## RS Aggarwal Class 8 Solutions Chapter 9 Percentage Ex 9B

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 9 Percentage Ex 9B.

**Other Exercises**

- RS Aggarwal Solutions Class 8 Chapter 9 Percentage Ex 9A
- RS Aggarwal Solutions Class 8 Chapter 9 Percentage Ex 9B

**Tick the correct answer in each of the following:**

**Question 1.**

**Solution:**

\(\\ \frac { 3 }{ 5 } \)

= \(\\ \frac { 3X20 }{ 5X20 } \)

= \(\\ \frac { 60 }{ 100 } \)

= 60% (d)

**Question 2.**

**Solution:**

0.8%

= \(\\ \frac { 0.8 }{ 100 } \)

= \(\\ \frac { 8 }{ 10X100 } \)

= \(\\ \frac { 8 }{ 1000 } \)

= 0.008 (b)

**Question 3.**

**Solution:**

6 : 5

= \(\\ \frac { 6 }{ 5 } \)

= \(\\ \frac { 6X20 }{ 5X20 } \)

= \(\\ \frac { 120 }{ 100 } \)

= 120% (c)

**Question 4.**

**Solution:**

5% of a number is 9

Number = \(\\ \frac { 9X100 }{ 5 } \)

= 180 (d)

**Question 5.**

**Solution:**

Let x% of 90 = 120

=> \(\\ \frac { x }{ 100 } \) x 120 = 90

=> x% = \(\\ \frac { 120X100 }{ 90 } \)

= \(133\frac { 1 }{ 3 } %\) (c)

**Question 6.**

**Solution:**

Let x% 10 kg = 250 g

\(\\ \frac { x }{ 100 } \) x 10 kg

= \(\\ \frac { 250 }{ 1000 } \) kg

x = \(\\ \frac { 250X100 }{ 1000X10 } \)

= \(\\ \frac { 25 }{ 10 } \)%

= 2.5% (d)

**Question 7.**

**Solution:**

40% of x = 240

=> x = \(\\ \frac { 240 }{ 40 } \) x 100

= 600 (b)

**Question 8.**

**Solution:**

?% of 400 = 60

=> x% of 400 = 60

\(\\ \frac { x }{ 100 } \) x 400 = 60

x = \(\\ \frac { 60X100 }{ 400 } \)

= 15 (c)

**Question 9.**

**Solution:**

(180% of ?)÷2 = 504

\(\left( \frac { 180 }{ 100 } \times x \right) \div 2\) = 504

\(\frac { 180 }{ 100 } x\) = 504 x 2

\(x=\frac { 504\times 2\times 100 }{ 180 }\)

= 560 (d)

**Question 10.**

**Solution:**

20% of Rs. 800

= \(\\ \frac { 20 }{ 100 } \) x 800

= Rs 160 (a)

**Question 11.**

**Solution:**

Nitin gets = 98 marks

and it is 56% of total marks

Total-marks = \(\\ \frac { 98X100 }{ 56 } \)

= 175 (c)

**Question 12.**

**Solution:**

Let a number be = 1000

Then increase = 10%

Increased number = \(\\ \frac { 100X110 }{ 100 } \) = 110

Now decrease = 1%

Decreased number = \(\\ \frac { 110X90 }{ 100 } \) = 99

Difference = 100 – 99 = 1

% decrease = 1% (b)

**Question 13.**

**Solution:**

4 hours 30 min = \(4\frac { 1 }{ 2 } %\)

= \(\\ \frac { 9 }{ 2 } \) hours

% of a day = \(\\ \frac { 9 }{ 2 } \) x \(\\ \frac { 100 }{ 24 } \)%

= \(\\ \frac { 75 }{ 4 } \)%

= \(18\frac { 3 }{ 4 } %\) (a)

**Question 14.**

**Solution:**

Let total number of examinees = 100

Passed = 65

Failed = 100 – 65 = 35

Now 35% of total examinees = 420

Total examinees = \(\\ \frac { 420X100 }{ 35 } \)

= 1200 (c)

**Question 15.**

**Solution:**

Let number = x

Then x = \(\\ \frac { xX20 }{ 100 } \) = 40

=> 100x – 200x = 4000

80x = 4000

=> x = \(\\ \frac { 4000 }{ 80 } \) = 50

Number = 50 (a)

**Question 16.**

**Solution:**

Rate of decrease = \(27\frac { 1 }{ 2 } %\)

Let number = x

**Question 17.**

**Solution:**

Let x% of 20 = 0.05

\(\\ \frac { x }{ 100 } \) x 20 = 0.05

x = \(\\ \frac { 0.05X100 }{ 20 } \)

= 0.25% (c)

**Question 18.**

**Solution:**

\(\\ \frac { 1 }{ 3 } \) = 1206 = 402

**Question 19.**

**Solution:**

x% of y is y% = \(\\ \frac { xy }{ 100 } \)

\(\\ \frac { y }{ 100 } \) × x

= y% of x (a)

**Question 20.**

**Solution:**

Let x% of \(\\ \frac { 2 }{ 7 } \) = \(\\ \frac { 1 }{ 35 } \)

=>\(\\ \frac { x }{ 100 } \) x \(\\ \frac { 2 }{ 7 } \) = \(\\ \frac { 1 }{ 35 } \)

x = \(\\ \frac { 1X100X7 }{ 35X2 } \)

= 10% (b)

Hope given RS Aggarwal Solutions Class 8 Chapter 9 Percentage Ex 9B are helpful to complete your math homework.

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