## RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Test Yourself

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Test Yourself.

**Other Exercises**

- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a
- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9b
- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9c
- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9d
- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9e
- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f
- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ
- RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself

**Question 1.**

**Solution:
**Correct option: (b)

The cumulative frequency table is useful in determining the median.

**Question 2.**

**Solution:
**Correct option: (c)

Mean = 27

Median = 33

Mode = 3Median – 2Mean

= 3 x 33 – 2 x 27

= 99 – 54

= 45

**Question 3.**

**Solution:**

**Question 4.
**

**Solution:**

**Question 5.**

**Solution:
**

**Question 6.
**

**Solution:**

Number of athletes who completed the race in less than 14.6 seconds

= 2 + 4 + 15 + 54

= 75.

**Question 7.
**

**Solution:**

**Question 8.
**

**Solution:**

**The frequency table is as follows:**

The frequency corresponding to the class 20 – 25 is 4.

**Question 9.**

Solution:

**Question 10.**

**Solution:
**

**Question 11.
**

**Solution:**

**Question 12.**

Solution:

**Question 13.**

**Solution:
**We plot the points (10, 3), (20, 11), (30, 28), (40, 48) and (50, 70) to get the cumulative frequency curve as follows:

**Question 14.**

Solution:

**Question 15.****
Solution:
**We plot the points (20, 2), (30, 7), (40, 17), (50, 40), (60, 60), (70, 82), (80, 85), (90, 90) and (100, 100) to get the cumulative frequency curve as follows:

Here, N = 100 ⇒ N/2 = 50

At y = 50, affix A.

Through A, draw a horizontal line meeting the curve at P.

Through P, a vertical line is drawn which meets OX at M.

OM = 56.

Hence, median = 56

**Question 16.**

Solution:

**Question 17.**

Solution:

**Question 18.**

Solution:

**Question 19.**

Solution:

**Question 20.**

Solution:

**Less Than Series:
**

We plot the points (10, 2), (15, 14), (20, 16), (25, 20), (30, 23), (35, 27) and (40, 30) to get less than ogive.

**More Than Series:**

We plot the points (5, 30), (10, 28), (15, 16), (20, 14), (25, 10), (30, 7) and (35, 3) to get more than ogive.

–

The two curves intersect at L. Draw LM ⊥ OX.

Thus, median = OM = 16.

**Question 21.
**

**Solution:**

**Less Than Series:**

We plot the points (45, 1), (50, 10), (55, 25), (60, 43), (65, 83), (35, 27), (70, 109), (75, 125), (80, 139) and (85, 149) to get less than ogive.

**More Than Series:
**

We plot the points (40, 149), (45, 148), (50, 139), (55, 124), (60, 106), (65, 66), (70, 40), (75, 24) and (80, 10) to get more than ogive.

—

**Question 22.**

**Solution:
**

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