RS Aggarwal Class 6 Solutions Chapter 10 Ratio, Proportion and Unitary Method Ex 10D

RS Aggarwal Class 6 Solutions Chapter 10 Ratio, Proportion and Unitary Method Ex 10D

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10D.

Other Exercises

• RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10A
• RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10B
• RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10C
• RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10D

OBJECTIVE QUESTIONS
Mark against the correct answer in each of the following :

Question 1
Solution:
(d) \(\\ \frac { 92 }{ 115 } \)

Question 2.
Solution:
(a) \(\\ \frac { 57 }{ x } \)
= \(\\ \frac { 51 }{ 85 } \)

Question 3.
Solution:
(a) \(\\ \frac { 25 }{ 35 } \)
= \(\\ \frac { 45 }{ x } \)

Question 4.
Solution:
(c) \(\\ \frac { 4 }{ 5 } \)
= \(\\ \frac { x }{ 35 } \)

Question 5.
Solution:
(b) \(\\ \frac { a }{ b } \)
= \(\\ \frac { c }{ d } \)
=>ad = bc

Question 6.
Solution:
(b) a : b :: b : c

Question 7.
Solution:
(b) \(\\ \frac { 5 }{ 8 } \) < \(\\ \frac { 3 }{ 4 } \) => 4 x 5 < 3 x 8 => 20 < 24

Question 8.
Solution:
Total amount = Rs 760
Ratio A : B = 8 : 11

Question 9.
Solution:
(d) largest = \(\\ \frac { 252\times 7 }{ 5+7 } \)
= \(\\ \frac { 252\times 7 }{ 12 } \)
= 21 x 7
= 147

Question 10.
Solution:
(b) largest = \(\\ \frac { 90\times 5 }{ 1+3+5 } \)
= \(\\ \frac { 90\times 5 }{ 9 } \)
= 50 cm

Question 11.
Solution:
(c) total strength of school
largest = \(\\ \frac { 840 }{ 5 } \) x (12 + 5)
= \(\\ \frac { 840\times 17 }{ 5 } \)
= 168 x 17
= 2856

Question 12.
Solution:
(b) Cost of 12 pens = Rs 138
Cost of 1 pen = Rs \(\\ \frac { 138\times 14 }{ 12 } \)
and cost of 14 pens = Rs 161

Question 13.
Solution:
(b) \(\\ \frac { 24\times 15 }{ 8 } \)
= 45 days

Question 14.
Solution:
(a) \(\\ \frac { 26\times 40 }{ 20 } \)
= 52 men

Question 15.
Solution:
(b) In 6 L of petrol, a car covers = 111 km
In 1 L, it will cover = \(\\ \frac { 111 }{ 6 } \) km
and in 10 L it will cover = \(\\ \frac { 111\times 10 }{ 6 } \) km
= 185 km

Question 16.
Solution:
(a) \(\\ \frac { 28\times 550 }{ 700 } \)
= 22 days

Question 17.
Solution:
Ratio in the angles of triangle
= 3 : 1 : 2

Question 18.
Solution:
(b) Ratio in length and breadth of a rectangle = 5 : 4
Width = 36 m
Length = \(\\ \frac { 5 }{ 4 } \) x 36 m
= 45m

Question 19.
Solution:
Bus covers in 3 hrs = 195 km
It will cover in 1 hr = \(\\ \frac { 195 }{ 3 } \) = 65 km

Question 20.
Solution:
1 dozen = 12 bars
Cost of 5 bars of soap = Rs.82.50

Question 21.
Solution:
Total pencils in 30 packets of 8 pencils
= 30 x 8= 240
and total pencils of 25 packets of 12
pencils = 25 x 12 = 300
Now cost of 240 pencils = Rs. 600
Then cost of 1 percent = Rs. \(\\ \frac { 600 }{ 24 } \)
and cost of 300 pencils = Rs. \(\\ \frac { 600\times 300 }{ 240 } \)
= Rs 750 (b)

Question 22.
Solution:
Journey of 75 km costs = Rs 215
Cost of 1 km = Rs \(\\ \frac { 215 }{ 75 } \)

Question 23.
Solution:
1st term = 12
2nd term = 21
fourth term = 14

Question 24.
Solution:
10 boys dig a patch in = 12 hrs
1 boy will dig it in = 12 x 10 hours

Hope given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10D are helpful to complete your math homework.

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