## RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6B

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6B.

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6A
- RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6B

**OBJECTIVE QUESTIONS**

**Mark against the correct answer in each of the following :**

**Question 1.**

**Solution:**

(c) 8 + 4 ÷ 2 x 5

= 8 + 4 x \(\\ \frac { 1 }{ 2 } \) x 5

= 8 + 10

= 18.

**Question 2.**

**Solution:**

(b) 54 ÷ 3 of 6 + 9 = 54 ÷ 18 + 9

= 54 x \(\\ \frac { 1 }{ 18 } \) + 9

= 3 + 9

= 12.

**Question 3.**

**Solution:**

(b) 13 – (12 – 6 ÷ 3)

= 13 – (12 – 2)

= 13 – 10

= 3

**Question 4.**

**Solution:**

(a) 1001 ÷ 11 of 13

= 1001 ÷ 143

= 1001 x \(\\ \frac { 1 }{ 143 } \)

= 7.

**Question 5.**

**Solution:**

(b) 133 + 28 ÷ 7 – 8 x 2

= 133 + 4 – 16

= 137 – 16

= 121.

**Question 6.**

**Solution:**

(a) 3640 – 14 ÷ 7 x 2

= 3640 – 2 x 2

= 3640 – 4

= 3636.

**Question 7.**

**Solution:**

(b) 100 x 10 – 100 + 2000 ÷ 100

= 1000 – 100 + 20

= 920.

**Question 8.**

**Solution:**

(b) \(27-\left[ 18-\left\{ 16-\left( 5-\overline { 4-1 } \right) \right\} \right] \)

= 27 – [18 – {16 – (5 – 4 + 1)}]

= 27 – [18 – {16 – 5 + 4 – 1}]

= 27 – [18 – 16 + 5 – 4 + 1]

= 27 – 18 + 16 – 5 + 4 – 1

= 23

**Question 9.**

**Solution:**

\(32-\left[ 48\div \left\{ 36-\left( 27-\overline { 16-9 } \right) \right\} \right] \)

= 32 – [48 ÷ {36 – (27 – 16 + 9)}]

= 32 – [48 ÷ {36 – 27 + 16 – 9}]

= 32 – [48 ÷ 16]

= 32 – 3

= 29

**Question 10.**

**Solution:**

(a) 8 – [28 ÷ {34 – (36 – 18 ÷ 9 x 8)}]

\(8-\left[ 28\div \left\{ 34-\left( 36-18\times \frac { 1 }{ 9 } \times 8 \right) \right\} \right] \)

= 8 – [28 ÷ {34 – (36 – 16)}]

= 8 – [28 ÷ {34 – 20}]

= 8 – {28 ÷ 14}

= 8 – 2

= 6.

Hope given RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6B are helpful to complete your math homework.

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