RS Aggarwal Class 7 Solutions Chapter 10 Percentage Ex 10C
These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10C.
Other Exercises
- RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10A
- RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10B
- RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10C
- RS Aggarwal Solutions Class 7 Chapter 10 Percentage CCE Test Paper
Objective Questions :
Mark (✓) against the correct answer in each of the following :
Question 1.
Solution:
(b) \(\frac { 3 }{ 4 }\) = \(\frac { 3 }{ 4 }\) x 100 = 75 %
Question 2.
Solution:
(c)
2 : 5 = \(\frac { 2 }{ 5 }\) = \(\frac { 2 }{ 5 }\) x 100 = 40%
Question 3.
Solution:
(c)
Question 4.
Solution:
(c) x% of 75 = 9
Question 5.
Solution:
(d)
Question 6.
Solution:
(b)
Let x% of 1 day = 36 minutes
Question 7.
Solution:
(a)
Let x be the required number
Question 8.
Solution:
(b)
Let x be the required number, then
Question 9.
Solution:
(d)
Let ore = x, then
5% of x = 400g
\(\frac { x x 5 }{ 100 }\) 400
Question 10.
Solution:
(b)
Let gross value of T.V = x
Commission = 10%
After deducting commission, the value
Question 11.
Solution:
(b)
Increase in salary = 25%
Let original salary = x
Question 12.
Solution:
(c)
Let x be the number of total examinees
No. of examinees passed
Question 13.
Solution:
(c)
Let total number of apples = x
Question 14.
Solution:
(b)
Present value of machine = Rs. 25000
Rate of depreciation = 10% p.a.
Value of machine after one year
Question 15.
Solution:
(c) Let x be numbers
Question 16.
Solution:
(c) 60% of 450
= \(\frac { 60 }{ 100 }\) x 450 = 270
Question 17.
Solution:
(d) Rate of reduction = 6%
Price after reduction = Rs. 658
Question 18.
Solution:
(b) Boys = 70% of students
No. of girls = 240
Girls percentage = 100 – 70 = 30%
Question 19.
Solution:
(c) Let number = x
11% of x – 7% of x = 18
Question 20.
Solution:
(a) Let number = x
35% of x + 39 = x
Question 21.
Solution:
(c) Pass marks = 36%
A students get =145 marks
But failed by 3 5 marks
Then pass marks = 145 + 35 = 180
Maximum marks = \(\frac { 180 x 100 }{ 36 }\) = 500
Question 22.
Solution:
(d) Let number be = x
Then decreasing by 40%
Hope given RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10C are helpful to complete your math homework.
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