NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.3 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.3.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 5 |

Chapter Name |
Data Handling |

Exercise |
Ex 5.3 |

Number of Questions Solved |
6 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.3

**Question 1.**

List the outcomes you can see in these experiments.

**(a)** Spinning a wheel

**(b)** Tossing two coins together

**Solution.**

**(a)** Outcomes in spinning the given wheel are A, B, C and D.

**(b)** Outcomes in tossing two coins together are HT, HH, TH, TT (Here HT means Head on first coin and Tail on the second coin and so on).

**Question 2.**

When a die is thrown, list the outcomes of an event of getting

**(i)**

**(a)** a prime number

**(b)** not a prime number

**(ii)**

**(a)** a number greater than 5

**(b)** a number not greater than 5.

**Solution.**

Possible outcomes are:

1, 2, 3, 4, 5, and 6.

Out of these, prime numbers are

2, 3 and 5.

**(i)**

**(a)** Outcomes of an event of getting a prime number are: 2, 3 and 5

**(b)** Outcomes of an event of not getting a prime number are 1, 4 and 6.

**(ii)**

**(a)** Outcomes of an event of getting a number greater than 5 are 6

**(b)** Outcomes of an event of getting a; number not greater than 5 are 1, 2, 3, 4 and 5.

**Question 3.**

Find the

**(a)** Probability of the pointer stopping on D in (Question l-(a))?

**(b)** Probability of getting an ace from a j well shuffled deck of 52 playing cards?

**(c)** Probability of getting a red apple. (See figure)

**Solution.**

**(a)** There are in all 5 outcomes of the event. These are A, B, C and D. The pointer stopping on D has only 1 outcome, i.e., D

∴ Probability of the pointer stopping on D =\(\frac { 1 }{ 5 } \)

**(b)** Total number of playing cards = 52 Number of possible outcomes = 52

Number of aces in a deck of playing cards = 4

cards = 4

∴ Probability of getting an ace from a well shuffled deck of 52

playing cards = \(\frac { 4 }{ 52 } \) = \(\frac { 1 }{ 13 } \)

**(c)** Total number of apples = 7

Number of red apples = 4

∴ Probability of getting a red apple = \(\frac { 4 }{7} \)

**Question 4.**

Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of?

**(i)** getting a number 6?

**(ii)** getting a number less than 6?

**(iii)** getting a number greater than 6?

**(iv)** getting a 1-digit number?

**Solution.**

Total number of outcomes of the event (1, 2, 3, 4, 5, 6, 7, 8, 9 and 10) = 10

**(i)**

∵ Number of outcomes of getting a number 6=1

∴ Probability of getting a number \(\frac { 1 }{10} \)

**(ii)**

∵ There are 5 numbers (1, 2, 3, 4 and 5) less than 6.

∴ Number of outcomes of getting a number less than 6 = 5

∴ Probability of getting a number less than \(6=\frac { 5 }{ 10 } =\frac { 1 }{ 2 } \)

**(iii)**

∵ There are 4 numbers (7, 8, 9 and 10) greater than 6

∴ Number of outcomes of getting a number greater than 6 = 4

∴ Probability of getting a number greater than \(6=\frac { 4 }{ 10 } =\frac { 2}{ 15 } \)

**(iv)**

∵ There are 9 1-digit numbers (1, 2, 3, 4, 5, 6, 7, 8 and 9)

∴ Number of outcomes of getting a 1-digit number = 9

∴ Probability of getting a 1-digit number \(=\frac { 9 }{ 10 } \)

**Question 5.**

If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a nonblue sector?

**Solution.**

Number of green sectors = 3

Number of blue sectors = 1

Number of red sectors = 1

∴ Total number of sectors = 3 + 1 + 1=5

∴ Total number of outcomes of the event = 5

Number of outcomes of getting a green sector = 3

∴ Probability of getting a green sector = \(\frac { 3 }{ 5 } \)

Number of outcomes of getting a non-blue sector = Number of green sectors + Number of red sectors

=3+1=4

∴ Probability of getting a non-blue sector = \(\frac { 4 }{ 5 } \).

**Question 6.**

Find the probabilities of the events given in Question 2.

**Solution.**

Total number of outcomes of the event (1, 2, 3, 4, 5 and 6) = 6

**(i)**

**(a)** Number of prime numbers (2, 3 and 5) = 3

∴ Number of outcomes of getting a prime number = 3

∴ Probability of getting a prime number = \(\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \).

**(b)** Number of non-prime numbers (1, 4 and 6) = 3

∴ Number of outcomes of getting a non-prime number = 3

∴ Probability of getting a non-prime number = \(\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \).

**(ii)**

**(a)** Number greater than 5 = 6, i.e., only one.

∴ Number of outcomes of getting a number greater than 5 = 1

∴ Probability of getting a number greater than 5 = \(\frac { 1 }{ 6 } \).

**(b)** Number of numbers not greater than 5 (1, 2, 3, 4 and 5) = 5

∴ Number of outcomes of getting a number not greater than 5 = 5

∴ Probability of getting a number not greater than 5 = \(\frac { 5 }{ 6 } \).

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