Online Education NCERT Solutions for Class 6 English Honeysuckle Poem Chapter 6 The Wonderful Words

In Online Education NCERT Solutions for Class 6 English Honeysuckle Poem Chapter 6 The Wonderful Words are part of NCERT Solutions for Class 6 English. Here we have given NCERT Solutions for Class 6 English Honeysuckle Poem Chapter 6 The Wonderful Words.

Board CBSE
Textbook NCERT
Class Class 6
Subject English Honeysuckle Poem
Chapter Chapter 6
Chapter Name The Wonderful Words
Number of Questions Solved 22
Category NCERT Solutions

Online Education NCERT Solutions for Class 6 English Honeysuckle Poem Chapter 6 The Wonderful Words

Stanzas For Comprehension

Read the following extracts and answer the questions that follow choosing the best option from among the given ones.
1.
Never let a thought shrivel and die
For want of a way to say it
For English is a wonderful game
And all of you can play it
All that you do is match the words
To the brightest thoughts in your head
NCERT Solutions for Class 6 English Honeysuckle Poem Chapter 6 The Wonderful Words image 1

Paraphrase :
Do not let a thought die unexpressed for want of words. Expression is a funny game in English. Everyone can play it. All that you have to do is to find proper words to match your best thoughts.

Multiple Choice Questions.
1.
The thoughts die when

(a) they are bad
(b) they are good
(c) they are beautiful
(d) they are not expressed

2.
To give expression to the thoughts one has to

(a) work hard
(b) think well
(c) find proper words
(d) study a lot

3.
The poet feels that English has enough words

(a) to express every idea
(b) for us to learn
(c) to confuse us
(d) to write any book

4.
English is a game which is

(a) like cricket
(b) like playing cards
(c) for all persons
(d) for those who love to express themselves

5.
The adverb form of ‘wonderful’ is

(a) wonder
(b) wonderfully
(c) wondered
(d) wondering

Answers :

  1. (d) they are not expressed
  2. (c) find proper words
  3. (a) to express every idea
  4. (d) for those who love to express themselves
  5. (b) wonderfully

2.
So that they come out clear and true
And handsomely groomed and fed-
For many of the loveliest things
Have never yet been said.
Word-Notes :
True-exact, सही-सहीHandsomely-beautifully, सुंदरता से। Groomed-decorated, सजा हुआ।

हिन्दी अनुवाद :
ताकि वे (विचार) स्पष्ट और सही तरह अभिव्यक्त हों और उन्हें सुंदरता से सजाया और विकसित किया जा सके। क्योंकि बहुत से सुन्दरतम विचार अभी तक अभिव्यक्ति नहीं पा सके हैं।

Paraphrase :
(Work to express your best thoughts) so that they are expressed beautifully decorated and developed. The truth is that many of the most beautiful things are still waiting for an expression.

Multiple Choice Questions

1.
The passage is taken from

(a) The Wonderful Words
(b) Beauty
(c) A House, A Home
(d) The Kite

2.
The author of the poem is

(a) L.M. Halli
(b) Mary O’ Neill
(c) Peter Dixon
(d) Shure

3.
The poem is about

(a) a groom
(b) a girl
(c) words
(d) beauty

4.
The ‘loveliest things’ are

(a) money
(b) fame
(c) beauty
(d) great ideas

5.
The noun form of ‘fed’ is

(a) feed
(b) feeding
(c) food
(d) feeling

Answers :

  1. (a) The wonderful words
  2. (b) Mary O’ Neill
  3. (c) words
  4. (d) great ideas
  5. (c) food

3.
Words are the food and dress of thought
They give it its body and swing
And everyone’s longing today to hear
Some fresh and beautiful thing ;
But only words can free a thought
From its prison behind your eyes
May be your mind is holding now
A marvellous new surprise !
Word-Notes :
Swing-rhythm/progression/impetus/freedom, लय/ गति/ शक्ति/ स्वतंत्रा Longing-desiring, इछुक। Holding-keeping, रखे हुए। Marvellous wonderful, शानदार।

हिन्दी अनुवाद :
शब्द विचारों के शरीर और वस्त्र हैं। वे उन्हें उनका रूप, शक्ति और स्वतंत्रता प्रदान करते हैं। और आज हर व्यक्ति कोई ताजी और सुन्दर बात सुनने की कामना करता है, पर केवल शब्द ही तुम्हारी आँखों के पीछे छिपे कारागार से उन्हें मुक्ति दिला सकते हैं, हो सकता है इस समय भी तुम्हारे मस्तिष्क में कोई शानदार नया विचार सुरक्षित है।

Paraphrase :
Thoughts survive on words. They are their food and clothing. They give them the body and force. Everybody wants to hear some new and beautiful things today. Only the words can free a thought imprisoned in the mind. May be your mind is even now holding back a new and beautiful thought.

Multiple Choice Questions.
1.
If the words are the body, the thought is its

(a) dress
(b) food
(c) soul
(d) swing

2.
According to the poet, everyone wants to hear

(a) good music
(b) fine words
(c) a new poem
(d) new and noble thoughts

3.
The words can free a thought which is

(a) in a prison
(b) in the mind
(c) in the eyes
(d) nowhere

4.
the real beauty is in

(a) new and beautiful ideas
(b) beautiful words
(c) beautiful expression
(d) surprising words

5.
The word longing is a

(a) gerund
(b) verb
(c) noun
(d) adjective

Answers :

  1. (c) soul
  2. (d) new and noble thoughts
  3. (b) in the mind
  4. (a) new and beautiful ideas
  5. (c) noun

Textual Questions

Question 1.
With your partner, complete the following sentences in your own words using the ideas in the poem.

  1. Do not let a thought shrivel and die because ________ .
  2. English is a ________ with words that everyone can play.
  3. One has to match ________ .
  4. Words are the ________ of thought.

Answer :

  1. it may be a ‘marvellous new surprise’ which everyone is longing to hear.
  2. wonderful game of matching thoughts.
  3. the words to the brightest thought in the mind.
  4. food and dress of thought.

Question 2.
In groups of four discuss the following lines and their meanings.

  1. All that you do is match the words To the brightest thoughts in your head
  2. For many of the loveliest things Haye never yet been said
  3. And everyone’s longing today to hear Some fresh and beautiful thing
  4. But only words can free a thought From its prison behind your eyes

Answer :

  1. You have only to find the nearest possible words which seem to trans¬late your best thoughts.
  2. Many of the most beautiful ideas are still waiting for proper expres¬sion.
  3. Today everyone is very eager to hear something new and beautiful.
  4. Words are imprisoned in the mind. They will remain so until and un¬less you find proper words to give them expression. This alone will give them freedom from the prison of mind.

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Vocation Extra Questions and Answers Class 6 English Honeysuckle

Online Education for Vocation Extra Questions and Answers Class 6 English Honeysuckle

Here we are providing Online Education for Vocation Extra Questions and Answers Class 6 English Honeysuckle, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

Online Education for Vocation Extra Questions and Answers Class 6 English Honeysuckle

Vocation Extra Questions and Answers Short Answer Type

Your partner and you may now be able to answer these questions.

Vocation Poem Extra Questions And Answers Class 6 Question 1.
Who is the speaker in the poem? Who are the people the speaker meets? What are they doing?
Answer:
A school-going child speaks in the poem. The speaker meets a hawker, a gardener and a watchman. The hawker sells bangles. The gardener digs the ground. The watchman keeps a watch in the street at night.

Vocation Class 6 Questions And Answers Question 2.
What wishes does the child in the poem make? Why does the child want to be a hawker, a gardener, or a watchman? Pick out the lines in each stanza, which tell us this.
Answer:
The child in the poem wants to be a hawker, a gardener, and a watchman. When he looks at the hawker, he wishes he could also spend his day on the road crying “Bangles, crystal bangles!” He feels that there is nothing to hurry the hawker on. There is no road he must take, no place he must go to, and no fixed time when he must come home. These are the things that he cannot do himself and therefore, he wants to be a hawker so that he could do all these things.

Next, he wishes he was a gardener because a gardener does what he likes with his spade. He soils his clothes with dust. Nobody scolds him if he gets baked in the sun or gets wet. Therefore, if the little child was a gardener, nobody would stop him from digging. Finally, he sees the watchman and wants to be like the watchman so that he could walk through dark and lonely streets all night with his lantern and chase shadows.

When he is put to bed and is not allowed to roam outside, he see the watchman swinging his lantern with his shadow at his side and he feels that the watchman never even once has to go to bed in his entire life. Therefore, he wants to be a hawker, a gardener, and a watchman so that he could do all the things they did as he could not do them being a child.

Vocation Poem Class 6 Questions And Answers Pdf Question 3.
From the way the child envies the hawker, the gardener and the watchman, we can guess that there are many things the child has to do, or must not do. Make a list of the do’s and don’ts that the child doesn’t like. The first line is done for you.

The child must
come home at a fixed time.
………………..
……………….

The child must not
get his clothes dirty in the dust.
……………..
……………….
Now add to the list your own complaints about the things you have to do, or must not do.
Answer:
The child must
come home at a fixed time
Go to bed when it get dark
Go to school everyday
Please do yourself.

The child must not
get his clothes dirty in the dust.
Get baked in the sun or get wet
Walk on dark and lonely street at night.

Vocation Question Answer Class 6 Question 4.
Like the child in the poem, you perhaps have your own wishes for yourself. Talk to your friend, using “I wish I were…”
Answer:
Please do yourself.

Vocation Chapter Question Answer Class 6 Question 5.
Find out the different kinds of work done by the people in your neighbourhood. Make different cards for different kinds of work. You can make the card colourful with pictures of the persons doing the work.
Answer:
Please do yourself.

Vocation Extra Questions and Answers Reference of Context

Vocation Poem Class 6 Questions And Answers Question 1.
When the gong sounds ten in the morning and
I walk to school by our lane,
Every day I meet the hawker crying, “Bangles,
crystal bangles!”
There is nothing to hurry him on, there is no
road he must take, no place he must go to, no
time when he must come home.
I wish I were a hawker, spending my day in
the road, crying, “Bangles, crystal bangles!”

Explanation
The poet walks to the school lane when the gong rang at ten in the morning. On the way, he meets a Bangle seller who sells crystal bangles. He need not to hurry and worry as the poet has to. He is jealous of the hawker because he is not restricted from going anywhere. He is also not forced to reach home on time. The poet wishes to be a hawker and sell bangles in the streets.

(i) Who wrote the poem?
(ii) At what time does the poet go to school?
(iii) What does the hawker cry to sell bangles?
(iv) What does the poet say about the life of the hawker?
(v) Give the meaning of‘crystal’.
Answer:
(i) Rabindranath Tagore wrote the poem.
(ii) The poet goes to school at 10 a.m.
(iii) The hawker cries “Bangles, crystal bangles” to sell his bangles.
(iv) The poet says that the hawker has freedom.
(v) Highly transparent glass.

Vocation Poem Questions And Answers Class 6 Question 2.
When at four in the afternoon I come back from the school,
I can see through the gate of that house the gardener digging the ground.
He does what he likes with his spade, he soils
his clothes with dust, nobody takes him to
task, if he gets baked in the sun or gets wet.
I wish I were a gardener digging away at the
garden with nobody to stop me from digging.

Explanation
The poet witnesses the freedom of choice of the gardener whom he comes across on the way home. The gardener digs the ground with the spade. His dress is soiled with dust, but still he is not scolded by anyone. He is free to be in sunlight or get wet in the rains. The poet wishes to bask in the sun and get drenched in the rains. He wants to enjoy freedom of digging the ground.

(i) Whom does the poet see at four in the afternoon?
(ii) Where does the poet see him?
(iii) What does the gardener do with the spade?
(iv) What is the wish of the poet?
(v) Give the meaning of baked.
Answer:
(i) The poet sees the gardener at four in the afternoon.
(ii) The poet sees him through the gate of a house.
(iii) The gardener does what he likes with his spade.
(iv) The poet wishes that nobody should stop him if he were a gardener.
(v) (a) Food cooked by dry heat in an oven.
(b) Stay in sunlight for long hours.

Vocation Poem Class 6 Extra Questions And Answers Question 3.
Just as it gets dark in the evening and my
mother sends me to bed,
I can see through my open window the
watchman walking up and down.
The lane is dark and lonely, and the street lamp
stands like a giant with one red give in its head.
The watchman swings his lantern and walks
with his shadow at his side, and never once
goes to bed in his life.
I wish I were a watchman walking the street
all night, chasing the shadow with my lantern.

Explanation
The poet’s mother compels the poet to slip into bed. The poet sees through his window a watchman doing his duty. The lanes are dark and desolate. The poet describes that he looks like a giant with one red eye in its head. The lantern saving here and there in his hand. The poet wants to chase his shadow like him.

(i) Who sends the poet to bed?
(ii) Whom does he see through his window?
(iii) How does the poet describe the street lamp?
(iv) What was his reason of comparison?
(v) Choose the word similar to ‘torch’.
Answer:
(i) The poet’s mother send him to bed.
(ii) He sees a watchman through his window.
(iii) The poet describes the street lamp as a giant with one red eye in its head.
(iv) He does not wish to go to bed early and wants to roam around in streets chasing his own shadow.
(v) Lantern.

The Living Organisms and Their Surroundings Class 6 Extra Questions and Answers Science Chapter 9

Online Education for The Living Organisms and Their Surroundings Class 6 Extra Questions and Answers Science Chapter 9

In this page, we are providing Online Education for The Living Organisms and Their Surroundings Class 6 Extra Questions and Answers Science Chapter 9 pdf download. NCERT Extra Questions for Class 6 Science Chapter 9 The Living Organisms and Their Surroundings with Answers will help to score more marks in your CBSE Board Exams.

Online Education for Class 6 Science Chapter 9 Extra Questions and Answers The Living Organisms and Their Surroundings

Extra Questions for Class 6 Science Chapter 9 The Living Organisms and Their Surroundings with Answers Solutions

The Living Organisms and Their Surroundings Class 6 Extra Questions Very Short Answer Type

Class 6 Science Chapter 9 Extra Questions And Answers Question 1.
Name the process by which living things obtain energy from food.
Answer:
Respiration

Class 6 Science Chapter 9 Extra Questions Question 2.
Name two aquatic plants which are completely submerged in water.
Answer:
Lily and lotus

Ncert Class 6 Science Chapter 9 Extra Questions Question 3.
Name two terrestrial habitats.
Answer:
Deserts, mountains

The Living Organisms And Their Surroundings Class 6 Questions And Answers Question 4.
What are two components of the habitat?
Answer:
(i) Biotic components
(ii) Abiotic components

Class 6 Science Ch 9 Extra Questions Question 5.
Name one characteristic which tells us that seeds are living things.
Answer:
They grow into a plant when get favourable conditions.

Living Organisms And Their Surroundings Class 6 Extra Questions Question 6.
Name two animals which live in the arboreal habitat.
Answer:
(i) Birds
(ii) Monkey

Ncert Solutions For Class 6 Science Chapter 9 Extra Questions Question 7.
Mention few aquatic plants found in a pond.
Answer:
Water hyacinth, water lily, lotus, Hydrilla, etc.

Class 6 Science Chapter 9 Extra Question Answer Question 8.
Name the habitats of following plants:
(a) Cactus
(b) Hydrilla
Answer:
(a) Cactus: Desert
(b) Hydrilla: Aquatic

Living Organisms And Their Surroundings Extra Questions Question 9.
Name some plants which live in dry areas.
Answer:
Plants like cactus, Acacia, pine, prickly pear live in dry areas.

The Living Organisms Characteristics And Habitats Extra Questions Question 10.
Name two aquatic habitats.
Answer:
Oceans, ponds

Extra Questions For Class 6 Science Chapter 9 Question 11.
Write the names of two sea animal which have nostrils.
Answer:
Dolphins and whales

Living Organisms And Their Surroundings Class 6 Hots Questions Question 12.
What is stimuli?
Answer:
The changes in our surrounding that makes us respond to them are called stimuli.

Chapter 9 Science Class 6 Extra Questions Question 13.
How does gills help a fish?
Answer:
Gills help fish to take-up oxygen dissolved in water.

Living Organisms And Their Surroundings Class 6 Questions And Answers Question 14.
Name an animal in which the exchange of gases, during respiration, take place through its skin.
Answer:
The earthworm breathes through the skin.

Class 6 Chapter 9 Science Extra Questions Question 15.
Name one animal which is adapted to live in water as well as land.
Answer:
Frog

The Living Organisms and Their Surroundings Class 6 Extra Questions Short Answer Type

Question 1.
What is adaptation?
Answer:
The change in specific features or certain habits, which enables a plant or an animal to live in its surroundings is called adaptation.

Question 2.
Define ecology.
Answer:
The study of relationship between living organism and their surroundings is called ecology.

Question 3.
What is environment?
Answer:
Our physical surrounding is called environment.

Question 4.
What is ocean?
Answer:
A very large body of salt water that covers nearly three-fourths of the surface of the earth is called ocean.

Question 5.
Where does a camel lives?
Answer:
A camel lives in a hot desert where there is scarcity of water.

Question 6.
What is habitat?
Answer:
The place or surroundings where a plant or an animal lives is called its habitat.

Question 7.
What is terrestrial habitat?
Answer:
A land based habitat is called a terrestrial habitat.

Question 8.
What is acclimatisation?
Answer:
Small changes that take place in the body of a single organism over short periods, to overcome small problems due to changes in the surroundings, is called acclimatization.

Question 9.
What is reproduction?
Answer:
The process by which living organisms produce new member of their species is called reproduction.

Question 10.
What is excretion?
Answer:
The removal of waste substances from the body of a living organism is called excretion.

Question 11.
What are organisms?
Answer:
The living things are called organisms.

Question 12.
What are biotic components?
Answer:
The living things such as plants, animals and microorganisms in a habitat are its biotic components.

Question 13.
Explain abiotic components.
Answer:
Various non-living things such as rocks, soil, air and water in a habitat constitute its abiotic components.

Question 14.
Why do fish have slippery scales on their bodies?
Answer:
These scales protect the fish from external damage from sharp objects and also help in easy movement through water.

Question 15.
Give three adaptive features in desert plants.
Answer:

  1. Well developed root systems.
  2. Leaves either very small or converted to spines.
  3. Stem is green and fleshy in some plants to carry out photosynthesis.

The Living Organisms and Their Surroundings Class 6 Extra Questions Long Answer Type

Question 1.
List the important characteristics of living things.
Answer:
Following are the important characteristics of living things:

  1. Living things need food, air and water.
  2. Living things grow.
  3. Living things reproduce themselves.
  4. Living things respire.
  5. Living things are made up of living cells.
  6. Living things excrete.
  7. Living things have a definite lifespan.

Question 2.
How does the desert animals prevent the loss of water from their body?
Answer:

  1. Many animals living in desert remain inactive during the day and become active during night to prevent the loss of water from their body. Such animals are called nocturnal.
  2. Certain animals hide themselves in burrows with gelatinous secretion and sleep for about 8 to 9 months in a year. This is called aestivation or summer sleep.

Question 3.
How are plants adapted to aquatic habitat?
Answer:

  1. In aquatic plants, roots are much reduced in size and their main function is to hold the plant on its place.
  2. The stems may be reduced or long, slender, flexible and spongy. The air spaces in spongy stems make them buoyant.
  3. The leaves are thin, large and flat with waxy surface as in lotus and water lily. This protects leaves from wetting and decaying.
  4. The leaves of submerged plants are thin and narrow. Hydrilla and Vallisneria are submerged plants and have thin and narrow leaves. Such leaves allow the water to flow without damaging them.

Question 4.
What is respiration?
Answer:
All the living things need energy to grow, move and stay alive. They get this energy from food through respiration. Respiration is the chemical process in which food taken by an organism combines with oxygen to release energy. This energy is used by the organism to carry out its various life processes. Carbon dioxide and water are the other products of the process of respiration.

Question 5.
What is habitat? Explain briefly.
Answer:
All the living organisms (plants and animals) prefer to live in those places which are best suited to their needs. The place or surroundings where a plant or an animal live is called its habitat.

Habitat can be divided into two main groups:
(i) Terrestrial habitat
(ii) Aquatic habitat
A land based habitat is called terrestrial habitat and a water based habitat is called aquatic habitat.

Question 6.
Differentiate between biotic and abiotic components.
Answer:

Abiotic components Biotic components
1. The term ‘biotic’ means living. 1. The term ‘abiotic’ means non-living.
2. All the living thing in a habitat are biotic components. 2. All non-living things in a habitat are known as abiotic components.
3. Example, plants, animals, etc. 3. Example, air, soil, etc.

Question 7.
Differentiate between xerophytes and hydrophytes.
Answer:

Xerophytes Hydrophytes
1. Plants are adapted to dry conditions. 1. Plants are adapted to aquatic conditions.
2. Leaves are reduced in size or are modified to spines to reduce transpiration. 2. Leaves are broad for floating or ribbon-shaped to allow water current through it.
3. Roots are long and well developed. 3. Roots are not very well developed. Their main function is just anchoring the plant.
4. Example, Cactus, Acacia 4. Example, Hydrilla, Vallisneria

The Living Organisms and Their Surroundings Class 6 Extra Questions HOTS

Question 1.
What is acclimatization? How it differs from adaptation?
Answer:
Small changes in an organism to overcome small changes in the surrounding is called acclimatization. Whereas adaptation is permanent ability of an organism to make themselves suitable for living in a particular environment. Adaptation is slow and gradual process whereas acclimatization is comparatively a quick method.

Question 2.
Can you name some plant parts, apart from seed, which give rise to a new plant?
Answer:
Leaves, stem, bulb, offset, corm, etc., of some plants can give rise to a new plant.

Question 3.
Is seed a living thing?
Answer:
Yes, seed is a living thing as it has living embryo in it. It is in dormant state which could be break by subjecting it to favourable conditions.

Question 4.
Differentiate between aestivation and hibernation.
Answer:

Aestivation Hibernation
1. It is summer sleep 1. It is winter sleep.
2. Animals rests in cool or shady and moist place. 2. Animals rest in a warm place.
3. It lasts for hot dry day time as nights are cooler. 3. It is of longer duration and lasts for the whole duration of winter.
4. Activators are snails, earthworms, bees, salamanders, frogs, toads, lizards, snakes, mud turtles, etc. 4. Hibernators are polar bear, kangaroo, mouse, squirrels, etc.

Question 5.
Why do mountaineers carry oxygen cylinders with them?
Answer:
As we go higher the air gets less dense. There is lack of supply of oxygen. Thus, mountaineers carry oxygen cylinders with them.

The Living Organisms and Their Surroundings Class 6 Extra Questions Value-Based (VBQs)

Question 1.
Radha while learning about the characteristics of living organisms studied that living organism excrete their waste out of the body. She remembered that plants are also living organisms. But she wondered how plants excrete their waste. She searched in internet to solve her query.
(a) What are the characteristics of living organisms?
(b) Which component is constituted by plants?
(c) How do plant excrete their waste materials?
(d) What value of Radha is shown here?
Answer:
(a) Living organisms can

  1. grow
  2. reproduce
  3. excrete
  4. respire
  5. move
  6. show response to stimuli

(b) Biotic component
(c) In plants different modes of excretion are present. They loses their gaseous waste through their stomata. Deciduous plants transfer their toxic waste to the leaves which fall on maturity. Excess water is lost through transpiration.
(d) Radha is curious, responsible and hardworking.

Question 2.
Gita lives in Tamil Nadu. Her family planned to visit a hilly area during her school vacation. She was so excited. When she reached there, she experienced breathing problem while walking or running. She got worried that something might have happened to her. But her father consoled her and said, that this is normal and she will be fine after few days of staying there.
(a) Why does Gita experience breathing problem in hilly area?
(b) How will she be fine after some days?
(c) What do this process of adjusting to environment called?
(d) What values of Gita’s father is shown here?
Answer:
(a) In hilly areas oxygen level is very low. So, Gita experienced breathing problem.
(b) Her body will make small changes, like increased red blood cells, to cope with decreased amount of oxygen.
(c) Acclimatisation
(d) Gita’s father is caring, loving, responsible and have scientific aptitude.

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1.

Board CBSE
Textbook NCERT
Class Class 6
Subject Maths
Chapter Chapter 12
Chapter Name Ratio and Proportion
Exercise  Ex 12.1
Number of Questions Solved 16
Category NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Question 1.
There are 20 girls and 15 boys in a class.
(a) What is the ratio of a number of girls to the number of boys?
(b) What is the ratio of a number of girls to the total number of students in the class?
Solution :
(a) Ratio of number of girls to the number of boys
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 1
(b) Total number of students in the class = 20 + 15 = 35
∴ Ratio of number of girls to the total number of students in the class
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 2

Question 2.
Out of 30 students in a class, 6 like football, 12 like cricket and remaining like tennis. Find the ratio of:
(a) Number of students liking football to a number of students liking tennis.
(b) Number of students liking cricket to the total number of students.
Solution :
(a) Number of students liking tennis = 30-(6+ 12) = 30 – 18 = 12
∴ Ratio of number of students liking football to number of students liking tennis
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 3
(b) Number of students liking cricket to total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 4

Question 3.
See the figure and find the ratio of:
(a) Number of triangles to the number of circles inside the rectangle.
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 5
(b) Number of squares to all the figures inside the rectangle.
(c) Number of circles to all the figures inside the rectangle.
Solution :
(a) Number of triangle inside the rectangle = 3 . , Number of circles inside the rectangle = 2 Ratio of number of triangles to the number of circles inside the rectangle = \(\frac{ 3 }{ 2 }\) =3:2.
(b) Number of squares inside the rectangle = 2 Number of all the figures inside the rectangle = 7
∴ Ratio of number of squares to all the figures 2
inside the rectangle = \(\frac{ 2 }{ 7 }\) =2:7.
(c) Ratio of number of circles to all the figures inside the rectangle = \(\frac{ 2 }{ 7 }\) =2:1.

Question 4.
Distance travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar.
Solution :
Ratio of speed of Hamid to the speed of
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 31
Question 5.
Fill in the following blanks:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 6
Solution :
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 7
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 8

Question 6.
Find the ratio of the following :
(a) 81 to 108
(b) 98 to 63
(c) 33 km to 121 km
(d) 30 minutes to 45 minutes.
Solution :
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 9
Question 7.
Find the ratio of the following :
(a) 30 minutes to 1.5 hours
(b) 40 cm to 1.5 m
(c) 55 paise to ₹ 1
(d) 500 ml to 2 litres.
Solution :
(a) 1.5 hours = 1.5 × 60 minutes = 90 minutes
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 10
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 11

Question 8.
In a year, Seema earns- ₹ 1,50.000 and saves ₹ 50,000. Find the ratio of:
(a) Money that Seema earns to the money she saves.
(b) Money that she saves to the money that she spends.
Solution :
(a) Ratio of money that Seema earns to the money she saves
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 12
(b) Money that she spends
= ₹ 1,50,000 – ₹ 50,000 = ₹ 1,00,000
∴ Ratio of money she saves to the money she spends
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 13
Question 9.
There are 102 teachers in a school of 3300 students. Find the ratio of the number of teachers to the number of students.
Solution :
Ratio of the number of teachers to the number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 14
Question 10.
In a college, out of4320 students, 2300 are girls. Find the ratio of:
(a) Number of girls to the total number of students.
(b) Number of boys to the number of girls.
(c) Number of boys to the total number of students.
Solution :
(a) Ratio of number of girls to the total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 15
(b) Number of boys = 4320 – 2300 = 2020
∴ Ratio of number of boys to the number of girl
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 16
(c) Ratio of number of boys to the total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 17
Question 11.
Out of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of:
(a) Number of students who opted basketball to the number of students who opted table tennis.
(b) Number of students who opted cricket to the number of students opting basketball.
(c) Number of students who opted basketball to the total number of students.
Solution :
(a) Number of students opting table tennis = 1800 – (750 + 800) = 1800 -1550 = 250
∴ Ratio of number of students opting basketball to number of students opting table tennis
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 18
(b) Ratio of number of students opting cricket to the number of students opting basketball
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 19
(c) Ratio of number of students opting basketball to the total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 20
Question 12.
Cost of a dozen pens is ₹ 180 and cost of 8 ball pens is ₹ 56. Find the ratio of cost of a pen to the cost of a ball pen.
Solution :
1 dozen =12 items
∴ Cost of 12 pens = ₹ 180
∴ Cost of 1 pen = ₹ \(\frac{ 180 }{ 12 }\) = ₹ 15
∴ Cost of 8 ball pens = ₹ 56
∴ Cost of 1 ball pen = ₹ \(\frac{ 56 }{ 8 }\) = ₹ 7
∴ Ratio of cost of a pen to the cost of a ball 15 pen = \(\frac{ 15 }{ 7 }\) =15:7.

Question 13.
Consider the statement: Ratio of breadth and length of a hall 2: 5. Complete the following table that shows some possible breadths and lengths of the hall.
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 21
Solution :
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 22
Hence, the completed table is as follows:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 23
Question 14.
Divide 20 pens between Sheela and Sangeeta in the ratio 3: 2.
Solution :
Total number of pens = 20 Ratio = 3:2
Sum of the parts = 3 + 2 = 5
∴ Sheel’s shae = \(\frac{ 3 }{ 5 }\) × 20 = 12 and, Samgeeta’s share = \(\frac{ 2 }{ 5 }\) × 20 = 8

Question 15.
Mother wants to divide ₹ 36 between her daughters Shreya and Bhoomika in the ratio of their ages. If the age of Shreya is 15 years and age of Bhoomika is 12 years, find how much Shreya and Bhoomika will get?
Solution :
Total money = ₹ 36
The ratio of the ages of Shreya and Bhoomika
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 24
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 25
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 26
Hence, Shreya will get ₹ 20 and Bhoomika will get ₹ 16.

Question 16.
Present age of the father is 42 years and that of his son is 14 years. Find the ratio of :
(a) Present age of father to the present age of the son.
(b) Age of the father to the age of son, when the son was 12 years old.
(c) Age of father after 10 years to the age of son after 10 years.
(d) Age of father to the age of son when father was 30 years old.
Solution :
(a) Ratio of the present age of father to the present age of the son
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 27
(b) Son was 12 years old 14 – 12 = 2 years before
Age of the father 2 years before = 42 – 2 = 40 years
∴ Ratio of the age of the father to the age of the son. when son was 12 years old
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 28
(c) Age of father after 10 years = 42 + 10 = 52 years
Age of son after 10 years = 14 + 10 = 24 years
∴ Ratio of age of father after 10 years to the age of son after 10 years
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 29
(d) Father was 30 years old 42 – 30 = 12 years before
Age of son 12 years before = 14 – 12 = 2 years
∴ Ratio of the age of father to the age of son when father was 30 years old
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 30

 

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Separation of Substances Class 6 Extra Questions and Answers Science Chapter 5

Separation of Substances Class 6 Extra Questions and Answers Science Chapter 5

In this page, we are providing Separation of Substances Class 6 Extra Questions and Answers Science Chapter 5 pdf download. NCERT Extra Questions for Class 6 Science Chapter 5 Separation of Substances with Answers will help to score more marks in your CBSE Board Exams. https://ncertmcq.com/extra-questions-for-class-6-science/

Class 6 Science Chapter 5 Extra Questions and Answers Separation of Substances

Extra Questions for Class 6 Science Chapter 5 Separation of Substances with Answers Solutions

Separation of Substances Class 6 Extra Questions Very Short Answer Type

Class 6 Science Chapter 5 Extra Questions Question 1.
What are the components of air?
Answer:
Oxygen, carbon dioxide, nitrogen, etc.

Separation Of Substances Class 6 Extra Questions Question 2.
What are the components of milk?
Answer:
Milk-proteins, calcium, cream and water.

Separation Of Substances Class 6 Questions And Answers Question 3.
What are the types of mixture?
Answer:
Heterogeneous mixtures and homogeneous mixtures.

Class 6 Science Ch 5 Extra Questions Question 4.
Name the process used to separate heavier and lighter components of a mixture.
Answer:
Winnowing

Ncert Class 6 Science Chapter 5 Extra Questions Question 5.
Mention one purpose of separating the constituents of a mixture.
Answer:
To remove the undesirable substances.

Separation Of Substances Extra Questions Question 6.
When handpicking is used?
Answer:
Handpicking is used to separate undesirable components having different shape, size, colour and are present in small amount.

Questions On Separation Of Substances Class 6 Question 7.
Which type of separation process is used in cashewnut factories?
Answer:
Sieving

Separation Of Substances Class 6 Extra Questions Answers Question 8.
Name the process used to obtain salt from sea water.
Answer:
Evaporation

Separation Of Substances Question Answer Question 9.
Write opposite of the process of condensation.
Answer:
Evaporation

Extra Questions For Class 6 Science Chapter 5 Question 10.
What is effect of temperature on solubility?
Answer:
Solubility increases when temperature increases.

Class 6 Chapter 5 Science Extra Questions Question 11.
Name the process of obtaining clear water from muddy water in which alum is used.
Answer:
Loading

Science Class 6 Chapter 5 Extra Questions Question 12.
Which method is used to separate a mixture of tea leaves and iron filings?
Answer:
By magnet

Class 6 Separation Of Substances Extra Questions Question 13.
Which gas dissolved in water helps aquatic animals to breathe?
Answer:
Oxygen gas

Extra Questions On Separation Of Substances Class 6 Question 14.
Name the method by which you can separate butter from milk.
Answer:
Centrifugation

Separation Of Substances Questions And Answers Question 15.
Which liquid is called as universal solvent?
Answer:
Water

Question 16.
Name some materials that are used as filters.
Answer:
Cotton, ceramic, fine cloth, filter paper, etc.

Question 17.
Give one example of sieving used in everyday life.
Answer:
Separation of bran from flour.

Question 18.
Which substance is used for loading?
Answer
Alum

Question 19.
Which process is used to separate bacteria from water?
Answer:
Filtration by using bacteria proof filters.

Question 20.
Name the process of separating two immiscible liquids.
Answer:
Decantation

Separation of Substances Class 6 Extra Questions Short Answer Type

Question 1.
Why mixtures need to be separated?
Answer:
The main reason for separating the mixtures are:

  1. To remove undesirable substances.
  2. To get desirable substances.
  3. To obtain highly pure substances.

Question 2.
What is handpicking? When this method is used?
Answer:
The method in which the constituents are separated by simply picking them up by hand is called hand-picking. It is used when there is a difference in size, colour, shape of desirable and undesirable constituents.

Question 3.
What is evaporation? What is the significance of this process?
Answer:
The changing of liquid into vapours is called evaporation. The process of evaporation is used on a large scale to obtain common salt from sea water.

Question 4.
What is threshing?
Answer:
The process of separating grains from the stalks is called threshing.

Question 5.
What is the use of decantation?
Answer:
Decantation is used to separate insoluble solids from liquids. Two immiscible liquids are also separated by this process.

Question 6.
What is a mixture?
Answer:
When two or more than two substances are mixed together in any ratio then it is called a mixture.

Question 7.
What is decantation?
Answer:
Decantation is the process of separating insoluble solids from liquids. A suspension of solid particles in liquid is allowed to stand for some time. Solid particles settle down at the bottom. The clear water is then transferred into another beaker.

Question 8.
State one use of the method of winnowing.
Answer:
The method of winnowing is used to separate husk from various types of grain like wheat, rice, etc. Give one use of the handpicking method of separating mixtures in daily life. The method of handpicking is usually used to separate undesirable substances such as small pieces of stones from wheat, rice and pulses.

Question 9.
Define the term sedimentation.
Answer:
The process in which heavier, insoluble solid settles down in a solution is called sedimentation.

Separation of Substances Class 6 Extra Questions Long Answer Type

Question 1.
Elaborate the process of filtration.
Answer:
Filtration is the process of separating an insoluble solid from a liquid with the help of a filtering agent like filter paper, cloth, strainer, etc. During filtration, the solid insoluble substance is retained at the filter paper as residue while the liquid free from any suspended matter passes through the filter paper and is collected as filtrate.

There are certain soluble components infiltrate which can be separated by the process of evaporation followed by crystallization.

Question 2.
What is meant by saturated and unsaturated solution?
Answer:

  • Saturated solution: At any particular temperature, a solution that has dissolved as much solute as it is capable of dissolving, is said to be a saturated solution.
  • Unsaturated solution: A solution in which more quantity of solute can be dissolved without raising the temperature of the solution is called unsaturated solution.

Question 3.
What is the effect of temperature on a saturated solution?
Answer:
(i) When a saturated solution is heated to a higher temperature, then it becomes unsaturated because the solubility of solute increases with increase in temperature of the solution.
(ii) When a saturated solution is cooled to a lower temperature, then some of the dissolved solute separates out in the form of solid crystal because the solubility of solute decreases on cooling the solution.

Question 4.
What is the importance of centrifugation? How it is done?
Answer:
Centrifugation is the process of separating suspended particles from a liquid by rotating the liquid at a high speed.

The mixture is taken in a closed bottle and rotated at a high speed. The heavy particles settle at the bottom while light particles remains behind. The method is also used to separate cream from milk. Cream being lighter than milk, floats at the top of the mixture.

Question 5.
What is loading? How will you obtain clear water from muddy river water by the process of loading?
Answer:
The suspended small particles of muddy water are negatively charge which inhibit them to settle down due to repulsion. On adding alum to this muddy water, removes the negative charge from the particles. This particles forms clump easily, become heavier and settles down.

This process is called loading. Loading helps in purification of water from small suspended particles which do not settles down easily and quickly. The clear water after settling down of suspended particles is decanted in another container and is comparatively clearer.

Separation of Substances Class 6 Extra Questions HOTS

Question 1.
Rahul by mistake mixed sugar with salt. What method he must adopt to quickly separate this mixture?
Answer:
He must use the method of sieving for separating salt and sugar.

Question 2.
Can we separate the mixture of sugar and milk?
Answer:
No

Question 3.
Which method of separation will you adopt to separate a mixture of wheat flour, moong dal and chana?
Answer:
We will adopt the method of sieving followed by handpicking to separate the mixture. Sieving will separate wheat flour from moong dal and chana. Handpicking will separate moong dal from chana. Sieve with appropriate pores can also be used to separate moong dal from chana.

Question 4.
Suggest any two methods to separate suspended particles of mud from water.
Answer:
Loading with alum and centrifugation.

Question 5.
Is there any method through which we can separate different components of ink?
Answer:
Chromatography technique.

Separation of Substances Class 6 Extra Questions Value Based Question (VBQs)

Question 1.
Some shopkeepers mix many cheap and harmful substances in the food materials. This process is called adulteration. Anybody who are involved in such kind of illegal practices are liable for imprisonment.
(a) Why shopkeepers mix cheap and harmful substances in food materials?
(b) How will you separate impurities from grains and pulses?
(c) What values of shopkeepers are shown here?
Answer:
(a) Shopkeepers add these undesirable substances to increase the quantity of the food materials and thus their profit.
(b) Through handpicking.
(c) Shopkeepers observing such practices are greedy, self-centred, criminal-minded and soulless.

Question 2.
There were guests at Sonam’s house. Sonam thought of making lemonade for them. She dissolved sugar in chilled water and observe that sugar was taking long time to dissolve. Meanwhile, Sonam’s mother came and asked her to transfer the upper chilled water in another container and then add water at normal temperature to this sugar settled at bottom.
Sonam then found it easy to dissolve the sugar for lemonade.
(a) What is saturated solution?
(b) What is the effect of temperature on the capacity of water in dissolving substances?
(c) What will happen if we cool a supersaturated solution?
(d) What value of Sonam is shown here?
Answer:
(a) A saturated solution is the solution which cannot dissolve any more solute in it at a given temperature.
(b) With increase in temperature solubility of a substance increases in water and vice versa.
(c) When a supersaturated solution is cooled, it form crystals of the salt. This process is known as crystallization.
(d) Sonam is a good host, learner, helpful girl.

Extra Questions for Class 6 Social Science SST with Answers

Extra Questions for Class 6 Social Science SST with Answers

Online Education for NCERT Class 6 Social Science Extra Questions and Answers

NCERT Class 6 Geography Extra Questions

  1. The Earth in the Solar System Class 6 Extra Questions
  2. Globe Latitudes and Longitudes Class 6 Extra Questions
  3. Motions of the Earth Class 6 Extra Questions
  4. Maps Class 6 Extra Questions
  5. Major Domains of the Earth Class 6 Extra Questions
  6. Major Landforms of the Earth Class 6 Extra Questions
  7. Our Country India Class 6 Extra Questions
  8. India Climate Vegetation and Wildlife Class 6 Extra Questions

NCERT Class 6 History Extra Questions

  1. What, Where, How and When? Class 6 Extra Questions
  2. On The Trail of the Earliest People Class 6 Extra Questions
  3. From Gathering to Growing Food Class 6 Extra Questions
  4. In the Earliest Cities Class 6 Extra Questions
  5. What Books and Burials Tell Us Class 6 Extra Questions
  6. Kingdoms, Kings and an Early Republic Class 6 Extra Questions
  7. New Questions and Ideas Class 6 Extra Questions
  8. Ashoka, The Emperor Who Gave Up War Class 6 Extra Questions
  9. Vital Villages, Thriving Towns Class 6 Extra Questions
  10. Traders, Kings and Pilgrims Class 6 Extra Questions
  11. New Empires and Kingdoms Class 6 Extra Questions
  12. Buildings, Paintings, and Books Class 6 Extra Questions

NCERT Class 6 Civics Extra Questions

  1. Understanding Diversity Class 6 Extra Questions
  2. Diversity and Discrimination Class 6 Extra Questions
  3. What is Government Class 6 Extra Questions
  4. Key Elements of a Democratic Government Class 6 Extra Questions
  5. Panchayati raj Class 6 Extra Questions
  6. Rural Administration Class 6 Extra Questions
  7. Urban Administration Class 6 Extra Questions
  8. Rural Livelihoods Class 6 Extra Questions
  9. Urban Livelihoods Class 6 Extra Questions
Extra Questions for Class 6 English Honeysuckle, A Pact with the Sun

Online Education Extra Questions for Class 6 English Honeysuckle, A Pact with the Sun

Online Education CBSE Extra Questions for Class 6 English: Here we are providing NCERT Extra Questions for Class 6 English Honeysuckle, A Pact with the Sun. Students can get Class 6 English NCERT Solutions, Chapter Wise CBSE Class 6 English Extra Important Questions and Answers were designed by subject expert teachers.

Want to explore more about the English language in class 6 to score more marks in the final exam? Then, this article is the best choice for you. Here we have compiled a list of extra questions for class 6 English which are created by subject experts based on NCERT Syllabus prescribed by CBSE. View the list & access the links to download important English questions with answers free pdf and prepare well for the annual examination.

Online Education Extra Questions for Class 6 English Honeysuckle, A Pact with the Sun Important Questions

For more practice on the English language, checkout the below-given pdf links & prepare well with Extra Questions for Class 6 English with Answers.

Extra Questions for Class 6 English Honeysuckle Prose

  1. Who Did Patrick’s Homework? Extra Questions
  2. How the Dog Found Himself a New Master? Extra Questions
  3. Taro’s Reward Extra Questions
  4. An Indian-American Woman in Space : Kalpana Chawla Extra Questions
  5. A Different Kind of School Extra Questions
  6. Who I Am Extra Questions
  7. Fair Play Extra Questions
  8. A Game of Chance Extra Questions
  9. Desert Animals Extra Questions
  10. The Banyan Tree Extra Questions

Extra Questions for Class 6 English Honeysuckle Poem

  1. A House, A Home Extra Questions
  2. The Kite Extra Questions
  3. The Quarrel Extra Questions
  4. Beauty Extra Questions
  5. Where Do All the Teachers Go Extra Questions
  6. The Wonderful Words Extra Questions
  7. Vocation Extra Questions
  8. What if Extra Questions

Extra Questions for Class 6 English A Pact with the Sun

  1. A Tale of Two Birds Extra Questions
  2. The Friendly Mongoose Extra Questions
  3. The Shepherds Treasure Extra Questions
  4. The Old-Clock Shop Extra Questions
  5. Tansen Extra Questions
  6. The Monkey and the Crocodile Extra Questions
  7. The Wonder Called Sleep Extra Questions
  8. A Pact with the Sun Extra Questions
  9. What Happened to the Reptiles Extra Questions
  10. A Strange Wrestling Match Extra Questions

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NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1

NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1.

Board CBSE
Textbook NCERT
Class Class 6
Subject Maths
Chapter Chapter 11
Chapter Name Algebra
Exercise  Ex 11.1
Number of Questions Solved 1
Category NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1

Question 1.
Find the rule which gives the number of matchsticks required to make the following matchstick patterns. Use a variable to write the rule.
(a) A pattern of letter T asNCERT Solutions for Class 6 Maths Chapter 11 Algebra 1
(b) A pattern of letter Z as NCERT Solutions for Class 6 Maths Chapter 11 Algebra 2
(c) A pattern of letter U as NCERT Solutions for Class 6 Maths Chapter 11 Algebra 3
(d) A pattern of letter V as NCERT Solutions for Class 6 Maths Chapter 11 Algebra 4
(e) A pattern of letter E as NCERT Solutions for Class 6 Maths Chapter 11 Algebra 5
(f) A pattern of letter S as NCERT Solutions for Class 6 Maths Chapter 11 Algebra 6
(g) A pattern of letter A as NCERT Solutions for Class 6 Maths Chapter 11 Algebra 7
Solution.
(a) Number of matchsticks required = 2n
(b) Number of matchsticks required = 3n
(c) Number of matchsticks required = 3n
(d) Number of matchsticks required = 2n
(e) Number of matchsticks required = 5n
(f) Number of matchsticks required = 5n
(g) Number of matchsticks required = 6

Question 2.
We already know the rule for the pattern of letters L, C and F. Some of the letters from Q. 1 (given above) give us the same rule as that given by L. Which are these? Why does this happen?
Solution.
These letters are T and V. This happens since the number>of matchsticks require,d in each of them is 2.

Question 3.
Cadets are marching in a parade. There are 5 cadets in a row. What is the rule, which gives the number of cadets, given the number of rows? (Use n for the number of rows.)
Solution.
The number of cadets = 5n.

Question 4.
If there are 50 mangoes in a box, how will you write the total number of mangoes in terms of the number of boxes? (Use b for the number of boxes.)
Solution.
Total number of mangoes = 50b.

Question 5.
The teacher distributes 5 pencils per student. Can you tell how many pencils are needed, given the number of students? (Use for the number of students.)
Solution.
Number of pencils needed = 5s

Question 6.
A bird flies 1 kilometer in one minute. Can you express the distance covered by the bird in tertns of its flying time in minutes? (Use t for flying time in minutes.)
Solution.
Yes! / kilometers
The bird flies in one minute = 1 kilometer
The bird flies in / minutes = 1 x t kilometers
= kilometers

Question 7.
Radha is drawing a dot Rangoli (a beautified pattern of lines joining dots with chalk powder. She has 9 dots in a row. How many dots will her Rangoli have for r rows? How many dots are there if there are 8 rows? If there are 10 rows?
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 8
Solution.
∵ Number of dots in 1 row = 9
∴ Number of dots in r rows = 9 x r=9r
Number of dots in 8 rows = 9 x 8 = 72
Number of dots in 10 row = 9 x 10 = 90

Question 8.
Leela is Radha’s younger sister. Leela is 4 years younger than Radha. Can you write Leela’s age in terms of Radha’s age? Take Radha’s age to be x years.
Solution.
Yes! we can write Leela’s age in terms of Radha’s age.
Age of Radha = x years
∵ Leela is 4 years younger than Radha.
∴ Age of Leela = (x – 4) years

Question 9.
Mother has made laddus. She gives some laddus to guests and family members; still, 5 laddus remain. If the number of laddus mother gave away is l, how many laddus did she make?
Solution.
Number of laddus given away to guests and family members = l
Number of laddus remained = 5
∴ Number of laddus she made = 1 + 5

Question 10.
Oranges are to be transferred from larger boxes into smaller boxes. When a large box is emptied, the oranges from it fill two smaller boxes and still, 10 oranges remain, outside. If the number of oranges in a small box is taken to be x, what is the number of oranges in the larger box?
Solution.
Let the number of oranges in a smaller box box
∴ Number of oranges in two smaller boxes = 2x
Number of oranges remained outside = 10
∴ Number of oranges in the larger box = 2x+ 10

Question 11.
(a) Look at the following matchstick pattern of squares (figure). The squares are not separate. Two neighboring squares have a common matchstick. Observe the pattern and find the rule that gives the number of matchsticks in terms of the number of squares.
(Hint: If you remove the vertical stick at the end, you will get a pattern of Cs.)
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 9
(b) Figure gives a matchstick pattern of triangles. Av in Exercise 11(a) above, find the general rule that gives the number of matchsticks in terms of the number of triangles.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 10
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 11
Solution.
(a)
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 12

 Rule: Number of matchsticks required = 3x + I
where x is the number of squares.

(b)
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 13
Rule: Number of matchsticks required = 2x + 1,
where x is the number of triangles.

 

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RS Aggarwal Class 6 Solutions Chapter 24 Bar Graph Ex 24

RS Aggarwal Class 6 Solutions Chapter 24 Bar Graph Ex 24

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 24 Bar Graph Ex 24

Question 1.
Solution:
(i) The given bar graph shows the marks obtained by a student in each of the four subjects in an examination.
(ii) The student is poorest in Science.
(iii) The student is best in Mathematics.
(iv) He got more than 40 marks in Hindi and Mathematics.

Question 2.
Solution:
(i) The given bar graph shows the number of members in each of the 60 families of a colony.
(ii) 10 families have 3 members each.
(iii) 5 couples have no child.
(iv) A family of 4 members is most common.

Question 3.
Solution:
(i) The production was maximum in the 2nd week.
(ii) The production was minimum in the 4th week.
(iii) The average production is 720 per week.
(iv) 2400 cycles were produced in the first three weeks.

Question 4.
Solution:
(i) The given bar graph shows the different modes of transport to a school used by 51 students of a locality.
(ii) Maximum number of students use bicycle for going to school.
(iii) 14 students use bus for going to school.
(iv) 37 students do not use bus for going to school.

 

 

Hope given RS Aggarwal Solutions Class 6 Chapter 24 Bar Graph Ex 24 are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23

RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 23 Pictograph Ex 23

Question 1.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q1.1

Question 2.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q2.1

Question 3.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q3.1

Question 4.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q4.1

Question 5.
Solution:
(i) 24
(ii) 32
(iii) 40
(iv) 96 Ans.

Question 6.
Solution:
(i) 30
(ii) 24
(iii) Friday = 42
(iv) Saturday = 12 Ans.

 

Hope given RS Aggarwal Solutions Class 6 Chapter 23 Pictograph Ex 23 are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22

RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 22 Data Handling Ex 22

Question 1.
Solution:
(i) Data. The word data means information in the form of numerical figures.
(ii) Raw data. Data obtained in the original form is called raw data.
(iii) Array. Arranging the numerical figures (data) in an order i.e. ascending or descending order is called an array.
(iv) Tabulation of data. Arranging the given data in a systematic form in the form of a table is called tabulation of the data.
(v) Observations. Each numerical figure in a data is called an observation.
(vi) Frequency of an observation. The number of times a particular observation occurs is called its frequency.
(vii) Statistics. Statistics is a science which deals with the collection, presentation, analysis and interpretation of numerical data.

Question 2.
Solution:
Arranging the given data in ascending order, we get :
0, 0, 1, 1, 1, 1, 1, 1,2, 2, 2, 2,2, 2,2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q2.1

Question 3.
Solution:
Below is given the frequency distribution table of the given data :
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q3.1

Question 4.
Solution:
Below is given the frequency distribution table of the given data :
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q4.1

Question 5.
Solution:
Below is given the frequency distribution table of the given data
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q5.1

Question 6.
Solution:
(i) numerical figures
(ii) original
(iii) array
(iv) frequency
(v) tabulation

 

Hope given RS Aggarwal Solutions Class 6 Chapter 22 Data Handling Ex 22 are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.