NCERT Exemplar Solutions for Class 9 Science Chapter 16 Floatation
These Solutions are part of NCERT Exemplar Solutions for Class 9 Science . Here we have given NCERT Exemplar Solutions for Class 9 Science Chapter 16 Floatation
MULTIPLE CHOICE QUESTIONS
An object is put one by one in three liquids having different densities. The object floats with 1/9, 2/11 and 3/7 parts of their volumes outside the liquid surface in liquids of densities d1, d2 and d3 respectively. Which of the following statement is correct ?
(a) d1 > d2 > d3
(b) d1 > d2 < d3
(c) d1 < d2 > d3
(d) d1 < d2 < d3
(d). Upthrust due to liquid on an object is directly proportional to the density of the liquid.
- NCERT Exemplar Solutions for Class 9 Science
- NCERT Solutions for Class 9 Science
- Value Based Questions in Science for Class 9
- HOTS Questions for Class 9 Science
- Previous Year Question Papers for CBSE Class 9 Science
An obj ect weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be
(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N.
(a). Explanation : Weight of liquid displaced by an object = Weight of object in air – weight in liquid.
A girl stands on a box having 60 cm length, 40 cm breadth and 20 cm width in three ways. In which of the following cases, pressure exerted by the brick will be
(a) maximum when length and breadth form the base
(b) maximum when breadth and width form the base
(c) maximum when width and length form the base
(d) the same in all the above three cases.
(b). Explanation :
SHORT ANSWER QUESTIONS
(a) A cube of side 5 cm is immersed in water and then in saturated salt solution. In which case will it experience a greater buoyant force.
If each side of the cube is reduced to 4 cm and then immersed in water, what will be the effect on the buoyant force experienced by the cubeas compared to the first case for water. Give reason for each case. (CBSE 2012)
(b) A ball weighing 4 kg of density 4000 kg m-3 is completely immersed in water of density 103 kg m-3. Find the force of buoyancy on it. (Given g = 10 ms-2.)
(a) Buoyant force = Vρg. Since, density (ρ) of saturated salt solution is more than that of water. So, the cube will experience greater buoyant force in saturated salt solution. When size of cube is reduced, its volume (V) also reduces. Hence, it will experience less buoyant force then in first case.
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