RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS
These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS
Other Exercises
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.1
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.2
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.3
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.4
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS
Question 1.
Define complementary angles.
Solution:
Two angles whose sum is 90°, are called complementary angles.
Question 2.
Define supplementary angles.
Solution:
Two angles whose sum is 180°, are called supplementary angles.
Question 3.
Define adjacent angles.
Solution:
Two angles which have common vertex and one arm common are called adjacent angles.
Question 4.
The complement of an acute angles is…….
Solution:
The complement of an acute angles is an acute angle.
Question 5.
The supplement of an acute angles is………
Solution:
The supplement of an acute angles is a obtuse angle.
Question 6.
The supplement of a right angle is…….
Solution:
The supplement of a right angle is a right angle.
Question 7.
Write the complement of an angle of measure x°.
Solution:
The complement of x° is (90° – x)°
Question 8.
Write the supplement of an angle of measure 2y°.
Solution:
The supplement of 2y° is (180° – 2y)°
Question 9.
If a wheel has six spokes equally spaced, then find the measure of the angle between two adjacent spokes.
Solution:
Total measure of angle around a point = 360°
Number of spokes = 6
∴ Angle between the two adjacent spokes = \(\frac { { 360 }^{ \circ } }{ 6 }\) = 60°
Question 10.
An angle is equal to its supplement. Determine its measure.
Solution:
Let required angle = x°
Then its supplement angle = 180° – x
x = 180° – x
⇒ x + x = 180°
⇒ 2x = 180° ⇒ x = \(\frac { { 180 }^{ \circ } }{ 2 }\) = 90°
∴ Required angle = 90°
Question 11.
An angle is equal to five times its complement. Determine its measure.
Solution:
Let required measure of angle = x°
∴ Its complement angle = 90° – x
∴ x = 5(90° – x)
⇒ x = 450° – 5x
⇒ x + 5x = 450°
⇒ 6x = 450°
⇒ x = \(\frac { { 450 }^{ \circ } }{ 6 }\) = 75°
∴ Required angle = 75°
Question 12.
How many pairs of adjacent angles are formed when two lines intersect in a point?
Solution:
If two lines AB and CD intersect at a point O, then pairs of two adjacent angles are, ∠AOC and ∠COB, ∠COB and ∠BOD, ∠BOD and DOA, ∠DOA and ∠ZAOC
i.e, 4 pairs
Hope given RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS are helpful to complete your math homework.
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