NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3.

- Practical Geometry Class 8 Ex 4.1
- Practical Geometry Class 8 Ex 4.2
- Practical Geometry Class 8 Ex 4.4
- Practical Geometry Class 8 Ex 4.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 4.3 |

Number of Questions Solved |
1 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3

**Question 1.**

**Construct the following quadrilaterals :**

**(i) Quadrilateral MORE**

MO = 6 cm

OR = 4.5 cm

∠M = 60°

∠O = 105°

∠R = 105°

**(ii) Quadrilateral PLAN**

PL = 4 cm

LA = 6.5 cm

∠P = 90°

∠A = 110°

∠N – 85°.

**(iii) Parallelogram HEAR**

HE = 5 cm

EA = 6 cm

∠R = 85°

**(iv) Rectangle OKAY**

OK = 7 cm

KA = 5 cm.

**Solution.**

**(i) Steps of Construction**

- Draw MO = 6 cm.
- At 0, draw ray OX such that Z MOX = 105°.

- Cut OR = 4.5 cm from ray OX.
- At M, draw ray MY such that ∠OMY = 60°.
- At R, draw ray RZ such that ∠ORZ = 105°.
- Let the rays MY and RZ meet at E.

Then, MORE is the required quadrilateral.

**(ii) Steps of Construction**

- Draw PL = 4 cm.
- At L, draw ray LX such that ∠PLX = 75°.

By Angle-sum property of a quadrilateral,

∠P + ∠A + ∠N + ∠L = 360°

⇒ 90° + 110° + 85° + Z L = 360°

⇒ 285° + ∠ L = 360°

⇒ ∠L = 360° – 285°

⇒ ∠L = 75°. - Cut LA = 6.5 cm from ray LX.
- At A, draw ray AY such that ∠LAY = 110°.
- At P, draw ray PZ such that ∠LPZ = 90°.

Let the rays AY and PZ meet at N.

Then, PLAN is the required quadrilateral.

**(iii) Steps of Construction**

- Draw HE = 5 cm.
- At E, draw ray EX such that ∠HEX = 85°

∴ Opposite angles of a parallelogram are equal.

∵ ∠E = ∠R = 85° - Cut EA = 6 cm from the ray EX.

- With A as centre and radius AR = 5 cm, draw an arc.
- With H as centre and radius HR = 6 cm; draw another arc to intersect the arc drawn in step 4 at R.

∴ opposite sides of a parallelogram are equal in length

∵ AR = EH = 5 cm

and HR = EA = 6 cm - Join AR and HR.

Then, HEAR is the required parallelogram.

**(iv) Steps of Construction**

[We know that each angle of a rectangle

is 90°.

∴ ∠O=∠K=∠A=∠Y= 90°.

Also, opposite sides of a rectangle are equal in length.

∴ OY = KA = 5 cm and AY = KO = 7 cm]

- Draw OK = 7 cm.
- At K, draw ray KX such that ∠OKX = 90°.
- Cut KA – 5 cm from ray KX.

- Taking A as centre and radius AY = 7 cm, draw an arc.
- Taking O as centre and radius OY = 5 cm, draw another arc to intersect the arc drawn in step 4 at Y.
- Join AY and OY.

Then OKAY is the required rectangle.

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