## RS Aggarwal Class 7 Solutions Chapter 1 Integers CCE Test Paper

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 1 Integers CCE Test Paper.

**Other Exercises**

- RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1A
- RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1B
- RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1C
- RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1D
- RS Aggarwal Solutions Class 7 Chapter 1 Integers CCE Test Paper

**Question 1.
**

**Solution:**

Let the other integer be a. Then, we have;

a + (-12) = 43

⇒ a = 43 – (-12) = 55

Hence, the other integer is 55.

**Question 2.**

**Solution:**

p – (-8) = 3

⇒ p = 3 + (-8)

⇒ p = -5

Hence, the value of p is -5.

**Question 3.**

**Solution:**

Product of (-16) and (-9) = (-16) x (-9) = 144

Now, (-132) ÷ 6 gives the quotient -22.

144 + (-22) = 122

**Question 4.**

**Solution:**

Suppose that a divides -240 to obtain 16. Then, we have:

(-240) ÷ a =16

⇒ a = (-240) ÷ 16 = -15

Hence, -15 should divide -240 to obtain 16.

**Question 5.**

**Solution:**

Let a be divided by (-7) to obtain 12. Then, we have:

a ÷ (-7) = 12

a = \(\frac { -7 }{ 12 }\)

Hence, \(\frac { -7 }{ 12 }\) should be divided by -7 to obtain 12.

**Question 6.**

**Solution:**

(i) -450

(ii) 360

(iii) -1080

(iv) -600

(v) (-5)5 = -3125

(vi) (-1)25 = -1

**Question 7.**

**Solution:**

(i) (-16) x 12 + (-16) x 8 = (-16) x (12 + 8) [Associative property]

= (-16) x 20

= -320

(ii) 25 x (-33) + 25 x (-17)

= 25 x [(-33) + (-17)] [Associative property]

= 25 x (-50)

= -1250

(iii) (-19) x (-25) + (-19) x (-15)

= (-19) x [(-25) + (-15)] [Associative property]

= (-19) x (-40)

= 760

(iv) (-47) x 68 – (-47) x 38

= (-47) x (68 – 38) [Asssociative property]

= (-47) x 30

= -1410

(v) (-105) ÷ 21

(-105) ÷ 21 = -5

(vi) (-168) ÷ (-14) = 12

(vii) 0 ÷ (-34)

= 0 (zero).

Dividing 0 by any integer gives 0.

(viii) 37 ÷ 0

Not defined.

Dividing any integer by zero is not defined.

**Mark (√) against the correct answer in each of the following:**

**Question 8.**

**Solution:**

(d) -8

Let the other integer be a. Then, we have:

2 + a = -6

⇒ a = -6 – 2 = -8

⇒ The other integer is -8.

**Question 9.**

**Solution:**

(b) 8

Suppose that a is subtracted from (-7). Then, we have

-7 – a = -15

a = -7 + 15 = 8

8 must be subtracted from -7 to obtain-15.

**Question 10.**

**Solution:**

(b) 108

(108) + (-18) = -6

**Question 11.**

**Solution:**

(a) 370

= (-37) x (-7) + (-37) x (-3)

= (-37) x [(-7) + (-3)] [Associative property]

= (-37) x (-10)

= 370

**Question 12.**

**Solution:**

(c) -250

=(-25) x 8 + (-25) x 2

= (-25) x (8 + 2) [Associative property]

= (-25) x 10 = -250

**Question 13.**

**Solution:**

(b) -3

(-9) – (-6)

= (-9) + 6

= -3

**Question 14.**

**Solution:**

(b) -6

-8 – (-6) = 2

Hence, -8 is -6 less than -2.

**Question 15.**

**Solution:**

(i) (-35) x -1 = 35

(ii) (-53) x (1) = -53

(iii) (-14) x (-1) = (-16) x (-14) [Commutative property]

(iv) (-21) x (0) = 0 [Property of zero]

(v) (-119) ÷ 17 = (-7)

(vi) (-247) ÷ (-19) = 13

(vii) (0) ÷ 31 = 0

(viii) (152) ÷ (-19) = -8

**Question 16.**

**Solution:**

(i) True (T)

(ii) (-8) ÷ 0 = 0

False (F). Dividing any integer by zero is not defined.

(iii) False (F).

(-1) ÷ (-1) = 1

(iv) True (T)

(v) True(T)

(vi) False (T).

68 ÷ (-17) = -4

Hope given RS Aggarwal Solutions Class 7 Chapter 1 Integers CCE Test Paper are helpful to complete your math homework.

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