## RS Aggarwal Class 6 Solutions Chapter 10 Ratio, Proportion and Unitary Method Ex 10C

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10C.

Other Exercises

Question 1.
Solution:
Cost of 14 m of cloth = Rs. 1890
Cost of 1 m = Rs. $$\\ \frac { 1890 }{ 14 }$$
and cost of 6 m = Rs. $$\\ \frac { 1890\times 6 }{ 14 }$$
= Rs. 135 x 6
= Rs. 810

Question 2.
Solution:
Cost of 1 dozen or 12 soaps = Rs. 285.60
Cost of 1 soap = Rs. $$\\ \frac { 285.60 }{ 12 }$$
Cost of 15 soaps = Rs. $$\\ \frac { 285.60\times 15 }{ 12 }$$
= Rs. 357.00

Question 3.
Solution:
Cost of 9 kg of rice = Rs. 327.60
Cost of 1 kg = Rs. $$\\ \frac { 327.60 }{ 9 }$$
and cost of 50 kg = Rs. $$\\ \frac { 327.60\times 50 }{ 9 }$$
= Rs. 36.40 x 50
= Rs. 1820

Question 4.
Solution:
Weight of 22.5 metres of the iron rod: = 85.5 kg
Weight of 1 metre of the iron rod Question 5.
Solution:
Quantity of oil in 15 tins = 234 kg
Quantity of oil in 1 tin = $$\\ \frac { 234 }{ 15 }$$ kg
Quantity of oil in 10 tins Question 6.
Solution:
Distance covered by the car in 12 litres of diesel = 222 kms
Distance covered by the car in 1 litre of diesel = $$\\ \frac { 222 }{ 12 }$$ km Question 7.
Solution:
Charges of 25 tonnes of weight = Rs. 540
charges of 1 ton = Rs.$$\\ \frac { 540 }{ 25 }$$ Question 8.
Solution:
Weight of copper in 4.5 g of alloy = 3.5g
Weight of copper in 1 g of alloy Question 9.
Solution:
In Rs. 87.50, the inland letter are purchased = 35
In Re. 1, letters can be purchased
= $$\\ \frac { 35 }{ 87.50 }$$
and in Rs. 315, letters can be purchased Question 10.
Solution:
4 dozen = 4 x 12 = 48 bananas
In Rs. 104, banana are purchased = 48 Question 11.
Solution:
In Rs. 22770, chairs are purchased =18
In Re. 1, chairs will be purchased
= $$\\ \frac { 18 }{ 22770 }$$
and in Rs. 10120, chairs will be
purchased = $$\\ \frac { 18\times 10120 }{ 22770 }$$
= 8

Question 12.
Solution:
(i) A car travels 195 km distance in = 3 hours
It will travel 1 km distance in = $$\\ \frac { 3 }{ 195 }$$ hr.
and it will travel 520 km distance in
= $$\\ \frac { 3\times 520 }{ 195 }$$
= 8 hr
(ii) A car travels in 3hr = 195 km Question 13.
Solution:
(i) A laborer earn in 12 days = Rs. 1980
He will earn in 1 day = Rs. $$\\ \frac { 1980 }{ 12 }$$
and he will earn in 7 days Question 14.
Solution:
(i) Weight of 65 books = 13 kg
Then weight of 1 book = $$\\ \frac { 13 }{ 65 }$$ kg Question 15.
Solution:
Number of boxes needed for 6000 pens = 48
Number of boxes needed for 1 pen 48 = $$\\ \frac { 48 }{ 6000 }$$ Question 16.
Solution:
Clearly, less workers will build the wall in more days.
And, more workers will build the wall in less days.
24 workers can build the wall in 15 days
1 worker can build the wall in (15 x 24) days
(less worker, more days)
9 workers will build the wall in Question 17.
Solution:
Men needed to finish a piece of work in 26 days = 40
Men needed to finish a piece of work in 1 day = 40 x 26 (less days, more men) Question 18.
Solution:
Clearly, less men will take more days to consume the food.
And, more men will take less days to consume the food.
550 men have provisions for 28 days
1 men has provisions for (28 x 550) days [less men, more days]
700 men will have provisions for Question 19.
Solution:
Clearly, less persons will consume the rice in more days.
And more persons will consume the rice in less days.
60 persons consume the bag of rice in 3 days.
1 person will consume the bag of rice in
(3 x 60) days (less persons, more days)
18 persons will consume the bag of rice Hope given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10C are helpful to complete your math homework.

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