RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b
These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b.
Other Exercises
- RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15a
- RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b
- RS Aggarwal Solutions Class 10 Chapter 15 Probability MCQ
Question 1.
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Question 2.
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Question 3.
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Question 4.
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Question 5.
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Question 6.
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Question 7.
Solution:
Total number of tickets = 100
(i) Even numbers are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100
Total number of even number = 50
P(getting a even number) = 50/100 = 1/2.
(ii) Numbers less than 16 are 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
Total number of numbers less than 16 is 14
P(getting a number less than 16) = 14/100 = 7/50.
(iii) Numbers which are perfect square are 4, 9, 16, 25, 36, 49, 64, 81, 100
Total number of perfect squares = 9
P(getting a perfect square) = 9/100.
(iv) Prime numbers less than 40 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37
Total number of prime numbers =12
P(getting a prime number less 40) = 12/100 = 3/25.
Question 8.
Solution:
The total number of discs in the box are 80.
The numbers which are perfect squares are 1, 4, 9, 16, 25, 36, 49 and 64.
So, there are 8 possible outcomes.
P(getting a number which is a perfect square) = 8/80 = 1/10.
Question 9.
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Question 10.
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Question 11.
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Question 12.
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Question 13.
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Question 14.
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Question 15.
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Question 16.
Solution:
Two dice are thrown simultaneously
Total number of outcomes = 6 6 = 36
(i) Favourable cases are:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 6) = 25.
∴ Probability that 5 will not come upon either die = 25/36.
(ii) Favourable cases are:
(1, 5), (2, 5), (3, 5), (4, 5), (5, 5), (6, 5), (5, 1), (5, 2), (5, 3), (5, 4), (5, 6) = 11
Probability that 5 will come at least once = 11/36.
(iii) 5 will come up on both dice in 1 case = (5,5)
∴ probability that 5 will come on both dice = = 1/36.
Question 17.
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Question 18.
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Question 19.
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Question 20.
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Question 21.
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Question 22.
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Question 23.
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Question 24.
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Question 25.
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Hope given RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b are helpful to complete your math homework.
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