## RD Sharma Class 9 Solutions Chapter 2 Exponents of Real Numbers MCQS

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 2 Exponents of Real Numbers MCQS

Mark the correct alternative in each of the following:

Question 1.

The value of {2 – 3 (2 – 3)^{3}}^{3} is

(a) 5

(b) 125

(c) \(\frac { 1 }{ 5 }\)

(d) -125

Solution:

{2 – 3 (2 – 3)^{3}}^{3} = {2 – 3 (-1)^{3}}^{3
}= {2 – 3 x (-1)}^{3
}= (2 + 3)^{3} = (5)^{3
}= 125 (b)

Question 2.

The value of x – y^{x-y} when x = 2 and y = -2 is

(a) 18

(b) -18

(c) 14

(d) -14

Solution:

x = 2, y = -2

x-y^{x-y} = 2 – (-2)^{2 – (-2)
}= 2 – (-2)^{2}^{ + }^{2} = 2 – (-2)^{4
}= 2 – (+16) = 2 – 16 = -14 (d)

Question 3.

The product of the square root of x with the cube root of x, is

(a) cube root of the square root of x

(b) sixth root of the fifth power of x

(c) fifth root of the sixth power of x

(d) sixth root of x

Solution:

Question 4.

The seventh root of x divided by the eighth root of x is

Solution:

Question 5.

The square root of 64 divided by the cube root of 64 is

(a) 64

(b) 2

(c) \(\frac { 1 }{ 2 }\)

(d) 64^{\(\frac { 2 }{ 3 }\)
}Solution:

Question 6.

Which of the following is (are) not equal to

Solution:

Question 7.

When simplified (x^{–}^{1} + y^{–}^{1})^{–}^{1} is equal to

Solution:

Question 8.

If 8^{x}^{+1} = 64, what is the value of 3 ^{2x}^{ +1}?

(a) 1

(b) 3

(c) 9

(d) 27

Solution:

Question 9.

If (2^{3})^{2} = 4^{x} then 3^{x} =

(a) 3

(b) 6

(c) 9

(d) 27

Solution:

Question 10.

If x^{-2}= 64, then x^{\(\frac { 1 }{ 3 }\)} + x°=

(a) 2

(b) 3

(c) \(\frac { 3 }{ 2 }\)

(c) \(\frac { 2 }{ 3 }\)

Solution:

Question 11.

When simplified ( –\(\frac { 1 }{ 27 }\))^{\(\frac { -2 }{ 3 }\)}

(a) 9

(b) -9

(c) \(\frac { 1 }{ 9 }\)

(d) –\(\frac { 1 }{ 9 }\)

Solution:

Question 12.

Which one of the following is not equal to

Solution:

Question 13.

Which one of the following is not equal to

Solution:

Question 14.

If a, b, c are positive real numbers, then

Solution:

Question 15.

Solution:

Question 16.

Solution:

Question 17.

Solution:

Question 18.

Solution:

Question 19.

Solution:

Question 20.

Solution:

Question 21.

The value of {(23 + 2^{2})^{2/3}+ (150 -29)^{1/2}}^{2} is

(a) 196

(b) 289

(c) 324

(d) 400

Solution:

{(23 + 2^{2})^{2/}^{3} + (150 – 29)^{1/2}}^{2
}= [(23×4)^{\(\frac { 2 }{ 3 }\)} +(150 – 29)^{\(\frac { 1 }{ 2 }\)} ]^{2
}= [(27)^{\(\frac { 2 }{ 3 }\)} + (121)^{\(\frac { 1 }{ 2 }\)} ]^{2
}= [(3^{3})^{3} +(11^{2})^{\(\frac { 1 }{ 2 }\)}]^{2} = (9 + 11)^{2
}= (20)^{2} = 400 (d)

Question 22.

(256)^{0.16}x (256)^{0.09
}(a) 4

(b) 16

(c) 64

(d) 256.25

Solution:

Question 23.

If 10^{2y} = 25, then 10^{-y} equals

Solution:

Question 24.

If 9^{X }^{+} ^{2} = 240 + 9^{X}. then x =

(a) 0.5

(b) 0.2

(c) 0.4

(d) 0.1

Solution:

Question 25.

If x is a positive real number and x^{2} = 2, then x^{3} =

(a) \(\sqrt { 2 } \)

(b) 2\(\sqrt { 2 } \)

(c) 3\(\sqrt { 2 } \)

(d) 4

Solution:

Question 26.

Solution:

Question 27.

Solution:

Question 28.

Solution:

Question 29.

Solution:

Question 30.

Solution:

Question 31.

Solution:

Question 32.

Solution:

Question 33.

If (16)^{2x + 3} = (64)^{x + 3} , then 4^{2x – 2} =

(a) 64

(b) 256

(c) 32

(d) 512

Solution:

Question 34.

Solution:

Question 35.

Solution:

Question 36.

Solution:

Question 37.

Solution:

Question 38.

Solution:

Question 39.

Solution:

Question 40.

Solution:

Hope given RD Sharma Class 9 Solutions Chapter 2 Exponents of Real Numbers MCQS are helpful to complete your math homework.

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