## RS Aggarwal Class 6 Solutions Chapter 3 Whole Numbers Ex 3B

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3B.

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3A
- RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3B
- RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3C
- RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3D
- RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3E
- RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3F

**Question 1.**

**Solution:**

(i) 458 + 639 = 639 + 458 (Commulative law)

(ii) 864 + 2006 = 2006 + 864 (Commulative law)

(iii) 1946 + 984 = 984 + 1946 (Commulative law)

(iv) 8063 + 0 = 8063 (Additive property of zero)

(v) 53501 + (574 + 799) = 574 + (53501 + 799) (Associative law)

**Question 2.**

**Solution:**

(i) 16509 + 114 = 16623

Check : 16623 – 114 = 16509 which is given.

(ii) 2359 + 548 = 2907

Check: 2907 – 2359 = 548 which is given

(iii) 19753 + 2867 = 22620

Check : 22620 – 19753 = 2867 which is given

**Question 3.**

**Solution:**

(1546 + 498) + 3589

= 2044 + 3589

= 5633

and 1546 + (498 + 3589)

= 1546 + 4087

= 5633

Yes, the above two sum are equal.

The property used is associative law of addition.

**Question 4.**

**Solution:**

(i) 953 + 707 + 647

= (953 + 647) + 707

(by associative law)

= 1600 + 707

= 2307

(ii) 1983 + 647 + 217 + 353

= (1983 + 217) + (647 + 353)

= 2200 + 1000 = 3200

(iii) 15409 + 278 + 691 + 422

= (15409 + 691) + (278 + 422)

(by associative law)

= 16100 + 700

= 16800

(iv) 3259 + 10001 + 2641 + 9999

= (3259 + 2641) + (10001 + 9999)

(by associative law)

= 5900 + 20000

= 25900

(v) 1 +2 + 3 +4 + 96 + 97 + 98 + 99

= (1 +99) + (2 + 98) + (3 + 97) + (4 + 96)

= (100+ 100) + (100 +100)

= 200 + 200

= 400

(vi) 2 + 3 + 4 + 5 + 45 + 46 + 47 + 48

= (2 + 48) + (3 + 47) + (4 + 46) + (5 + 45)

= (50 + 50) + (50 + 50)

= 100 + 100 = 209

**Question 5.**

**Solution:**

(i) 6784 + 9999 = (6784 – 1) + (9999 + 1)

(Adding and subtracting 1)

= 6783 + 10000

= 16783

(ii) 10578 + 99999

(Adding and subtracting 1)

= (10578 – 1) + (99999 + 1)

= 10577 + 100000

= 110577

**Question 6.**

**Solution:**

Yes it is true, by the property of associative law of addition.

**Question 7.**

**Solution:**

The magic squares given are completed as under:

In each row/column, the sum = 46

**Question 8.**

**Solution:**

(i) The sum of two odd numbers is an odd number (F)

As sum of two odd numbers is alway an even number

(ii) The sum of two even number is an even number (T)

(iii) The sum of an even number and an odd number is an odd number (T)

Hope given RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3B are helpful to complete your math homework.

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