## RS Aggarwal Class 6 Solutions Chapter 21 Concept of Perimeter and Area Ex 21B

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21B

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21A
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21B
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21C
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21D
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21E

**Question 1.**

**Solution:**

(i) Radius of the circle (r) = 28 cm

Circumference = 2 πr

= 2 x \(\\ \frac { 22 }{ 7 } \) x 28 cm

= 176 cm Ans.

**Question 2.**

**Solution:**

(i) Diameter of the circle (d) = 14 cm

Circumference = πd

= \(\\ \frac { 22 }{ 7 } \) x 14

= 44 cm

**Question 3.**

**Solution:**

Circumference of the circle = 176 cm

Let r be the radius, then

**Question 4.**

**Solution:**

Circumference of a wheel = 264 cm

Let d be its diameter, then

πd = 264

=> \(\\ \frac { 22 }{ 7 } d\)

= 264

**Question 5.**

**Solution:**

Diameter of the wheel (d) = 77 cm

Circumference = πd

**Question 6.**

**Solution:**

Diameter of the wheel = 70 cm

circumference = πd

Hope given RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21B are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.