is a digit, it can only be possible that 8 + y = 9. Therefore, y = 1.

**Question 2.**

If 31z5 is a multiple of 9, where z is a digit, what is the value of z?

You will find that there are two answers to the last problem. Why is this so?

**Solution.**

Since 31z5 is a multiple of 9, its sum of digits 3 + 1 + z + 5 = 9 + z isa multiple of 9; so 9 + z is one of these numbers: 0, 9, 18, 27, 36, 45, … .

But since z is a digit, it can only be possible that 9 + z = 9 or 18. Therefore, z = 0 or 9.

**Question 3.**

If 24x is a multiple of 3, where x is a digit, what is the value of x?

(Since 24x is a multiple of 3, its sum of digits 6 + x is a multiple of 3; so 6 + x is one of these numbers: 0, 3, 6, 9, 12, 15, 18, … .

But since xis a digit, it can only be that 6 + x = 6 or 9 or 12 or 15. Therefore, x = 0 or 3 or 6 or 9. Thus, x can have any of four different values.)

**Solution.**

The solution is given with question.

**Question 4.**

If 31z5 is a multiple of 3, where z is a digit, what might be the values of z?

**Solution.**

Since 31z5 is a multiple of 3, its sum of digits 3 + 1 + z + 5 = 9 + z is a multiple of 3; so 9 + z is one of these numbers: 0, 3, 6, 9, 12, 15, 18, … .

But since z is a digit, it can only be possible that 9 + z = 9 or 12 or 15 or 18. Therefore, z = 0 or 3 or 6 or 9.

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