NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2.

- Practical Geometry Class 7 Ex 10.1
- Practical Geometry Class 7 Ex 10.3
- Practical Geometry Class 7 Ex 10.4
- Practical Geometry Class 7 Ex 10.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 10 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 10.2 |

Number of Questions Solved |
4 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2

**Question 1.**

Construct A XYZ in which XY = 4.5 cm, YZ = 5 cm and, ZX = 6 cm.

**Solution:**

**Steps of Construction**

- Draw a line segment YZ of length 5 cm.

- With Y as centre, draw an arc of radius 4.5 cm.
- With Z as centre, draw an arc of radius 6 cm,
- Mark the point of intersection of arcs as X.
- Join XY and XZ. ∆ XYZ is now ready.

**Question 2.**

Construct an equilateral triangle of side 5.5 cm.

**Solution:**

**Steps of Construction:**

- Draw a line segment BC of length 5.5 cm.
- With B as centre, draw an arc of radius 5.5 cm.

- With C as centre, draw an arc of radius 5.5 cm.
- Mark the point of intersection of arcs as A.
- Join AB and AC. Equilateral ∆ ABC is now ready.

**Question 3.**

Draw ∆ PQR with PQ = 4 cm, QR =3.5 cm and PR = 4 cm. What type of triangle is this?

**Solution:**

**Steps of Construction:**

- Draw a line segment QR of length 3.5 cm.
- With Q as centre, draw an arc of radius 4 cm.
- With R as centre, draw an arc of radius 4 cm.

- Mark the point of intersection of arcs as P.
- Join PQ and PR.

∆ PQR is now ready,

∵ PQ = PR

∴ ∆ PQR is isosceles.

**Question 4.**

Construct ∆ ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

**Solution:**

**Steps of Construction**

- Draw a line segment BC of length 6 cm.

- With B as centre, draw an arc of radius 2.5 cm.
- With C as centre, draw an arc of a radius of 6.5 cm.
- Mark the point of intersection of arcs as A.
- Join AB and AC.
- ∆ ABC is now ready. On measurement, ∠B = 90°.

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