Check the below NCERT MCQ Questions for Class 7 Maths Chapter 4 Simple Equations with Answers Pdf free download. MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. We have provided Simple Equations Class 7 Maths MCQs Questions with Answers to help students understand the concept very well. https://ncertmcq.com/mcq-questions-for-class-7-maths-with-answers/

Students can also refer to NCERT Solutions for Class 7 Maths Chapter 1 Simple Equations for better exam preparation and score more marks.

## Simple Equations Class 7 MCQs Questions with Answers

**Simple Equations Class 7 MCQ Question 1.**

Write the following statement in the form of an equation:

The sum of three times x and 10 is 13.

(a) 3x + 10 = 13

(b) 3x – 10 = 13

(c) 3x + 13 = 10

(d) none of these

## Answer

Answer: (a) 3x + 10 = 13

**Class 7 Maths Chapter 4 MCQ Question 2.**

Write the following statement in the form of an equation:

If you subtract 3 from 6 times a number, you get 9

(a) 3x – 6 = 9

(b) 6x – 3 = 9

(c) 6x + 3 = 9

(d) 3x + 6 = 9

## Answer

Answer: (b) 6x – 3 = 9

**MCQ Questions For Class 7 Maths Chapter 4 Question 3.**

Write the following statement in the form of an equation:

One fourth of n is 3 more than 2

(a) \(\frac { n }{ 4 } \) – 2 = 3

(b) \(\frac { n }{ 4 } \) + 2 = 3

(c) \(\frac { n }{ 2 } \) – 4 = 3

(d) \(\frac { n }{ 2 } \) + 4 = 3

## Answer

Answer: (a) \(\frac { n }{ 4 } \) – 2 = 3

**MCQ On Simple Equations For Class 7 Question 4.**

Write the following statement in the form of an equation:

One third of a number plus 2 is 3

(a) \(\frac { m }{ 3 } \) – 2 = 3

(b) \(\frac { m }{ 3 } \) + 2 = 3

(c) \(\frac { m }{ 2 } \) – 3 = 3

(d) \(\frac { m }{ 2 } \) + 3 = 3

## Answer

Answer: (b) \(\frac { m }{ 3 } \) + 2 = 3

**Class 7 Maths Chapter 4 MCQ With Answers Question 5.**

Write the following statement in the form of an equation:

Taking away 5 from x gives 10

(a) x – 5 = 10

(b) x + 5 = 10

(c) x – 10 – 5

(d) none of these

## Answer

Answer: (a) x – 5 = 10

**Class 7 Maths Ch 4 MCQ Question 6.**

Write the following statement in the form of an equation:

Four times a number p is 8.

(a) 4P = 8

(b) P + 4 = 8

(c) p – 4 = 8

(d) p ÷ 4 = 8

## Answer

Answer: (a) 4P = 8

**Class 7 Math Chapter 4 MCQ Question 7.**

Write the following statement in the form of an equation:

Add 1 to three times n to get 7

(a) 3n + 1 = 7

(b) 3n – 1 = 7

(c) 3n + 7 = 1

(d) none of these

## Answer

Answer: (a) 3n + 1 = 7

**Simple Equations MCQ Class 7 Question 8.**

Write the following statement in the form of an equation:

The number b divided by 6 gives 5.

(a) \(\frac { b }{ 6 } \) = 5

(b) b – 5 = 6

(c) 5b = 6

(d) b + 5 = 6

## Answer

Answer: (a) \(\frac { b }{ 6 } \) = 5

**Class 7 Simple Equations MCQ Question 9.**

The solution of the equation x + 3 = 0 is

(a) 3

(b) -3

(c) 0

(d) 1

## Answer

Answer: (b) -3

Hint:

x + 3 = 0 ⇒ x = -3.

**MCQ Questions On Simple Equations For Class 7 Question 10.**

The solution of the equation x – 6 = 1 is

(a) 1

(b) 6

(c) -7

(b) 7

## Answer

Answer: (d) 7

Hint:

x – 6 = 1 ⇒ x = 1 + 6 = 7.

**Class 7th Maths Chapter 4 MCQ Question 11.**

The solution of the equation 5x = 10 is

(a) 1

(b) 2

(c) 5

(d) 10

## Answer

Answer: (b) 2

Hint:

5x = 10 ⇒ x = \(\frac{10}{5}\) = 2

**MCQ Questions For Class 7 Maths Simple Equations Question 12.**

The solution of the equation \(\frac { m }{ 2 } \) = 3 is

(a) 2

(b) 3

(c) 12

(d) 6

## Answer

Answer: (d) 6

Hint:

\(\frac{m}{2}\) = 3 ⇒ m = 3 × 2 = 6.

**Class 7 Maths Chapter 4 MCQ Online Test Question 13.**

The solution of the equation 7n + 5 = 12 is

(a) 0

(b) – 1

(c) 1

(d) 5

## Answer

Answer: (c) 1

Hint:

7n + 5 = 12 ⇒ 7n = 12 – 5

⇒ 7n = 1 ⇒ n = \(\frac{7}{7}\) = 1.

**Class 7 Chapter 4 Maths MCQ Question 14.**

The solution of the equation 4p – 3 = 9 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (c) 3

Hint:

4p – 3 = 9 ⇒ 4p = 9 + 3 = 12

⇒ p = \(\frac{12}{4}\) = 3.

**MCQ Class 7 Maths Chapter 4 Question 15.**

The solution of the equation 5p + 2 = 7 is

(a) 0

(b) 1

(c) -1

(d) 2

## Answer

Answer: (b) 1

Hint:

5p + 2 = 71 ⇒ 5p = 7 – 2 = 5

⇒ p = \(\frac{5}{5}\) = 1.

Question 16.

The solution of the equation 3p – 2 = 4 is

(a) 0

(b) 1

(c) 2

(d) 3

## Answer

Answer: (c) 2

Hint:

3p – 2 = 4 ⇒ 3p = 4 + 2 = 6

⇒ P = \(\frac{6}{3}\) = 2

Question 17.

The solution of the equation p + 4 = 4 is

(a) 0

(b) 4

(c) -4

(d) 8

## Answer

Answer: (a) 0

Hint:

p + 4 = 4 ⇒ P = 4 – 4 = 0.

Question 18.

The solution of the equation m – 1 = 2 is

(a) 1

(b) 2

(c) 3

(d) 6

## Answer

Answer: (c) 3

Hint:

m – 1 = 2 ⇒ m = 2 + 1 = 3.

Question 19.

The solution of the equation 2m = 4 is

(a) 1

(b) 2

(c) -1

(d) -2

## Answer

Answer: (b) 2

Hint:

2m = 4 ⇒ m = \(\frac{4}{2}\) = 2

Question 20.

The solution of the equation \(\frac { m }{ 3 } \) = 3 is

(a) 3

(b) 6

(c) 9

(d) 12

## Answer

Answer: (c) 9

Hint:

\(\frac{m}{3}\) = 3 ⇒ m = 3 × 3 = 9.

Question 21.

The solution of the equation = 6 is

(a) 6

(b) 7

(c) 14

(d) 3

## Answer

Answer: (c) 14

Hint:

\(\frac{3m}{7}\) = 6 ⇒ 3m = 7 × 6 = 42

⇒ m = \(\frac{42}{3}\) = 14

Question 22.

The solution of the equation 3p + 5 = 8 is

(a) -1

(b) 1

(c) 3

(d) 5

## Answer

Answer: (b) 1

Hint:

3p + 5 = 8 ⇒ 3p = 8 – 5 = 3

⇒ P = \(\frac{3}{3}\) = 1 4p – 2 = 10

Question 23.

The solution of the equation 4p – 2 = 10 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (c) 3

Hint:

4p – 2 = 10 ⇒ 4p = 10 + 2 = 12

⇒ p = \(\frac{12}{4}\) = 3.

Question 24.

The solution of the equation \(\frac { p }{ 2 } \) + 1 = 3 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (d) 4

Hint:

\(\frac{p}{2}\) + 1 = 3 ⇒ \(\frac{p}{2}\) = 3 – 1 = 2

p = 2 × 2 = 4

Question 25.

The solution of the equation 3 m + 7=16 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (c) 3

Hint:

3m + 7 = 16 ⇒ 3m = 16 – 7 = 9

⇒ m = \(\frac{9}{3}\) = 3

Question 26.

The solution of the equation 2p – 1 = 3 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (b) 2

Hint:

2p – 1 = 3 ⇒ 2p = 3 + 1 = 4

⇒ p = \(\frac{4}{2}\) = 2.

Question 27.

The solution of the equation 4x + 5 = 9 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (a) 1

Hint:

4x + 5 = 9 ⇒ 4x = 9 – 6 = 4

⇒ x = \(\frac{4}{4}\) = 1.

Question 28.

The solution of the equation 10 y – 20 = 30 is

(a) 1

(b) 2

(c) 3

(d) 5

## Answer

Answer: (d) 5

Hint:

10y – 20 = 30 ⇒ 10y = 30 + 20 = 50

⇒ y = \(\frac{50}{10}\) = 5.

Question 29.

The solution of the equation y – 4 = – 1 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (c) 3

Hint:

y – 4 = -1 ⇒ y = 4 – 1 = 3.

Question 30.

The solution of the equation y + 2 = -2 is

(a) 2

(b) -2

(c) 4

(d) -4

## Answer

Answer: (d) -4

Hint:

y + 2 = -2 ⇒ y = -2 – 2 = -4.

Question 31.

The solution of the equation 10t = -20 is

(a) 1

(b) -1

(c) 2

(d) -2

## Answer

Answer: (d) -2

Hint:

10t = -20 ⇒ t = –\(\frac{20}{10}\) = -2

Question 32.

The solution of the equation \(\frac { z }{ 2 } \) = \(\frac { 3 }{ 4 } \) is

(a) \(\frac { 1 }{ 2 } \)

(b) \(\frac { 3 }{ 2 } \)

(c) \(\frac { 1 }{ 4 } \)

(d) \(\frac { 3 }{ 4 } \)

## Answer

Answer: (b) \(\frac { 3 }{ 2 } \)

Hint:

\(\frac{z}{2}\) = \(\frac{3}{4}\) ⇒ z = \(\frac{3×2}{4}\) = \(\frac{3}{2}\)

Question 33.

The solution of the equation 2s = 0 is

(a) 2

(b) -2

(c) 0

(d) \(\frac { 1 }{ 2 } \)

## Answer

Answer: (c) 0

Hint:

2s = 0 ⇒ s = \(\frac{0}{2}\) = 0.

Question 34.

The solution of the equation – \(\frac { p }{ 7 } \) = 3 is

(a) -3

(b) -7

(c) -21

(d) 21

## Answer

Answer: (c) -21

Hint:

–\(\frac{p}{7}\) = 3 ⇒ -p = 3 × 7 = 21

⇒ p = -21

Question 35.

The solution of the equation 3s + 6 = 0 is

(a) 1

(b) -1

(c) 2

(d) -2

## Answer

Answer: (d) -2

Hint:

3s + 6 = 0

⇒ 3s = -6 ⇒ s = –\(\frac{6}{3}\) = -2.

Question 36.

The solution of the equation 10p = 10 is

(a) 1

(b) – 1

(c) 10

(d) – 10

## Answer

Answer: (a) 1

Hint:

10p = 10 ⇒ p = \(\frac{10}{10}\) = 1.

Question 37.

The solution of the equation 10p + 10 = 110 is

(a) 10

(b) -10

(c) 100

(d) 110

## Answer

Answer: (a) 10

Hint:

10p + 10 = 110

⇒ 10p = 110 – 10 = 100

⇒ p = \(\frac{100}{10}\) = 10.

Question 38.

The solution of the equation 12p – 11 = 13 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (b) 2

Hint:

12p – 11 = 13 ⇒ 12p = 13 + 11 = 24

⇒ p = \(\frac{24}{12}\) = 2.

Question 39.

The solution of the equation 2 (m + 3) = 8 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (a) 1

Hint:

2(m + 3) = 8 ⇒ m + 3 = \(\frac{8}{2}\) = 4

⇒ m = 4 – 3 = 1.

Question 40.

The solution of the equation – 2(x + 3) = 4 is

(a) -2

(b) -3

(c) -4

(d) -5

## Answer

Answer: (d) -5

Hint:

-2 (x + 3) = 4 ⇒ x + 3 = \(\frac{4}{-2}\) = -2

⇒ x = -2 – 3 = -5.

Question 41.

The solution of the equation \(\frac { 5 }{ 2 } \) x = 15 is

(a) 2

(b) 4

(c) 6

(d) 10

## Answer

Answer: (c) 6

Hint:

\(\frac{5}{2}\) x = 15 ⇒ x = \(\frac{15×2}{5}\) = 6

Question 42.

The solution of the equation 4(2 – x) = 4 is

(a) 1

(b) 2

(c) 3

(d) 4

## Answer

Answer: (a) 1

Hint:

4 (2 – x) = 4 ⇒ 2 – x = \(\frac{4}{4}\) = 1

⇒ x = 2 – 1 = 1.

Question 43.

The solution of the equation -4(2 + x) = 4 is

(a) -1

(b) -2

(c) -3

(d) -4

## Answer

Answer: (c) -3

Hint:

-4(2 + x) = 4 ⇒ 2 + x = \(\frac{4}{-4}\) = -1

⇒ x = -1 – 2 = -3.

Question 44.

The solution of the equation – 4 = 2 (p – 2) is

(a) 0

(b) 1

(c) 2

(d) 4

## Answer

Answer: (a) 0

Hint:

-4 = 2(p – 2) ⇒ p – 2 = –\(\frac{4}{2}\) = -2

⇒ p = -2 + 2 = 0.

Question 45.

The solution of the equation 0 = 4 + 4(m + 1) is

(a) 1

(b) -1

(c) 2

(d) -2

## Answer

Answer: (d) -2

Hint:

0 = 4 + 4 (m + 1)

⇒ 4(m + 1) = -4 ⇒ m + 1 = –\(\frac{4}{4}\) = -1

m = -1 – 1 = -2.

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