Category: CBSE Class 10

RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8b

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8b.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8a
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8b
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8c
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities MCQ
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Test Yourself

Question 1.
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Question 9.
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Question 10.
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Question 11.
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Question 12.
Solution:

Question 13.
Solution:

Question 14.
Solution:

Question 15.
Solution:

We hope the RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8b help you. If you have any query regarding RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8b, drop a comment below and we will get back to you at the earliest.

RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8a

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8a.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8a
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8b
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8c
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities MCQ
• RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Test Yourself

Question 1.
Solution:

Question 2.
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Question 3.
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Question 4.
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Question 5.
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Question 6.
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Question 7.
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Question 8.
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Question 9.
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Question 10.
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Question 11.
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Question 12.
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Question 13.
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Question 14.
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Question 15.
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Question 16.
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Question 17.
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Question 18.
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Question 19.
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Question 20.
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Question 21.
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Question 22.
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Question 25.
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Question 26.
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Question 27.
Solution:
(i)

(ii)

Question 28.
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Question 30.
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Question 31.
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Question 32.
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Question 33.
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Question 34.
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Question 35.
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Question 36.
Solution:
(i)

(ii)

(iii)

Question 37.
Solution:

We hope the RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8a help you. If you have any query regarding RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Identities Ex 8a, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 10 Social Science Geography Chapter 6 Manufacturing Industries

These Solutions are part of NCERT Solutions for Class 10 Social Science. Here we have given NCERT Solutions for Class 10 Social Science Geography Chapter 6 Manufacturing Industries.

TEXTBOOK EXERCISES

l. Very Short Answer Questions :

Question 1.
(a) Which industry uses limestone as a raw material ?
(b) Which agency markets steel for the public sector plants ?
(c) Which industry uses bauxite as a raw material ?
(d) Which industry manufactures telephones, computer etc.
Answer:

(a) Cement.
(b) Sail.
(c) Aluminium.
(d) Electronic industry.

Question 2.
Answer the following briefly in not more than 30 words :

1. What is manufacturing?
2. Name any three physical factors for the location of the industry.
3. Name any three human factors for the location of an industry.
4. What are the basic industries? Give an example.
5. Name the important raw materials used in the manufacturing of cement?

Answer:

1. Production of goods in large quantities after processing from raw materials to more
   valuable products is called manufacturing. For example, the paper is manufactured from wood, sugar from sugarcane and steel from iron ore, and aluminium from bauxite.
2. Three physical factors for the location of the industry are as given below :
   • Near to the raw material.
   • Nearness to power i.e., sources of power generation.
   • Climate particularly in the establishment of agro-based industries like cotton and jute textile.
3. Three human factors for the location of an industry are as mentioned below :
   • Labour – It may be skilled or unskilled.
   • Transport facilities – Good transport is needed to bring the raw material to the industries as well as to take finished goods to the market.
   • Demands for goods – There should be demands for goods so that the goods may be purchased and consumed. Some goods may ribbed to the good purchasing power of the people around the industries.
4. Basic industries are those industries which supply their products or raw materials to manufacture other goods e.g., iron and steel and copper smelting, aluminium smelting industries.
5. The important raw materials used in the manufacturing of cement are limestone, silica, alumina, and gypsum.

Question 3.
Write the answers to the following questions in 120 words :
(1) How are integrated steel plants different from mini steel plants? What problems does the industry face? What recent developments have led to a rise in production capacity?
(2) How do industries pollute the environment?
(3) Discuss the steps to be taken to minimise environmental degradation by industry? [CBSE 2016]
Answer:
(1)

1. Integrated steel plants are large.
2. They handle everything in one complex – from putting together raw material to steel making, rolling and shaping.
3. These plants manufacture everything from alloy to steel.

(2) Mini Steel Plants :

1. Mini steel plants are smaller, have electric furnaces, use steel scrap and sponge iron.
2. They have re-rollers that use steel ingots as well,
3. They produce mild and alloy steel of given specifications.

(3) The following problems are being faced by this industry —

1. High costs and limited availability of coking coal,
2. Lower productivity of labour
3. Irregular supply of energy and
4. Poor infrastructure.

(4)

(1) Liberalisation and Foreign Direct Investment have led to a rise in the production capacity of steel industry. Efforts of private entrepreneurs have given a boost to the industry. However, there is a need to allocate resources for research and development to produce steel more competitively.

(2) Industries have increased pollution and degraded environment. Industries create four types of pollution, namely, air, water, thermal and noise. These are explained as given below :

1. Air pollution :
The smoke emitted by til’s industries pollute air and water badly.

1. Air pollution is caused by the presence of high proportion of undesirable gases such as sulphur dioxide and carbon monoxide.
2. Air borne particulate materials contain both solid and liquid particles such as dust, sprays mist and smoke.
3. Smoke is emitted by chemical and paper factories, brick kilns, refineries and smelting plants, and burning of fossil fuels in big and small factories that ignore pollution norms.
4. The gas leaks can be very hazardous with long term effects. For example, Bhopal Gas tragedy killed hundreds of people and adversely affected human health, animals, plants etc. as a whole.

2. Water pollution :

1. The industrial effluents, both organic and inorganic, are discharged into rivers. They pollute the water.
2. Coal dyes, soaps, pesticides, fertilisers are some common pollutants of water.
3. The main industries that pollute water are paper, pulp, textiles, chemical, petroleum and electroplating.
4. These industries let out dyes, detergents, acids, salts and heavy metals like lead and mercury pesticides into the water bodies.
   Fly ash, phospho-gypsum and iron and steel slags are the major solid wastes in India.

3.Thermal pollution :

1. Thermal pollution of water occurs when hot water from factories and thermal plants is drained into the rivers and ponds before cooling.
2. Wastes from nuclear power plants, nuclear and weapon production facilities cause cancers, birth defects and miscarriages.
3. Dumping of wastes specially glass, harmful chemicals, industrial affluents, packagings, salts and garbage renders the soil useless.
4. Rain water percolates to the soil carrying the pollutants to the ground and the groundwater also gets contaminated

4. Noise pollution :

1. Industrial and construction activities, machinery, factory equipment, generators, saws and other equipment make a lot of noise which have bad effects on human beings.
2. It can cause hearing impairment, increased heart rate and blood pressure among other physiological effects.
3. Unwanted sound is an irritant and a source of stress.

(3) Steps to be taken to minimise environmental degradation by the industry. Some suggestions to minimise environmental degradation are given below :

1. To minimise use of water for processing by reusing and recycling it in two or more successive stages.
2. Harvesting of rainwater to meet water requirements.
3. Treating hot water and effluents before releasing them in rivers and ponds.
4. Treatment of industrial effluents can be done in three phases as given below :
   1. Primary treatment by mechanical means. This involves screening, grinding, flocculation and sedimentation.
   2. Secondary treatment by biological process.
   3. Tertiary treatment by biological, chemical and physical processes. This involves recycling of waste water.
5. There should be careful planning, siting of industries, better design equipment and better operation of the equipment.
6. Overdrawing of groundwater reserves should be regulated legally.
7. Particulate matter in the air can be reduced by fitting smoke stacks to factories with electrostatic precipitators, fabric filters, scrubbers and inertial separators.
8. Smoke can be reduced by using oil or gas instead of coal in factories.
9. Machinery and equipment can be used and generators should be fitted with silencers.
10. Almost all machinery can be redesigned to increase energy efficiency and reduce
    noise.
11. Noise absorbing material may be used apart from personal use of earplugs and earphones.

Question 4.
Give one word for each of the following with regard to industry. The number of letters in each word are hinted in brackets.

Answer:

(i) Power
(ii) Worker
(iii) Market
(iv) Retailer
(v) Product
(vi) Manufacture
(vii) Pollution.

Question 5.
Solve the puzzle by following your search horizontally and vertically to find the hidden answers.
1. Textiles, sugar, vegetable oil and plantation industries deriving raw materials from agriculture are called.
2. The basic raw material for sugar industry.
3. This fibre is also known as the ‘Golden Fibre’.
4. Iron-ore, coking coal, and limestone are the chief raw materials of this industry.
5. A public sector steel plant located in Chhattisgarh.
6. Railway diesel engines are manufactured in Uttar Pradesh at this place.

Answer:

1. Agro-based
2. Sugarcane
3. Jute
4. Iron Steel
5. Bhilai
6. Varanasi.

We hope the NCERT Solutions for Class 10 Social Science Geography Chapter 6 Manufacturing Industries help you. If you have any query regarding NCERT Solutions for Class 10 Social Science Geography Chapter 6 Manufacturing Industries, drop a comment below and we will get back to you at the earliest.

RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and O give Ex 9a

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Ex 9a.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9b
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9c
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9d
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9e
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself

Question 1.
Solution:

Question 2.
Solution:

​
Question 3.
Solution:

Question 4.
Solution:
We have

Question 5.
Solution:
We have

Question 6.
Solution:
We have

Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:

Question 13.
Solution:
We have
7+f₁+12+f₂+8+5=50 ⇒ f₂= 18-f₁

Question 14.
Solution:

Question 15.
Solution:
We have, Let A = 25 be the assumed mean

Hence mean = 28.

Question 16.
Solution:
Let the assumed mean be 150, h = 20

Hence, Mean = 146.25.

Question 17.
Solution:
Let A = 50 be the assumed mean, we have

Question 18.
Solution:

Question 19.
Solution:

Question 20.
Solution:

Question 21.
Solution:

​
Question 22.
Solution:

Question 23.
Solution:

​
Question 24.
Solution:

Question 25.
Solution:
Let h = 20 and assume mean = 550, we prepare the table given below:

Hence the mean of the frequency distribution is 544.

Question 26.
Solution:
The given series is an inclusive series, making it an exclusive series, we have

Question 27.
Solution:
The given series is an inclusive series making it an exclusive series,we get

Hence, Mean = 34.87 years.

Question 28.
Solution:

Question 29.
Solution:

We hope the RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a help you. If you have any query regarding RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a, drop a comment below and we will get back to you at the earliest

RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Test Yourself

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Test Yourself.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9b
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9c
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9d
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9e
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself

Question 1.
Solution:
Correct option: (b)
The cumulative frequency table is useful in determining the median.

Question 2.
Solution:
Correct option: (c)
Mean = 27
Median = 33
Mode = 3Median – 2Mean
= 3 x 33 – 2 x 27
= 99 – 54
= 45

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:

Question 6.
Solution:
Number of athletes who completed the race in less than 14.6 seconds
= 2 + 4 + 15 + 54
= 75.

Question 7.
Solution:

Question 8.
Solution:
The frequency table is as follows:

The frequency corresponding to the class 20 – 25 is 4.

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:

Question 13.
Solution:
We plot the points (10, 3), (20, 11), (30, 28), (40, 48) and (50, 70) to get the cumulative frequency curve as follows:

Question 14.
Solution:

Question 15.
Solution:
We plot the points (20, 2), (30, 7), (40, 17), (50, 40), (60, 60), (70, 82), (80, 85), (90, 90) and (100, 100) to get the cumulative frequency curve as follows:

Here, N = 100 ⇒ N/2 = 50
At y = 50, affix A.
Through A, draw a horizontal line meeting the curve at P.
Through P, a vertical line is drawn which meets OX at M.
OM = 56.
Hence, median = 56

Question 16.
Solution:

Question 17.
Solution:

Question 18.
Solution:

Question 19.
Solution:

Question 20.
Solution:
Less Than Series:

We plot the points (10, 2), (15, 14), (20, 16), (25, 20), (30, 23), (35, 27) and (40, 30) to get less than ogive.

More Than Series:

We plot the points (5, 30), (10, 28), (15, 16), (20, 14), (25, 10), (30, 7) and (35, 3) to get more than ogive.

–

The two curves intersect at L. Draw LM ⊥ OX.

Thus, median = OM = 16.

Question 21.
Solution:
Less Than Series:

We plot the points (45, 1), (50, 10), (55, 25), (60, 43), (65, 83), (35, 27), (70, 109), (75, 125), (80, 139) and (85, 149) to get less than ogive.

More Than Series:

We plot the points (40, 149), (45, 148), (50, 139), (55, 124), (60, 106), (65, 66), (70, 40), (75, 24) and (80, 10) to get more than ogive.

—

Question 22.
Solution:

We hope the RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself help you. If you have any query regarding RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself, drop a comment below and we will get back to you at the earliest.

RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give MCQ

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give MCQ.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9b
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9c
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9d
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9e
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself

Question 1.
Solution:
Correct option: (d)
Range is not a measure of central tendency.

Question 2.
Solution:
Correct option: (a)
Mean cannot be determined graphically.

Question 3.
Solution:
Correct option: (a)
Since mean is the average of all observations, it is influenced by extreme values.

Question 4.
Solution:
Correct option: (c)
Mode can be obtained graphically from a histogram.

Question 5.
Solution:
Correct option: (d)
Ogives are used to determine the median of a frequency distribution.

Question 6.
Solution:
Correct option: (b)
The cumulative frequency table is useful in determining the median.

Question 7.
Solution:
Correct option: (b)
Median is given by the abscissa of the point of intersection of the Less than Type and More than Type cumulative frequency curves.

Question 8.
Solution:
Correct option: (b)
For a grouped data,
\(\sum { f }_{ i }\left( { x }_{ i }-\bar { x } \right) =0\)

Question 9.
Solution:
Correct option: (b)
By formula method,
\(\bar { x } =\quad A+h\left[ \frac { \sum { { f }_{ i }{ u }_{ i } } }{ \sum { { f }_{ i } } } \right] \)
where \({ u }_{ i }=\quad \frac { \left( { x }_{ i }-A \right) }{ h } \)

Question 10.
Solution:
Correct option: (c)
d_i‘s are the deviations from A of midpoints of the classes.

Question 11.
Solution:
Correct option: (b)
While computing the mean of the grouped data, we assume that the frequencies are centred at the class marks of the classes.

Question 12.
Solution:
Correct option: (b)
Mode = (3 x median) – (2 x mean)

Question 13.
Solution:
Correct option: (c)
Since the abscissa of the point of intersection of both the ogives gives the median, we have median = 20.5

Question 14.
Solution:

Question 15.
Solution:
Correct option: (c)
Class having maximum frequency is the modal class.
Here, maximum frequency = 30
Hence, the modal class is 30 – 40.

Question 16.
Solution:
Correct option: (b)
Mode = \({ x }_{ k }+h.\left\{ \frac { { f }_{ k }-{ f }_{ k-1 } }{ \left( { 2f }_{ k }-{ f }_{ k-1 }-{ f }_{ k+1 } \right) } \right\} \)

Question 17.
Solution:
Correct option: (a)
Median = \(l+\left\{ h\times \frac { \left( \frac { N }{ 2 } -cf \right) }{ f } \right\} \)

Question 18.
Solution:
Correct option: (c)
Mean = 8.9
Median = 9
Mode = 3Median – 2Mean
= 3 x 9 – 2 x 8.9
= 27 – 17.8
= 9.2.

Question 19.
Solution:

Question 20.
Solution:

Question 21.
Solution:

Question 22.
Solution:

Question 23.
Solution:
Correct option: (c)
For a symmetrical distribution,
we have  Mean = mode = median

Question 24.
Solution:
Correct option: (c)
Number of families having income more than Rs. 20000 = 50
Number of families having income more than Rs. 25000 = 37
Hence, number of families having income range 20000 to 25000 = 50 – 37 = 13

Question 25.
Solution:

Question 26.
Solution:
Correct option: (d)
Mean of 20 numbers = 0
Hence, sum of 20 numbers = 0 x 20 = 0
Now, the mean can be zero if
sum of 10 numbers is (S) and the sum of remaining 10 numbers is (-S),
sum of 11 numbers is (S) and the sum of remaining 9 numbers is (-S), …….
sum of 19 numbers is (S) and the 20^th number is (-S), then their sum is zero.
So, at the most, 19 numbers can be greater than zero.

Question 27.
Solution:

Question 28.
Solution:

Question 29.
Solution:
(a) – (s)
The most frequent value in a data is known as mode.
(b) – (r)
Mean cannot be determined graphically.
(c) – (q)
An ogive is used to determine median.
(d) – (p)
Standard deviation is not a measure of central tendency.

Question 30.
Solution:

Question 31.
Solution:

We hope the RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ help you. If you have any query regarding RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ, drop a comment below and we will get back to you at the earliest.

RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Ex 9f

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Ex 9f.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9b
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9c
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9d
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9e
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself

Question 1.
Solution:

Question 2.
Solution:
Class having maximum frequency is the modal class.
Here, maximum frequency = 27
Hence, the modal class is 40 – 50.
Thus, the lower limit of the modal class is 40.

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:

Question 6.
Solution:

Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:

Question 13.
Solution:

Question 14.
Solution:

Question 15.
Solution:

Question 16.
Solution:

Question 17.
Solution:

Question 18.
Solution:

Question 19.
Solution:

Question 20.
Solution:

Question 21.
Solution:

Question 22.
Solution:

We hope the RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f help you. If you have any query regarding RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f, drop a comment below and we will get back to you at the earliest.

RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Ex 9e

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data,Cumulative Frequency Graph and O give Ex 9e.

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9a
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9b
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9c
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9d
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9e
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9f
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data MCQ
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Test Yourself

Question 1.
Solution:

We plot the points (10, 5), (20, 8), (30, 12), (40, 15), (50, 18), (60, 22), (70, 29), (80, 38), (90, 45) and (100, 53) to get the ‘less than type’ ogive as follows:

Here, N = 53 ⇒ N/2 = 26.5.
At y = 26.5, affix A.
Through A, draw a horizontal line meeting the curve at P.
Through P, a vertical line is drawn which meets OX at M.
OM = 68 units
Hence, median marks = 68

Question 2.
Solution:
We plot the points (15, 2), (30, 5), (45, 9), (60, 17), (75, 39), (90, 54), (105, 70) and (120, 80) to get the ‘less than type’ ogive as follows:

Here, N = 80 ⇒ N/2 = 40.
At y = 40, affix A.
Through A, draw a horizontal line meeting the curve at P.
Through P, a vertical line is drawn which meets OX at M.
OM = 78 units
Hence, median number of wickets = 78

Question 3.
Solution:

We plot the points (0, 100), (10, 96), (20, 90), (30, 80), (40, 70), (50, 45), (60, 23) and (70, 5) to get the ‘more than type’ ogive as follows:

Here, N = 100 ⇒ N/2 = 50.
At y = 50, affix A.
Through A, draw a horizontal line meeting the curve at P.
Through P, a vertical line is drawn which meets OX at M.
OM = 47 units
Hence, median marks = 47.

Question 4.
Solution:

We plot the points (135, 50), (140, 45), (145, 37), (150, 28), (155, 16) and (160, 2) to get the ‘more than type’ ogive as follows:

Here, N = 50 ⇒ N/2 = 25.
At y = 25, affix A.
Through A, draw a horizontal line meeting the curve at P.
Through P, a vertical line is drawn which meets OX at M.
OM = 151 units
Hence, median height = 151 cm.

Question 5.
Solution:

We plot the points (140, 156), (160, 153), (180, 145), (200, 130), (220, 90), (240, 40) and (260, 10) to get the ‘more than type’ ogive as follows:

Here, N = 156 ⇒ N/2 = 78.
At y = 78, affix A.
Through A, draw a horizontal line meeting the curve at P.
Through P, a vertical line is drawn which meets OX at M.
OM = 226 units
Hence, median consumption of electricity = 226 units

Question 6.
Solution:

We plot the points (50, 100), (55, 98), (60, 90), (65, 78), (70, 54)and (75, 16) to get the ‘more than type’ ogive as follows:

Here, N = 100 ⇒ N/2 = 50.
At y = 50, affix A.
Through A, draw a horizontal line meeting the curve at P.
Through P, a vertical line is drawn which meets OX at M.
OM = 70.5 units
Hence, median production yield = 70.5 kg/ha

Question 7.
Solution:
Less Than Series:

Class interval	Cumulative Frequency
Less than 200	5
Less than 300	11
Less than 400	22
Less than 500	35
Less than 600	40
Less than 700	44
Less than 800	47
Less than 900	49

We plot the points (200, 5), (300, 11), (400, 22), (500, 35), (600, 40), (700, 44), (800, 47) and (900, 49) to get ‘less than type’ ogive.

More Than Series:

Class interval	Frequency
More than 100	49
More than 200	44
More than 300	38
More than 400	27
More than 500	14
More than 600	9
More than 700	5
More than 800	2

We plot the points (100, 49), (200, 44), (300, 38), (400, 27), (500, 14), (600,9), (700, 5) and (800, 2) to get more than ogive.

Question 8.
Solution:
More than series

We plot the points (400, 230), (450, 210), (500, 175), (550, 135), (600, 103), (650, 79), (700, 52), (750, 34)

Hence,N = 230 ⇒ N/2 = 115.
Take a point A(0, 115) on the y-axis and draw AP||x-axis meeting the curve at P, Draw PM ⊥ x-axis intersecting x-axis at M
Then,OM = 590
Hence median = 590.

Question 9.
Solution:
(i) Less than series:

Plot the points (5, 2), (10, 7), (15, 13), (20, 21), (25, 31), (30, 56), (35, 76), (40, 94), (45, 98) and (50, 100)

Join these points free hand to get the curve representing “less than” cumulative curve.

(ii)From the given table we may prepare the ‘more than’ series as shown below:

Now, on the same graph paper as above, we plot the point (0, 100), (5, 98), (10, 93), (15, 87), (20, 79), (25, 69), (30, 44), (35, 24) and (40, 6) and (45, 2)
Join these points free hand to get required curve
Here N = 100 ⇒ N/2 = 50
Two curves intersect at point P(28, 50)
Hence, the median = 28.

Question 10.
Solution:
We may prepare less than series and more than series

(i)Less than series :

Now on graph paper plot the points (140, 0), (144, 3), (148, 12), (152, 36), (156, 67), (160, 109), (164, 173), (168, 248), (172, 330), (176, 416), (180, 450)

(ii)More than series :

Now on the same graph plot the points (140, 450), (144, 447), (148, 438), (152, 414), (156, 383), (160, 341), (164, 277), (168, 202), (172, 120), (176, 34), (180, 0)

The curves intersect at (167, 225).
Hence, 167 is the median.

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NCERT Solutions for Class 10 Social Science Civics Chapter 1 Power Sharing

These Solutions are part of NCERT Solutions for Class 10 Social Science. Here we have given NCERT Solutions for Class 10 Social Science Civics Chapter 1 Power Sharing.

TEXTBOOK EXERCISES

Question 1.
What are the different forms of power-sharing in modern democracies? Give an example of each of these.
Answer:
(i) Power-sharing among the different organs of government (Horizontal power-sharing). In a democracy, power is shared among the different organs of the government such as the legislature, executive, and the judiciary. This is called the horizontal distribution of power because it allows different organs of the government placed at the same level to exercise different powers. Under this kind of power-sharing arrangement, one can exercise unlimited powers. Each organ has its own powers, and it can also check the powers of others. So this results in a balance of power among the various institutions.

(ii) Power-sharing among governments at different levels: Under this, people choose separate governments at separate levels, for example, a general local government for the entire country and local governments at the provincial, sub-national or regional levels. Such a general government for the entire country is usually called a Federal government.

(iii) Power-sharing among different social groups: In a democracy, especially, in a multi-ethnic society, power is also shared
among social groups such as the religious and linguistic groups. ‘Community government’ in Belgium is a good example of this arrangement. In some countries, there are constitutional and legal arrangements whereby socially weaker sections and women are represented in the legislatures and the administration.

(iv) Power-sharing among political parties, pressure groups, and movements : In a democracy, power is also shared among different political parties, pressure groups, and movements. Democracy provides citizens with a choice to choose their rulers. This choice is provided by the various political parties, who contest elections to win them. Such competition ensures that power does not remain in one hand.

Question 2.
State one prudential reason and one moral reason for power-sharing with an example from the Indian context.
Answer:
(1) Prudential reason:

1. Power-sharing helps to reduce the possibility of conflict between social groups,
2. Social conflict often leads to violence and political instability, power-sharing is a good way to ensure the stability of political order,
3. Imposing the will of the majority community over others undermines the unity of the nation as has happened in Sri Lanka,
4. The tyranny of the majority is not just oppressive for the majority, it often brings ruin to the majority as well. For example, in India seats in the assemblies and parliament have been reserved. This arrangement is meant to give space in the government and administration to diverse social groups. In addition to this minorities have been granted special fundamental rights.

(2) Moral reason:

1. In a democracy, power-sharing is necessary. Since all the people are affected by the policies of the government, they should be consulted in the governance of the country,
2. They should be allowed to participate in the decision-making process,
3. It is the basis of democracy. It is its very spirit.
4. A legitimate government is one where citizens participate and acquire a stake in the system. Thus, moral reasons emphasize the very act of power-sharing as valuable. In India, people elect their representatives every five years or earlier. People have also been granted the right to information.

Question 3.
After reading this chapter, three students drew different conclusions. Which of these do you agree with and why? Give your reasons in about 50 words.
Thomman — Power sharing is necessary only in societies which have religious, linguistic or ethnic divisions.
Mathai — Power sharing is suitable only for big countries that have regional divisions.
Ouseph — Every society needs some form of power-sharing even if it is small or does not have social divisions.
Answer:
Every society needs some form of power sharing even if they are small or do not have social divisions because :
(i) Some power-sharing is always needed to give voice to all, and representation to all the members of the country.
(ii) Power-sharing solutions are adopted to maintain stability in the system, and peace among various groups to ensure the smooth functioning of the system, irrespective of the size of the country.

Question 4.
The Mayor of Merchtem, a town near Brussels in Belgium, has defended a ban on speaking French in the town’s schools. He said that the ban would help all non-Dutch speakers integrate into this Flemish town. Do you think that this measure is in keeping with the spirit of Belgium’s power-sharing arrangements? Give your reasons in about 50 words.
Answer:
No, the measure taken by the Mayor of Merchtem is not in keeping with the spirit of Belgium’s power sharing arrangements. As 59 per cent of the population in the Flemish region speaks Dutch, the ban on speaking French in the town’s schools would prevent French and Dutch speakers to mingle with each other, and also create feelings of distrust and suspicion. The ban ignores the regional differences and cultural diversities. It is against the spirit of accommodating every linguistic group, and creating a right environment for everyone to live. The ban, rather, makes the ground for a civic strife, and a possible division of the community on linguistic lines.

Question 5.
Read the following passage and pick out any one of the prudential reasons for power sharing offered in this :
“We need to give more power to the panchayats to realise the dream of Mahatma Gandhi and the hopes of the makers of our Constitution. Panchayati Raj establishes true democracy. It restores power to the only place where power belongs in a democracy – in the hands of the people. Giving power to Panchayats is also a way to reduce corruption and increase administrative efficiency. When people participate in the planning and implementation of developmental schemes, they would naturally exercise greater control over these schemes. This would eliminate the corrupt middlemen. Thus, Panchayati Raj will strengthen the foundations of our democracy.”
Answer:
“Giving power to Panchayats is also a way to reduce corruption and increase adminis¬trative efficiency. When people participate in the planning and implementation of developmental schemes, they would naturally exercise greater control over these schemes. This would eliminate the corrupt middlemen. Thus, Panchayati Raj will strengthen the foundations of our democracy.” In this way power sharing will help to reduce the possibility of conflicts among different social groups in the village. There will be no violence and political stability will be established. As a result of it there will be peace and the village may make progress in different fields.

Question 6.
Different arguments are usually put forth in favour of and against power-sharing. Identify those which are in favour of power-sharing and select the answer using the codes given below. Power-sharing :
A. reduces conflict among different communities.
B. decreases the possibility of arbitrariness.
C. delays the decision-making process.
D. accommodates diversities.
E. increases instability and divisiveness.
F. promotes people’s participation in government.
G. undermines the unity of a country.

(a)	A	B	D	F
(b)	A	C	E	F
(c)	A	B	D	G
(d)	B	C	D	G

Answer:
(a) A, B, D, F.

Question 7.
Consider the following statements about power-sharing arrangements in Belgium and Sri Lanka :
A. In Belgium, the Dutch-speaking majority of people tried to impose their domi¬nation on the minority French-speaking community.
B. In Sri Lanka, the policies of the government sought to ensure the dominance of the Sinhala-speaking majority.
C. The Tamils in Sri Lanka demanded a federal arrangement of power-sharing to protect their culture, language and equality of opportunity in education and jobs.
D. The transformation of Belgium from a unitary government to a federal one prevented a possible division of the country on linguistic lines.
Which of the statements given above are correct?
(a) A, B, C, and D
(b) A, B, and D
(c) C and D
(d) B, C, and D
Answer:
(d) B, C, and D.

Question 8.
Match List I (forms of power-sharing) with List-II (forms of government) and select the correct answer using the codes given below in the lists :

List I	List II
1. Power shared among different organs of government	A. Community government
2. Power shared among governments at different levels	B. Separation of powers
3. Power shared by different social groups	C. Coalition government
4. Power shared by two or more political parties	D. Federal government

Answer:
(c) B, D, A, C.

Question 9.
Consider the following two statements on power-sharing and select the answer using the codes given below :
A. Power sharing is good for democracy.
B. It helps to reduce the possibility of conflict between social groups.
Which of these statements are true and false?
(a) A is true but B is false (b) Both A and B are true
(c) Both A and B are false (cl) A is false but B is true

	1	2	3	4
(a)	D	A	B	C
(b)	B	C	D	K A
(c)	B	D	A	c
(d)	C	D	A	B

Answer:
(b) Both A and B are true.

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NCERT Solutions for Class 10 Social Science Geography Chapter 1 Resource and Development

These Solutions are part of NCERT Solutions for Class 10 Social Science. Here we have given NCERT Solutions for Class 10 Social Science Geography Chapter 1 Resource and Development.

TEXTBOOK EXERCISES

Question 1.
(a) What type of resource is iron ore?
(b) Which is a replenishable type of resource?
(c) State one cause of land degradation in Punjab.
(d) In which state is terrace cultivation practised?
(e) Mention one state where black soil is found.
Answer:
(a) Non-renewable.
(b) Tidal energy.
(c) Intensive cultivation.
(d) Uttarakhand.
(e) Gujarat.

Question 2.
Answer the following questions in about 30 words :

1. Name three states having black soil and the crop which is mainly grown in it.
2. What type of soil is found in the river deltas of the eastern coast? Give three main features of this type of soil.
3. What steps can be taken to control soil erosion in the hilly areas?
4. What are the biotic and abiotic resources? Give some examples.

Answer:
(1) The states of Maharashtra, Madhya Pradesh and Chhattisgarh have black soil. The crop which is mainly grown in this soil is cotton. This soil is also called ‘Regur’ or black cotton soil.

(2) The river deltas of the eastern coast have alluvial soil.
Alluvial soil consists of various proportions of sand, silt, and clay.
The main features of alluvial soil are:

• These soils are very fertile and so ideal for cultivation.
• They contain adequate quantities of potash, phosphoric acid and lime good for the growth of sugarcane, paddy, and other crops.
• In drier areas, these soils are more alkaline.

(3) In hilly areas, soil erosion can be controlled by contour ploughing which is ploughing along contour-lines, using terrace farming techniques, and using strips of grasses to check soil erosion by wind and water.

(4) Biotic Resources: The resources which are obtained from the biosphere and have life are called Biotic Resources. Examples of biotic resources are animals, plants, human beings, fish, livestock, etc.
Abiotic Resources: The resources which are composed of non-living things are called Abiotic Resources.
Examples of abiotic resources are water, minerals, metals, wind, solar energy, etc.

Question 3(1).
Answer the following questions in about 120 words :
(1) Explain land use pattern in India and why has the land under forest not increased much since
1960-61.
Answer:
(1) The land use for different purposes in the year 1960-61 and 2002-03 is as given B below:

(2) On the basis of the above chart and other facts available, the main features of the land use pattern in India are as mentioned below :

• The total geographical area of India is 3.28 million sq. km.
• Land use data, however, is available only for 93 percent of the total area because the land use reporting for most of the north-east states except Assam has not been done fully. Moreover, some areas of Jammu and Kashmir occupied by Pakistan and China have also not been surveyed.

(3) The land under permanent pasture has decreased.
(4) The pattern of the net sown area varies greatly from one state to another. It is over 80 per tent of the total area in Punjab and Haryana and less than 10 percent in Arunachal Pradesh, Mizoram, Manipur, and Andaman Nicobar Islands.
(5) The land under forest has changed a little from 18.11% in 1960-61 to 22.57% in 2002-03. It is still far lower than the desired 33 percent of the geographical area as it was outlined in the National Forest Policy (1952). Land under forest has not increased due to various factors, namely, agricultural expansion, large-scale development projects or river valley projects, grazing and fuel collection.
(6) A part of the land is termed as wasteland and land put to other non-agricultural uses.

Question 3(2).
How has technical and economic development led to more consumption of resources?
Answer:
Technical and economic development has led to more consumption of resources due to reasons as mentioned below :

1. Higher level of technological development needs more and more resources for production activities.
2. As Gandhiji said the exploitative nature of modem technology is the root cause of resource depletion at the global level.
3. It was primarily the higher level of technological development of the colonising countries that helped them to exploit resources of other regions and establish their supremacy over the colonies. Thus resources can contribute to development only when they are accompanied by appropriate technological development and institutional changes. India has experienced all this in different phases of colonisation.
   Thus, it is true that technical and economic development leads to more consumption of resources. Water resources are being exploited to expand the irrigated areas and dry season agriculture. As the result as in the case of Punjab and Haryana, the water level has gone down creating problems for the farmers.

Question 4.
Imagine if oil supplies get exhausted, how will this affect our lifestyle?
Answer:

1. If oil supplies get exhausted, the world would come to a halt. People would end up living wherever they were. There will be no more planes, operating boats and trains.
2. Pricing for any transportation would be out of reach but for the richest for a limited period.
3. We would be limited to existing supplies of coal, natural gas, etc.
4. A lot of jobs would be lost because many factories, restaurants, etc. would be shut down.
5. Many would leave cities to live in rural areas.
6. Cities would become ghost towns. There may be killed in order to control the necessary things needed for survival in the world. We would not only lose our lifestyle but lose contact with the whole world. However, as scientists are doing research to find out alternative sources of energy, it is hoped that they would be successful in their efforts. They may be able to use solar or wind energy in place of petroleum products and in that case, if the oil supplies get exhausted, it would not make any difference in our lives. Perhaps, life would become better in the future.

Question 5.
Solve the puzzle by following your search horizontally and vertically to find the hidden answers.

1. Natural endowments in the form of land, water, vegetation and minerals.
2. A type of non-renewable resource.
3. Soil with high water retaining capacity.
4. Intensively leached soils of the monsoon climate.
5. Plantation of trees on a large scare to check soil erosion.
6. The Great Plains of India are made up of these soils.

Answer:

1. Resource
2. Minerals
3. Laterite
4. Black
5. Afforestation
6. Alluvial.

We hope the NCERT Solutions for Class 10 Social Science Geography Chapter 1 Resource and Development help you. If you have any query regarding NCERT Solutions for Class 10 Social Science Geography Chapter 1 Resource and Development, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 10 Social Science Geography Chapter 5 Minerals and Energy Resources

These Solutions are part of NCERT Solutions for Class 10 Social Science. Here we have given NCERT Solutions for Class 10 Social Science Geography Chapter 5 Minerals and Energy Resources.

TEXTBOOK EXERCISES

Very Short Answer Questions :

Question 1.
(a) Which mineral is formed by the decomposition of rocks leaving a residual mass of weathered material?
(b) Which place in Jharkhand is the leading producer of mica?
(c) In which type of rocks, are minerals deposited and accumulated in the stratas?
Answer:
(a) Bauxite.
(b) Koderma.
(c) Minerals are deposited and accumulated in the stratas of the sedimentary rocks.

Question 2.
Answer the following questions in about 30 words :
(1) Distinguish between the following in not more than 30 words :

• Ferrous and non-ferrous minerals.
• Conventional and non-conventional sources of energy.

(2) What is a mineral?
(3) How are minerals formed in igneous and metamorphic rocks?
(4) Why do we need to conserve mineral resources?
Answer:
(1)
1.The ferrous and non-ferrous minerals may be distinguished as given below
Ferrous minerals

1. Ferrous minerals contain iron e.g., iron ore, manganese, nickel, cobalt etc.
2. Ferrous minerals account for about three-fourths of the total value of the production of metallic minerals.
3. These minerals provide a strong base for the development of metallurgical industries.

Non-ferrous minerals

1. Non-ferrous minerals are copper, lead, tin, bauxite, gold.
2. India’s reserves and production of non-ferrous minerals are not very satisfactory.
3. These minerals play a vital role in a number of metallurgical, engineering, and electrical industries.

2. Conventional and non-conventional sources of energy are distinguished as given below :
Conventional sources of energy

1. Conventional sources of energy have been used for quite some time.
2. These are coal, petroleum, natural gas. uranium and electricity (both hydel and thermal etc.).
3. Conventional sources are finite and non-renewable.

Non-conventional sources of energy

1. Non-conventional sources arc new.
2. These are solar, wind, tidal, geothermal, biogas and atomic energy.
3. These are renewable energy sources.

(2) Geologists define mineral as a ‘homogeneous, naturally occurring substance with a definable internal structure’.

(3) Minerals are formed in igneous and metamorphic rocks as mentioned below :

(a) In igneous and metamorphic rocks Funerals may occur in the cracks, crevices, faults or joints.
(b) The smaller occurrences are called veins and the larger are called lodes.
(c) In most cases, they are formed when minerals in liquid/molten and gaseous forms are forced upward through cavities towards the earth’s surface.
(d) They cool and solidify as they rise.
(e) Major metallic minerals like tin, copper, zinc and lead are obtained from veins and lodes i.e., smaller and larger occurrences.

(4)
(1) We need to conserve mineral resources due to the reasons as mentioned below :

1. Our industry and agriculture depend on mineral deposits and the substances manufactured from them. But the total volume of workable mineral deposits is an insignificant fraction i.e., one per cent of the earth’s crest.
2. It took millions of years for the creation and concentration of mineral resources.
3. The geological processes of mineral formation is very slow but its consumption is fast. It may result in shortage in near future.
4. The mineral resources are finite and non-renewable.
5. Even rich mineral deposits in a country like India are valuable but short-lived possessions.
6. Continued extraction of ores leads to increasing costs as mineral extraction comes from greater depths. At the same time, its quality also decreases.

(2) Steps for the conservation of minerals :

1.  All should make a concerted effort to use our mineral resources in a planned and sustainable manner.
2. Improved technologies need to be constantly evolved to allow use of low grade ores at low costs.
3. Recycling of metals using scrap metals and other substitutes also helps in conserving mineral resources for the future.

Question 3.
Answer the following questions in about 120 words :
(1) Describe the distribution of coal in India.
(2) Why do you think that solar energy has a bright future in India?
Answer:
(1) Distribution of coal in India: It is the main source of power generation in India. Major places where coal is found in India are as given below :

1. Gondwana coal deposits: These are about 200 million years old. The major coal deposits in India are Gondwana coal, which are metallurgical coal and located in Damodar valley (West Bengal-Jharkhand). These constitute mainly Jharia, Dhanbad, Raniganj and Bokaro coalfields. Besides the Godavari, Mahanadi, Son and Wardha valley also contain coal deposits.
2. Tertiary coal deposits :
   1. These are around 55 million years old.
   2. These coal deposits are found in the north-eastern states of Meghalaya, Assam, Arunachal Pradesh and Nagaland.

(2) Solar energy has a bright future in India as mentioned below :

1. India is a tropical country. It has enormous possibilities of tapping solar energy.
2.  Photovoltaic technology converts sunlight directly into electricity.
3. Solar energy is fast becoming popular in rural and remote areas.
4. The largest solar plant of India is located at Madhapur, near Bhuj, where solar energy is used to sterilize milk cans.
5. It is expected that use of solar energy will be able to minimise the dependence of rural households on firewood and dung cakes, which in turn will contribute to environmental conservation and adequate supply of manure in agriculture.
6. Not only this solar energy may be used for solar domestic lights, solar lanterns and solar street lights.
7.  It can be used to keep the building warm in cold season in cold areas.
8. Solar energy can be produced about 20 MW per square km per annum. Thus if produced at the maximum production, it can solve many problems.

Question 4.

Fill the name of the correct mineral in the crossword below :

Answer:
Across

1. Manganese
2. Limestone
3. Magnetite
4. Anthracite
5. Bauxite
6. Copper
7. Gypsum

Down

1. Gold
2. Hematite
3. Mica
4. Tertiary
5. Tin

We hope the NCERT Solutions for Class 10 Social Science Geography Chapter 5 Minerals and Energy Resources help you. If you have any query regarding NCERT Solutions for Class 10 Social Science Geography Chapter 5 Minerals and Energy Resources, drop a comment below and we will get back to you at the earliest.