## RS Aggarwal Class 9 Solutions Chapter 8 Linear Equations in Two Variables Ex 8A

These Solutions are part of RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 8 Linear Equations in Two Variables Ex 8A.

**Question 1.**

**Solution:**

(i) x = 5 is the line AB parallel to the y-axis at a distance of 5 units.

(ii) y = – 2 is the line CD parallel to x-axis at a distance of – 2 units.

(iii) x + 6 = 0 => x = – 6 is the line EF parallel to y-axis at a distance of – 6 units.

(iv) x + 7 = 0 => x = – 7 is the line PQ parallel to y-axis at a distance of – 7 units.

(v) y = 0 is the equation of x-axis. The graph of y = 0 is the line X’OX

(vi) x = 0 is the equation of y-axis.The graph of x = 0 is the line YOY’

Ans.

**Question 2.**

**Solution:**

In the given equation.

y = 3x

Put x = 1, then y = 3 x 1 = 3

Put x = 2, then y = 3 x 2 = 6

Put x = – 1, then y = 3 ( – 1) = – 3

Now, plot the points (1, 3), (2, 6) and ( – 1, – 3) as given the following table

and join them to form a line of the given equation.

Now from x = – 2,

draw a line parallel to y-axis at a distance of x = – 2, meeting the given line at P. From P, draw, a line parallel to x-axis joining y-axis at M, which is y = – 6 Hence, y = – 6 Ans.

**Question 3.**

**Solution:**

In the given equation x + 2y – 3 = 0

=> 2y = 3 – x

y = \(\frac { 3-x }{ 2 } \)

put x = 1,then

**Question 4.**

**Solution:**

(i) In the equation y = x

When x = 1, then y = 1

when x = 2, then y = 2

and when x = 3, then y = 3

**Question 5.**

**Solution:**

In the given equation

2x – 3y = 5

**Question 6.**

**Solution:**

In the given equation

2x + y = 6

=> y = 6 – 2x

Put x = 1, then y – 6 – 2 x 1 = 6 – 2 = 4

Put x = 2, then y = 6 – 2 x 2 = 6 – 4 = 2

Put x = 3, then y = 6 – 2 x 3 = 6 – 6 = 0

**Question 7.**

**Solution:**

In the given equation

3x + 2y = 6

Hope given RS Aggarwal Class 9 Solutions Chapter 8 Linear Equations in Two Variables Ex 8A are helpful to complete your math homework.

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