## RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder Ex 19.2

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder Ex 19.2

Other Exercises

- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder Ex 19.1
- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder Ex 19.2
- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS
- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder MCQS

Question 1.

A soft drink is available in two packs – (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and

(ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much? [NCERT]

Solution:

In first case, in a rectangular container of soft drink, the length of base = 5 cm

and Width = 4 cm

Height = 15 cm

∴ Volume of soft drink = lbh = 5 x 4 x 15 = 300 cm^{3}

and in second case, in a cylindrical container, diameter of base = 7 cm

∴ The soft drink in second container is greater and how much greater = 385 cm – 380 cm^{2} = 85 cm^{2}

Question 2.

The pillars of a temple are cylindrically shaped. If each pillar has a circular base of radius 20 cm and height 10 m. How much concrete mixture would be required to build 14 such pillars? [NCERT]

Solution:

Radius of each pillar (r) = 20 cm

Question 3.

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm^{3} of wood has a mass of 0.6 gm. [NCERT]

Solution:

Inner diameter of a cylindrical wooden pipe = 24 cm

Question 4.

If the lateral surface of a cylinder is 94.2 cm^{2} and its height is 5 cm, find:

(i) radius of its base

(ii) volume of the cylinder [Use π = 3.14] [NCERT]

Solution:

Lateral surface area of a cylinder = 94.2 cm2

Question 5.

The capacity of a closed cylindrical vessel of height 1 m is 15.4 litres. How many square metres of metal sheet would be needed to make it? [NCERT]

Solution:

The capacity of a closed cylindrical vessel = 15.4 l

Question 6.

A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients? [NCERT]

Solution:

Diameter of the cylindrical bowl = 7 cm

∴ Radius (r) = \(\frac { 7 }{ 2 }\)cm

Level of soup in it = 4 cm

∴ Volume of soup in one bowl for one patient

Question 7.

A hollow garden roller, 63 cm wide with a girth of 440 cm, is made of 4 cm thick iron. Find the volume of the iron.

Solution:

Width of hollow cylinder (A) = 63 cm

Girth = 440 cm

Question 8.

The cost of painting the total outside surface of a closed cylindrical oil tank at 50 paise per square decimetre is ₹ 198. The height of the tank is 6 times the radius of the base of the tank. Find the volume corrected to 2 decimal places.

Solution:

Rate of painting = 50 paise per dm^{2}

Total cost = ₹198

Question 9.

The radii of two cylinders are in the ratio 2 : 3 and their heights are in the ratio 5:3. Calculate the ratio of their volumes and the ratio of their curved surfaces.

Solution:

Ratio in radii of two cylinders = 2:3

and ratio in their heights = 5:3

Let radius of the first cylinder (r_{1}) = 2x

and radius of second cylinder (r_{2}) = 3x

and height of first cylinders (h_{1}) = 5y

and height of second cylinder (h_{2}) = 3y

(i) Now volume of the first cylinder = πr^{2}h = π(2x)^{2} x 5y = 20πx^{2}2y

and volume of tlie second cylinder = π(3x)^{2} x 3y = π x 9×2 x 3y = 27πx^{2}y

Now ratio in their volume

= 20πx^{2}y : 21πx^{2}y = 20 : 27

(ii) Curved surface area of first cylinder = 2πrh = 2π x 2x x 5y =20πxy

and curved surface area of second cylinder = 2π x 3x x = 1 8πxy

∴ Ratio in their curved surface area

= 20πxy : 18πxy = 10 : 9

Question 10.

The ratio between the curved surface area and the total surface area of a right circular cylinder is 1 : 2. Find the volume of the cylinder, if its total surface area is 616 cm^{2}.

Solution:

Ratio in curved surface area and total surface area of a cylinder =1:2

Total surface area = 616 cm^{2}

Question 11.

The curved surface area of a cylinder is 1320 cm^{2} and its base had diameter 21 cm. Find the height and the volume of the cylinder. [Use π = 22/7]

Solution:

Curved surface area of a cylinder = 1320 cm^{2}

Diameter of the base = 21 cm

Question 12.

The ratio between the radius of the base and the height of a cylinder is 2 : 3. Find the total surface area of the cylinder, if its volume is 1617 cm^{3}.

Solution:

Ratio between radius and height of a cylinder = 2:3

Volume =1617 cm^{3}

Let radius (r) = 2x

Then height (h) = 3x

∴ Volume = πr^{2}h

Question 13.

A rectangular sheet of paper, 44 cm x 20 cm, is rolled along its length of form a cylinder. Find the volume of the cylinder so formed.

Solution:

Length of sheet = 44 cm

Breadth = 20 cm

By rolling along length, the height of cylinder (h) = 20cm

and circumference of the base = 44cm

Question 14.

The curved surface area of a cylindrical pillar is 264 m2 and its volume is 924 m3. Find the diameter and the height of the pillar.

Solution:

Curved surface area of a pillar = 264 m^{2}

and volume = 924 m^{3}

Let r be the radius and It be height, then 2πrh = 264

Question 15.

Two circular cylinders of equal volumes have their heights in the ratio 1 : 2. Find the ratio of their radii.

Solution:

Volumes of two cylinders are equal Ratio in their height h_{1} :h_{2} = 1: 2

Question 16.

The height of a right circular cylinder is 10.5 m. Three times the sum of the areas of its two circular faces is twice the” area of the curved surface. Find the volume of the cylinder.

Solution:

Height of a right circular cylinder = 10.5 m

3 x sum of areas of two circular faces

= 2 x area of curved surface

Let r be that radius,

Question 17.

How many cubic metres of earth must be dugout to sink a well 21 m deep and 6 m diameter? Find the cost of plastering the inner surface of the well at ₹9.50 per m^{2}.

Solution:

Diameter of a well = 6 m

∴ Radius (r) = \(\frac { 6 }{ 2 }\) = 3 m

Depth (h) = 21 m

∴ Volume of earth dugout = πr^{2}h

Question 18.

The trunk of a tree is cylindrical and its circumference is 176 cm. If the length of the trunk is 3 m. Find the volume of the timber that can be obtained from the trunk.

Solution:

Circumference of a cylindrical trunk of a tree = 176 cm

Question 19.

A cylindrical container with diameter of base 56 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 32 cm x 22 cm x 14 cm. Find the rise in the level of the water when the solid is completely submerged.

Solution:

Diameter of cylindrical container = 56 cm

∴ Radius (r) = \(\frac { 56 }{ 2 }\) = 28 cm

Dimensions of a rectangular solid are = 32 cm x 22 cm x 14 cm

∴ Volume of solid = lbh

= 32 x 22 x 14 = 9856 cm^{3}

∴ Volume of water in the container = 9856 cm^{3}

Let h be the level of water, then

πr2h = 9856

Question 20.

A cylindrical tube, open at both ends, is made of metal. The internal diameter of the tube is 10.4 cm and its length is 25 cm. The thickness of the metal is 8 mm everywhere. Calculate the volume of the metal.

Solution:

Length of metallic tube = 25 cm

Inner diameter = 10.4 cm

∴ Radius (r) = \(\frac { 10.4 }{ 2 }\) = 5.2 cm

Thickness of metal = 8 mm

∴ Outer radius (R) = 5.2 + 0.8 = 6.0 cm

Volume of metal used = π(R^{2} – r^{2}) x h

Question 21.

From a tap of inner radius 0.75 cm, water flows at the rate of 7 m per second. Find the volume in litres of water delivered by the pipe in one hour.

Solution:

Inner radius of a tap = 0.75 cm

Speed of flow of water in it = 7 m/s

Time = 1 hour

∴ Length of flow of water (h)

= 7 x 60 x 60 m = 25200 m

∴ Volume of water = πr^{2}h

Question 22.

A rectangular sheet of paper 30 cm x 18 cm can be transformed into the curved surface of a right circular cylinder in two ways i.e., either by rolling the paper along its length or by rolling it along its breadth. Find the ratio of the volumes of the two cylinders thus formed.

Solution:

Size of rectangular sheet = 30 cm x 18 cm

∴ Length of sheet = 30 cm

and breadth = 18 cm

By folding length wise,

Height = 18 cm

and circumference = 30 cm

Question 23.

How many litres of water flow out of a pipe having an area of cross-section of 5 cm^{2} in one minute, if the speed of water in the pipe is 30 cm/sec?

Solution:

Area of the cross-section of the pipe = 5 cm^{2}

Speed of water flow = 30 cm/sec

Period = 1 minute

∴ Flow of water in 1 minute = 30 x 60 cm = 1800 cm

Area of mouth of pipe = 5 cm^{2}

∴ Volume = 1800 x 5 = 9000 cm^{3}

Volume of water in litres = 9000 ml

Question 24.

Find the cost of sinking a tubewell 280 m deep, having diameter 3 m at the rate of ₹3.60 per cubic metre. Find also the cost of cementing its inner curved surface at ₹2.50 per square metre.

Solution:

Depth of well (h) = 280 m

Diameter = 3 m

Question 25.

Find the length of 13.2 kg of copper wire of diameter 4 mm, when 1 cubic cm of copper weighs 8.4 gm.

Solution:

Weights of copper wire = 13.2 kg

Diamter = 4 mm

Question 26.

A solid cylinder has a total surface area of 231 cm^{2}. Its curved surface area is \(\frac { 2 }{ 3 }\) of the total surface area. Find the volume of the cylinder.

Solution:

Surface area of solid cylinder = 231 cm^{2}

and curved surface area = \(\frac { 2 }{ 3 }\) of 231 cm^{2}

Question 27.

A well with 14 m diameter is dug 8 m deep. The earth taken out of it has been evenly spread all around it to a width of 21 m to form an embankment. Find the height of the embankment.

Solution:

Diameter of a well = 14 m

∴ Radius (r) = y = 7 m

Depth (h) = 8 m

∴ Volume of the earth dugout = πr^{2}h

Question 28.

The difference between inside and outside surfaces of a cylindrical tube 14 cm long is 88 sq. cm. If the volume of the tube is 176 cubic cm, find the inner and outer radii of the tube.

Solution:

Length of cylindrical tube = 14 cm

Difference betveen the outer surface and inner surface = 88 cm^{2}

and volume of the tube = 176 cm^{3}

Let R and r be the outer and inner radius of the tube

Question 29.

Water flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 6 metres per second into a cylindrical tank. The radius of whose base is 60 cm. Find the rise in the level of water in 30 minutes?

Solution:

Internal diameter of the pipe = 2 cm

∴ Radius (r) = \(\frac { 2 }{ 2 }\) = 1 cm

Speed of water flow = 6m per second Water in 30 minutes (h) = 6 x 60 x 30 m = 10800 m

Volume of water = πr^{2}h

Question 30.

A cylindrical water tank of diameter 1.4 m and height 2.1 m is being fed by a pipe of diameter 3.5 cm through which water flows at the rate of 2 metre per second. In how much time the tank will be filled?

Solution:

Diameter of cylindrical tank = 1.4 m

∴ Radius (r) = \(\frac { 1.4 }{ 2 }\) = 0.7 m

and height (h) = 2.1 m

∴ Volume of water in the tank = πr^{2}h

Question 31.

The sum of the radius of the base and height of a solid cylinder is 37 m. If the total surface area of the solid cylinder is 1628 m^{2}. Find the volume of the cylinder.

Solution:

Sum of radius and height of a cylinder = 37 m

Let r be the radius and h be the height, then r + h = 37m …(i)

Total surface area of a solid cylinder = 1628m^{3}

Question 32.

A well with 10 m inside diameter is dug 8.4 m deep. Earth taken out of it is spread all around it to a width of 7.5 m to form an embankment. Find the height of the embankment.

Solution:

Diameter of the well = 10 m 10

∴ Radius (r) = \(\frac { 10 }{ 2 }\) = 5 m

Depth (h) = 8.4 m

∴ Volume of earth dugout = πr^{2}h

Hope given RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder Ex 19.2 are helpful to complete your math homework.

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