NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2.

- Practical Geometry Class 8 Ex 4.1
- Practical Geometry Class 8 Ex 4.3
- Practical Geometry Class 8 Ex 4.4
- Practical Geometry Class 8 Ex 4.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 4.2 |

Number of Questions Solved |
1 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2

**Question 1.**

**Construct the following quadrilaterals:**

**(i) Quadrilateral LIFT**

LI = 4 cm

IF = 3 cm

TL = 2.5 cm

LF = 4.5 cm

IT = 4 cm

**(ii) Quadrilateral GOLD**

OL = 7.5 cm

GL = 6 cm

GD = 6 cm

LD = 5 cm

OD = 10 cm

**(iii) Rhombus BEND**

BN – 5.6 cm

DE = 6.5 cm

**Solution.**

**(i) Steps of Construction**

- Draw LI = 4 cm.
- With L as center and radius LT = 2.5 cm, draw an arc.

- With I as center and radius, IT = 4 cm, draw another arc to intersect the arc drawn in step 2 at T.
- With I as center and radius IF = 3 cm, draw an arc.
- With L as center and radius LF = 4.5 cm, draw another arc to intersect the arc drawn in step 4 at F.
- Join IF, FT, TL, LF and IT.

Then, LIFT is the required quadrilateral.

**(ii) Steps of Construction**

- Draw LD = 5 cm.
- With L as center and radius LG = 6 cm, draw an arc.

- With D as center and radius DG = 6 cm, draw another arc to intersect the arc drawn in step 2 at G.
- With L as center and radius LO = 7.5 cm, draw an arc.
- With D as center and radius DO = 10 cm, draw another arc to intersect the arc drawn in step 4 at O.
- Join DG, GO, OL, LG and DO.

Then GOLD is the required quadrilateral.

**(iii) Steps of Construction**

- Draw DE = 6.5 cm.
- Draw perpendicular bisector PQ of DE so as to intersect DE at M. Then M is the mid-point of DE.
- With M as centre and radius

\(=\frac { 1 }{ 2 } \times \left( 5.6 \right) =2.8 cm\)

opposite sides of DE to intersect MP at N and MQ at B.

- Join DN, NE, EB, and BD.

Then, BEND is the required rhombus.

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