## RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3D.

**Other Exercises**

- RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3A
- RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3B
- RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3C
- RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3D
- RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3E
- RS Aggarwal Solutions Class 7 Chapter 3 Decimals CCE Test Paper

**Question 1.**

**Solution:**

We know that a decimal divided by 10, the decimal point is shifted to the left by one place. Therefore

(i) 131.6 ÷ 10 = 13.16

(ii) 32.56 ÷ 10 = 3.256

(iii) 4.38 ÷ 10 = 0.438

(iv) 0.34 ÷ 10 = 0.034

(v) 0.08 ÷ 10 = 0.008

(vi) 0.062 ÷ 10 = 0.0062

**Question 2.**

**Solution:**

We know that decimal divided by 100, the decimal point is shifted to the left by two place. Therefore

(i) 137.2 ÷ 100 = 1.372

(ii) 23.4 ÷ 100= 0.234

(iii) 4.1 ÷ 100 = 0.047

(iv) 0.3 ÷ 100 = 0.003

(v) 0.58 ÷ 100 = 0.0058

(vi) 0.02 ÷ 100 = 0.0002

**Question 3.**

**Solution:**

We know that a decimal divided by 1000, the decimal point is shifted to the left by three places. Therefore:

(i) 1286.5 ÷ 1000= 1.2865

(ii) 354.16 ÷ 1000 = 0.35416

(iii) 38.9 ÷ 1000 = 0.0389

(iv) 4.6 ÷ 1000 = 0.0046

(v) 0.8 ÷ 1000 = 0.0008

(vi) 2 ÷ 1000 = 0.002

**Question 4.**

**Solution:**

**Question 5.**

**Solution:**

**Question 6.**

**Solution:**

**Question 7.**

**Solution:**

**Question 8.**

**Solution:**

Cost of 24 chairs = Rs. 9255.60

Cost of one chair = Rs. \(\frac { 9255.60 }{ 24 }\) = Rs. 385.65

**Question 9.**

**Solution:**

Length of cloth for one shirt = 1.8 m

Total length of piece of cloth = 45 m

Number of shirts will be = 45 ÷ 1.8

**Question 10.**

**Solution:**

A car covers in 2.4 litre = 22.8 km

It will cover in 1 litre = \(\frac { 22.8 }{ 2.4 }\) km = 9.5 km

**Question 11.**

**Solution:**

Oil in one tin = 16.5 l

Total oil = 478.5 l

**Question 12.**

**Solution:**

Weight of 37 bags of sugar=3644.5 kg

Weight of one bag of sugar = 3644.5 ÷ 37

**Question 13.**

**Solution:**

Capacity of 69 buckets = 586.5 litres

Capacity of 1 bucket = 586.5 ÷ 69

**Question 14.**

**Solution:**

Number of pieces in 1.15 m = 1

**Question 15.**

**Solution:**

Total weight of cement = 1792.8 kg

Cement in one bag = 49.8 kg

Number of bags = 1792.8 ÷ 49.8

**Question 16.**

**Solution:**

Total thickness = 1.89 m = 189 cm

Thickness of one piece = 0.3 5 cm

Number of pieces = 189 ÷ 0.35

**Question 17.**

**Solution:**

Product of two decimals = 261.36

One decimal = 17.6

Second decimal = 261.36 ÷ 17.6

Hope given RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3D are helpful to complete your math homework.

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