NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5.
- Practical Geometry Class 7 Ex 10.1
- Practical Geometry Class 7 Ex 10.2
- Practical Geometry Class 7 Ex 10.3
- Practical Geometry Class 7 Ex 10.4
| Board | CBSE |
| Textbook | NCERT |
| Class | Class 7 |
| Subject | Maths |
| Chapter | Chapter 10 |
| Chapter Name | Practical Geometry |
| Exercise | Ex 10.5 |
| Number of Questions Solved | 3 |
| Category | NCERT Solutions |
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5
Question 1.
Construct the right-angled ∆ PQR where m ∠Q = 90°, QR = 8 cm and PR = 10 cm.
Solution:
Steps of Construction:
- Draw QR of length 8 cm.
- At Q, draw QX ⊥ QR.
- With R as centre, draw an arc of radius 10 cm.
- Mark the meeting point of these two as P.
∆ PQR is now obtained.
Question 2.
Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.
Solution:
Steps of Construction
- Draw QR of length 4 cm.
- At Q, draw QX ⊥ QR.
- With R as centre, draw an arc of radius 6 cm.
- Mark the meeting point of arc and QX as P.
∆ PQR is now obtained.
Question 3.
Construct an isosceles right-angled triangle ABC where m ∠ACB = 90° and AC = 6 cm.
Solution:
Steps of Construction
- Draw AC of length 6 cm.
- At C, draw CX ⊥ CA.
- With C as centre, draw an arc of radius 6 cm to intersect CX at B.
- Join AB. ∆ACB is now obtained.
We hope the NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 help you. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry EX 10.5, drop a comment below and we will get back to you at the earliest.