## RS Aggarwal Class 6 Solutions Chapter 21 Concept of Perimeter and Area Ex 21D

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21D

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21A
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21B
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21C
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21D
- RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21E

**Question 1.**

**Solution:**

(i) Length (l) = 46 cm

Breadth (b) = 25 cm

Area of rectangle = l x b

= 46 x 25 sq. cm

= 1150 sq.cm.

(ii) Length (l) = 9 m

Breadth (b) = 6 m

Area = l x b = 9 x 6

= 54 sq. metre Ans.

(iii) Length (l) = 14.5 m

Breadth (b) = 6.8 m

Area = l x b

= 14.5 x 6.8 sq. m

= 98.6 sq. m Ans.

(iv) Length (l) = 2m 5cm

= 2x 100 cm + 5 cm

= 200 cm + 5 cm

= 205 cm

Breadth = 60 cm

Area = l x b

= 205 cm x 60 cm

= 12300 cm²

(v) Length (l) = 3.5 km

Breadth (b) = 2 km

Area = l x b

= 3.5 x 2

= 7 sq. km. Ans.

**Question 2.**

**Solution:**

Side of a square plot = 14 m

Area = (Side)²

= (14)²

= 196 m²

**Question 3.**

**Solution:**

Length of top of table (l) = 2 m, 25 cm = 2.25 m

Breadth (l) = 1 m 20 cm = 1.20 m

Area of the top of the table = l x b

= (2.25 x 1.20) sq. m

= 2.7 sq. m. Ans.

**Question 4.**

**Solution:**

Length of carpet (l) = 30 m 75 cm

= 30.75 m

Breadth (b) = 80 cm = 0.80 m

Area of the carpet = l x b

= (30.75 x 0.80) sq. m

= 24.6 sq. m

Cost of one square metre = Rs. 20

Total cost = 24.6 x 150

= Rs. 3690. Ans

**Question 5.**

**Solution:**

Length of the sheet of paper 3 m 24 cm

= 300 cm + 24 cm

= 324 cm

Breadth of the sheet of the paper 1 m 72 cm

= 100 cm + 72 cm

= 172 cm

Area of the sheet of paper = (324 x 172) cm²

Also, area of the piece of paper required for an envelope = (18 x 12) cm².

Number of envelopes that can be made

= \(\\ \frac { 324\times 172 }{ 18\times 12 } \)

= 258

**Question 6.**

**Solution:**

Length of room (l) = 12.5 m

Breadth (b) = 8 m

Area = l x b

= (12.5 x 8) sq. m

= 100 sq. m

Side of square carpet (a) = 8 m

Area of carpet = a² = (8 x 8) sq. m.

= 64 square metre

Area left without carpet = 100 sq. m – 64 sq. m

= 36 sq. m Ans.

**Question 7.**

**Solution:**

Length of the lane = 150 m

Breadth of the lane = 9 m

Area of the lane = (150 x 9) m²

= 1350 m²

Area of the brick = 22.5 cm x 7.5 cm

= 168.75 cm²

**Question 8.**

**Solution:**

Length of room (l) = 13 m

Breadth (b) = 9 m

Area of floor or carpet = l x b

= 13 x 9

= 117 sq. m

**Question 9.**

**Solution:**

Let the length of the rectangular park = 5x metres

and the breadth of the rectangular park = 3x metres

**Question 10.**

**Solution:**

Side of the square plot = 64 m

Perimeter of the square plot = 4 x Side

= 4 x 64

= 256 m

Perimeter of the rectangular plot = Perimeter of the square plot = 256 m

Length of the rectangular plot = 70 m

Perimeter = 2 x (Length + Breadth)

256 = 2 (70 + b)

256 = 140 + 2b

=> 2b = 256 – 140

=> 2b = 116

b = \(\\ \frac { 116 }{ 2 } \) = 58 cm

Area of the rectangular plot = (length x breadth)]

= (70 x 58) m²

= 4060 m²

Area of the square plot = Side x Side

= (64 x 64) m²

= 4096 m².

Square plot has the greater area than that of the rectangular plot by

(4096 – 4060)

= 36 m².

**Question 11.**

**Solution:**

Total cost of cultivating the rectangular field = Rs. 71400

Rate of cultivating = Rs. 35 per sq. m

**Question 12.**

**Solution:**

Area of rectangle = 540 sq. cm

Length (l) = 36 cm

**Question 13.**

**Solution:**

Measure of a marble tile = 12cm x 10cm

Area of wall = 4 m x 3 m

= 12 m²

Area of one marble tile

= 12 x 10

= 120 cm²

**Question 14.**

**Solution:**

Area of a rectangle = 600 cm²

Breadth = 25 cm

**Question 15.**

**Solution:**

diagonal of square = 5 √2

**Question 16.**

**Solution:**

(i) We name the given region as shown in the figure

**Question 17.**

**Solution:**

Measures are in cm

(i) In the figure, there are three rectangles and one square

= 5(6 x 6) cm²

= 180 cm²

Hope given RS Aggarwal Solutions Class 6 Chapter 21 Concept of Perimeter and Area Ex 21D are helpful to complete your math homework.

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