## RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1A

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1A
- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1B
- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1C
- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1D
- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1E
- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1F
- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1G
- RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1H

**Question 1.**

**Solution:**

(i) Nine thousand eighteen = 9,018.

(ii) Fifty four thousand seventy three = 54,073

(iii) Three lakh two thousand five hundred six = 3,02,506.

(iv) Twenty lakh ten thousand eight = 20,10,008.

(v) Six crore five lakh fifty-seven = 6,05,00,057.

(vi) Two crore two lakh two thousand two hundred two = 2,02,02,202.

(vii) Twelve crore twelve lakh twelve thousand twelve = 12,12,12,012.

(viii) Fifteen crore fifty lakh twenty thousand sixty-eight = 15,50,20,068.

**Question 2.**

**Solution:**

(i) 63,005 = Sixty three thousand five.

(ii)7,07,075 = Seven lakh, seven thousand seventy five.

(iii) 34,20,019 = Thirty-four lakh twenty thousand nineteen.

(iv) 3,05,09,0.12 = Three crore, five lakh, nine thousand twelve.

(v) 5,10,03,604 = Five crore ten lakh three thousand six hundred four.

(vi) 6,18,05,008 = Six crore eighteen lakh five thousand eight.

(vii) 19,09,09,900 = Nineteen crore nine lakh, nine thousand nine hundred.

(viii) 6,15.30,807 = Six crore fifteen lakh, thirty thousand eight hundred seven.

(ix) 6,60,60,060 = Six crore sixty lakh sixty thousand sixty. Ans.

**Question 3.**

**Solution:**

(i) 15,768 = (1 x 10000) + (5 x 1000) + (7 x 100) + (6 x 10) + (8 x 1)

(ii) 3,08,927 = (3 x 100000) + (8 x 1000) + (9 x 100) +(2 x 10) +(7 x 1)

(iii) 24,05,609 = (2 x 1000000) + (4 x 100000) + (5 x 1000) + (6 x 100) + (9 x 1)

(iv) 5,36,18,493 = (5 x 10000000) + (3 x 1000000) + (6 x 100000) + (1 x 10000) + (8 x 1000) + (4 x 100) + (9 x 10) + (3 x 1)

(v) 6,06,06,006 = (6 x 10000000) + (6 x 100000) + (6 x 1000) + (6 x 1)

(vi) 9,10,10,510 = (9 x 10000000) + (1 x 1000000) + (1 x 10000) + (5 x 100) + (1 x 10) Ans,

**Question 4.**

**Solution:**

(i) 6 x 10000 + 2 x 1000 + 5 x 100 + 8 x 10 + 4 x 1

= 60000 + 2000 + 500 + 80 + 4

= 62,584.

(ii) 5 x 100000 + 8 x 10000 + 1 x 1000 + 6 x 100 + 2 x 10 + 3 x 1

= 500000 + 80000 + 1000 + 600 + 20 + 3

= 5,81,623

(iii) 2 x 10000000 + 5 x 100000 + 7 x 1000 + 9 x 100 + 5 x 1

= 20000000 + 500000 + 7000 + 900 + 5

= 2,05,07,905

(iv) 3 x 1000000 + 4 x 100000 + 6 x 1000 + 5 x 100 + 7 x 1

= 3000000 + 400000 + 6000 + 500 + 7

= 34,06,507 Ans.

**Question 5.**

**Solution:**

In 79520986

Value of first 9 = 9000000

and value of second 9 = 900

Difference = 9000000 – 900

= 89,99,100 Ans.

**Question 6.**

**Solution:**

In 27650934

place value of 7 = 7000000

and face value of 7 = 7

Difference = 7000000 – 7

= 6999993 Ans.

**Question 7.**

**Solution:**

There are 900000 6-digits numbers in all

i.e. 999999 – 99999

= 900000 Ans

**Question 8.**

**Solution:**

There are 9999999 – 999999

= 9000000 7-digits numbers in all.

**Question 9.**

**Solution:**

In 1,00,000, there are 100 thousands. Ans.

**Question 10.**

**Solution:**

In 10000,000, there are 10000 thousands.

**Question 11.**

**Solution:**

Given Number = 738

Reversing its digits = 837

Difference between 738 and 837

= 837 – 738

= 99 Ans.

**Question 12.**

**Solution:**

Numbers after 9547999

= 9547999 + 1

= 9548000 Ans.

**Question 13.**

**Solution:**

Number first before 9900000

= 9900000 – 1

= 9899999 Ans.

**Question 14.**

**Solution:**

Number first before 10000000

= 10000000 – 1

= 9999999 Ans.

**Question 15.**

**Solution:**

3-digits numbers using 2, 3, 4 taking each digit only once will be

234, 243, 324, 342, 423, 432 Ans.

**Question 16.**

**Solution:**

The smallest number by using different digits 3, 1, 0, 5 and 7 will be

= 10357 Ans.

**Question 17.**

**Solution:**

The largest number formed by using different digits 2, 4, 0, 3, 6 and 9 will be

= 964320. Ans.

**Question 18.**

**Solution:**

(i) Seven hundred thirty five thousand eight hundred twenty-one.

(ii) Six million fifty seven thousand eight hundred ninety-four.

(iii) Fifty-six million nine hundred forty-three thousand eight hundred twenty-one.

(iv) Thirty-seven million five hundred two thousand ninety-three.

(v) Eighty-nine million three hundred fifty thousand sixty-four.

(vi) Ninety million seven hundred three thousand and six. Ans.

**Question 19.**

**Solution:**

**OBJECTIVE QUESTIONS**

**Tick the correct answer in each of the following :**

**Question 20.**

**Solution:**

(c) Because 6 is at lakh place.

**Question 21.**

**Solution:**

(a) Because face value is always same.

**Question 22.**

**Solution:**

(b) Because place value and face value of 5 in 87653421 are 50000 and 5.

difference

= 50000 – 5

= 49995.

**Question 23.**

**Solution:**

(b) Smallest counting number or natural number is 1.

**Question 24.**

**Solution:**

(b) Number of 4-digits numbers

= 9999 – 999 (i.e. these are 1000 to 9999)

= 9000

**Question 25.**

**Solution:**

(b) Number of 7-digit numbers (from 1000000 to 9999999)

= 9999999 – 999999

= 9000000

**Question 26.**

**Solution:**

(c) Numbers of 8-digit numbers (from 10000000 to 99999999)

= 99999999 – 9999999

= 90000000

**Question 27.**

**Solution:**

(b) Because 1000000 – 1

= 999999 Ans.

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1A are helpful to complete your math homework.

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