RS Aggarwal Class 7 Solutions Chapter 2 Fractions CCE Test Paper
These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper.
Other Exercises
- RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A
- RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2B
- RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2C
- RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2D
- RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper
Question 1.
Solution:
(i) A number of the form \(\frac { a }{ b }\), where a and b are rational numbers, is called a natural number.
Here, a is the numerator and b is the denominator.
(a) \(\frac { 2 }{ 3 }\) is a fraction with 2 as the numerator and 3 as the denominator.
(b) \(\frac { 12 }{ 5 }\) is a fraction with 12 as the numerator and 5 as the denominator.
(ii) A fraction whose denominator is a whole number other than 10, 100, 1000, etc., is called a vulgar faction.
Examples : \(\frac { 2 }{ 5 }\) and \(\frac { 4 }{ 15 }\).
(iii) A fraction whose numerator is greater than or equal to its denominator is called an improper fraction.
Example : \(\frac { 11 }{ 3 }\) and \(\frac { 41 }{ 35 }\)
Question 2.
Solution:
Required number to be added
Hence, the required number is 8\(\frac { 2 }{ 5 }\)
Question 3.
Solution:
Question 4.
Solution:
Question 5.
Solution:
Question 6.
Solution:
Question 7.
Solution:
Question 8.
Solution:
Question 9.
Solution:
Mark (√) against the correct answer in each of the following:
Question 10.
Solution:
(d) \(\frac { 5 }{ 8 }\)
\(\frac { 5 }{ 8 }\) is a vulgar fraction, because its denominator is other than 10,100, 1000, etc.
Question 11.
Solution:
(c) \(\frac { 46 }{ 63 }\)
A fraction \(\frac { a }{ b }\) is said to be irreducible or in its lowest terms if the HCF of a and b is 1
46 = 2 x 23 x 1
63 = 3 x 3 x 21 x 1
Clearly, the HCF of 46 and 63 is 1.
Hence, \(\frac { 46 }{ 63 }\) is an irreducible fraction.
Question 12.
Solution:
(d) None of these
Reciprocal of 1\(\frac { 3 }{ 5 }\) = Reciprocal of \(\frac { 8 }{ 5 }\) = \(\frac { 5 }{ 8 }\)
Question 13.
Solution:
Question 14.
Solution:
Question 15.
Solution:
Question 16.
Solution:
(b) 33 km
Distance covered by the car on
Question 17.
Solution:
Question 18.
Solution:
(i) False.
By cross multiplication, we have:
9 x 24 = 216 and 13 x 16 = 208
However, 216 > 208
\(\frac { 9 }{ 16 }\) > \(\frac { 13 }{ 24 }\)
Hope given RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper are helpful to complete your math homework.
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