NCERT Maths Solutions for Ex 2.2 class 10 Polynomials is the perfect guide to boost up your preparation during CBSE 10th Class Maths Examination.

RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B. You must go through NCERT Solutions for Class 10 Maths to get better score in CBSE Board exams along with RS Aggarwal Class 10 Solutions.

Question 1.
Solution:
Zeros are 3, -2, 1 of
p(x) = x3 – 2x2 – 5x + 6
Here, a = 1, b = -2, c = -5, d = 6
We know that if α, β and γ are the roots of
f(x) = ax3 + bx2 + cx + d, then
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 1

Question 2.
Solution:
Zeros are 5, -2 and \(\frac { 1 }{ 3 }\) of
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 2

Question 3.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 3

Question 4.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 4
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 5

Question 5.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 6

Find the quotient and the remainder when:
Question 6.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 7

Question 7.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 8

Question 8.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 9

Question 9.
Solution:
f(x) = 2x4 + 3x3 – 2x2 – 9x – 12
g(x) = x2 – 3
Quotient [q(x)] = 2x2 + 3x + 4
Remainder [r(x)] = 0
Remainder is zero.
x2 – 3 is a factor of f(x)
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 10

Question 10.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 11

Question 11.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 12

Question 12.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 13
= (x + 1) (x + 4) (x – 3)
If x + 4 = 0, then x = -4
If x – 3 = 0, then x = 3
Zeros are -1, -4, 3

Question 13.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 14

Question 14.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 15
=> (x – 3) (x + 3) [x (x + 2) – 1 (x + 2)]
=> (x – 3) (x + 3) (x + 2) (x – 1)
Other zeros will be
If x + 2 = 0 then x = -2
and if x – 1 =0, then x = 1
Zeros are 3, -3, -2, 1

Question 15.
Solution:
2 and -2 are the two zeros of the polynomial
f(x) = x4 + x3 – 34x2 – 4x + 120,
Then (x – 2) (x + 2) or x2 – 4 will its the factor of f(x)
Now dividing f(x) by x2 – 4, we get
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 16
f(x) = (x – 2) (x + 2) (x2 + x – 30)
= (x – 2)(x + 2)[x2 + 6x – 5x – 30]
= (x – 2) (x + 2)[x(x + 6) – 5(x + 6)]
= (x – 2) (x + 2) (x + 6) (x – 5)
Other two zeros are
If x + 6 = 0, then x = -6 and
if x – 5 = 0, then x = 5
Roots of f(x) are 2, -2, -6, 5

Question 16.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 17
Other two zeros are :
if x + 5 = 0, then x = -5
and if x – 4 = 0, then x = 4
Hence, all the zeros of f(x) are : √3, – √3, 4, -5

Question 17.
Solution:
√3 and – √3 are the zeros of the polynomial
f(x) = 2x4 – 3x3 – 5x2 + 9x – 3
=> (x – √3) (x + √3) or (x2 – 3) is a factor of f(x)
Now, dividing f(x) by x2 – 3, we get
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 18

Question 18.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 19
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 20

Question 19.
Solution:
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 21
RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2B 22

Hope given RS Aggarwal Solutions Class 10 Chapter 2 Polynomials Ex 2B are helpful to complete your math homework.

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