## RS Aggarwal Class 7 Solutions Chapter 9 Unitary Method Ex 9A

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9A.

**Other Exercises**

- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9A
- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9B
- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9C
- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method CCE Test Paper

**Question 1.**

**Solution:**

Cost of 15 oranges = Rs. 110

Cost of 1 orange = Rs. \(\frac { 110 }{ 15 }\)

and cost of 39 oranges = Rs. \(\frac { 110 }{ 15 }\) x 39

= Rs. 22 x 13 = Rs. 286

**Question 2.**

**Solution:**

In Rs. 260, the sugar is bought = 8 kg

and in Re. 1, the sugar is bought = \(\frac { 8 }{ 260 }\) kg

Then in Rs. 877.50, the sugar will be bought = \(\frac { 8 }{ 260 }\) x 877.50 kg

= \(\frac { 8 }{ 260 }\) x \(\frac { 87750 }{ 100 }\)

= 27 kg

**Question 3.**

**Solution:**

In Rs. 6290, silk is purchased = 37 m

and in Re. 1, silk is purchased = \(\frac { 37 }{ 6290 }\) m

and in Rs. 4420, silk will be purchased 37

= \(\frac { 37 }{ 6290 }\) x 4420 m = 26 m

**Question 4.**

**Solution:**

Rs. 1110 is wages for = 6 days.

Re. 1 will be wages for = \(\frac { 6 }{ 1110 }\) days

and Rs. 4625 will be wages for

**Question 5.**

**Solution:**

In 42 litres of petrol, a car covers = 357 km

and in 1 litre, car will cover = \(\frac { 357 }{ 42 }\) km

and in 12 litres, car will cover = \(\frac { 357 }{ 42 }\) x 12 = 102 km

**Question 6.**

**Solution:**

Cost of travelling 900 km is = Rs. 2520

and cost of 1 km will be = Rs. \(\frac { 2520 }{ 900 }\)

andcostof360kmwillbe = Rs. \(\frac { 2520 }{ 900 }\) x 360 = Rs. 1008

**Question 7.**

**Solution:**

To cover a distance of 51 km, time is taken = 45 minutes

**Question 8.**

**Solution:**

If weight is 85.5 kg, then length of iron rod = 22.5 m

If weight is 1 kg, then length of rod will be

**Question 9.**

**Solution:**

In 162 grams, sheets are = 6

**Question 10.**

**Solution:**

1152 bars of soap can be packed in 8 cartons

1 bar of soap coil be packed in

**Question 11.**

**Solution:**

In 44 mm of thickness, cardboards are = 16

In 1 mm of thickness, cardboards will be

**Question 12.**

**Solution:**

If length of shadow is 8.2 m, then

height of flag staff is = 7 m

If length of shadow is 1 m, then height will

**Question 13.**

**Solution:**

16.25 m long wall is build by = 15 men

**Question 14.**

**Solution:**

1350 litres of milk cm be consumed by = 60 patients

1 litres of milk can be consumed by = \(\frac { 60 }{ 1350 }\) patients

and 1710 litres of milk can be consumed

**Question 15.**

**Solution:**

2.8 cm extension is produced by = 150 g.

1 cm extension will be produced by = \(\frac { 150 }{ 2.8 }\) g

and 19.6 cm extension will be produced by

Hope given RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9A are helpful to complete your math homework.

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