RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b.

Other Exercises

Question 1.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 1

Question 2.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 2

Question 3.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 3

Question 4.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 4

Question 5.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 5

Question 6.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 6

Question 7.
Solution:
Total number of tickets = 100
(i) Even numbers are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100
Total number of even number = 50
P(getting a even number) = 50/100 = 1/2.

(ii) Numbers less than 16 are 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
Total number of numbers less than 16 is 14
P(getting a number less than 16) = 14/100 = 7/50.

(iii) Numbers which are perfect square are 4, 9, 16, 25, 36, 49, 64, 81, 100
Total number of perfect squares = 9
P(getting a perfect square) = 9/100.

(iv) Prime numbers less than 40 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37
Total number of prime numbers =12
P(getting a prime number less 40) = 12/100 = 3/25.

Question 8.
Solution:
The total number of discs in the box are 80.
The numbers which are perfect squares are 1, 4, 9, 16, 25, 36, 49 and 64.
So, there are 8 possible outcomes.
P(getting a number which is a perfect square) = 8/80 = 1/10.

Question 9.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 7

Question 10.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 8

Question 11.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 9

Question 12.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 10

Question 13.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 11

Question 14.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 12

Question 15.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 13

Question 16.
Solution:
Two dice are thrown simultaneously
Total number of outcomes = 6 6 = 36

(i) Favourable cases are:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 6) = 25.
∴ Probability that 5 will not come upon either die = 25/36.

(ii) Favourable cases are:
(1, 5), (2, 5), (3, 5), (4, 5), (5, 5), (6, 5), (5, 1), (5, 2), (5, 3), (5, 4), (5, 6) = 11
Probability that 5 will come at least once = 11/36.

(iii) 5 will come up on both dice in 1 case = (5,5)
∴ probability that 5 will come on both dice = = 1/36.

Question 17.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 14

Question 18.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 15

Question 19.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 16

Question 20.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 17

Question 21.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 18

Question 22.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 19

Question 23.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 20

Question 24.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 21

Question 25.
Solution:
RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b 22

Hope given RS Aggarwal Solutions Class 10 Chapter 15 Probability Ex 15b are helpful to complete your math homework.
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