RD Sharma Class 9 Solutions Chapter 4 Algebraic Identities VSAQS

RD Sharma Class 9 Solutions Chapter 4 Algebraic Identities VSAQS

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 4 Algebraic Identities VSAQS

Question 1.

Solution:

Question 2.

Solution:

Question 3.
If a + b = 7 and ab = 12, find the value of a² + b².
Solution:
a + b = 7, ab = 12
Squaring both sides,
(a + b)² = (7)²
⇒  a² + b² + 2ab = 49
⇒  a² + b² + 2 x 12 = 49
⇒ a² + b² + 24 = 49
⇒ a² + b² = 49 – 24 = 25
∴ a² + b² = 25

Question 4.
If a – b = 5 and ab = 12, find the value of a² + b² .
Solution:
a – b = 5, ab = 12
Squaring both sides,
⇒ (a – b)² = (5)²
⇒  a² + b² – 2ab = 25
⇒  a² + b² – 2 x 12 = 25
⇒  a² + b² – 24 = 25
⇒  a² + b² = 25 + 24 = 49
∴ a² + b² = 49

Question 5.

Solution:

Question 6.

Solution:

Question 7.

Solution:

Hope given RD Sharma Class 9 Solutions Chapter 4 Algebraic Identities VSAQS are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.