## RS Aggarwal Class 7 Solutions Chapter 8 Ratio and Proportion CCE Test Paper

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 8 Ratio and Proportion CCE Test Paper.

**Other Exercises**

- RS Aggarwal Solutions Class 7 Chapter 8 Ratio and Proportion Ex 8A
- RS Aggarwal Solutions Class 7 Chapter 8 Ratio and Proportion Ex 8B
- RS Aggarwal Solutions Class 7 Chapter 8 Ratio and Proportion Ex 8C
- RS Aggarwal Solutions Class 7 Chapter 8 Ratio and Proportion CCE Test Paper

**Question 1.**

**Solution:**

**Question 2.**

**Solution:**

The sum of ratio terms is = 2 + 3 + 5 = 10

Then, we have :

A’s share = ₹ \(\frac { 2 }{ 10 }\) x 1100 = ₹ 220

B’s share = ₹ \(\frac { 3 }{ 10 }\) x 1100 = ₹ 330

C’s share = ₹ \(\frac { 5 }{ 10 }\) x 1100 = ₹ 550

**Question 3.**

**Solution:**

Product of the extremes = 25 x 6 = 150

Product of the means = 36 x 5 = 180

The product of the extremes is not equal to that of the means.

Hence, 25, 36, 5 and 6 are not in proportion.

**Question 4.**

**Solution:**

x : 18 :: 18 : 108

⇒ x x 108 = 18 x 18

(Product of extremes = Product of means)

⇒ 108x = 324

⇒ x = 3

Hence, the value of x is 3.

**Question 5.**

**Solution:**

Suppose that the numbers are 5x and 7x

Then, 5x + 7x = 84

12x = 84

x = 7

Hence, the numbers are (5 x 7) = 35 and (7 x 7) = 49.

**Question 6.**

**Solution:**

Suppose that the present ages of A and B are 4x yrs and 3x yrs, respectively

Eight years ago, age of A = (4x – 8) yrs

Eight years ago, age of B = (3x – 8) yrs

Then,

(4x – 8) : (3x – 8) = 10 : 7

⇒ \(\frac { 4x – 8 }{ 3x – 8 }\) = \(\frac { 10 }{ 7 }\)

⇒ 28x – 56 = 30x – 80

⇒ 2x = 24

⇒ x = 12

**Question 7.**

**Solution:**

Distance covered in 60 min = 54 km

Distance covered in 1 min = \(\frac { 54 }{ 60 }\) km

Distance covered in 40 min = \(\frac { 54 }{ 60 }\) x 40 = 36 km

**Question 8.**

**Solution:**

Suppose that the third proportional to 8 and 12 is x

Then, 8 : 12 :: 12 : x

⇒ 8x = 144 (Product of extremes = Product of means)

x = 18

Hence, the third proportional is 18.

**Question 9.**

**Solution:**

40 men can finish the work in 60 days

1 man can finish the work in 60 x 40 days [Less men, more days]

75 men will finish the work in = \(\frac { 60 x 40 }{ 75 }\) = 32 days

Hence, 75 men will finish the same work in 32 days.

**Mark (✓) against the correct answer in each of the following :**

**Question 10.**

**Solution:**

(d) 6 : 4 : 3

A = \(\frac { 3 }{ 2 }\) B

C = \(\frac { 3 }{ 4 }\) B

A : B : C = \(\frac { 3 }{ 2 }\) B : B : \(\frac { 3 }{ 4 }\) B

= 6 : 4 : 3

**Question 11.**

**Solution:**

(a) 2 : 3 : 4

**Question 12.**

**Solution:**

(c) 11 : 3

**Question 13.**

**Solution:**

(a) 3

Let us assume that the number to be subtracted is x

Then, (15 – x) : (19 – x) = 15 : 3

⇒ \(\frac { 15 – x }{ 19 – x }\) = \(\frac { 3 }{ 4 }\)

⇒ 60 – 4x = 57 – 3x

⇒ x = 3

**Question 14.**

**Solution:**

(b) ₹ 360

Sum of the ratio terms = 4 + 3 = 7

B’s share = ₹ 840 x \(\frac { 3 }{ 7 }\) = ₹ 360

**Question 15.**

**Solution:**

(c) 40 years

Suppose that the present ages of A and B are 5x yrs and 2x yrs, respectively

After 5 years, the ages of A and B will be (5x + 5) yrs and (2x + 5) yrs, respectively

Then, (5x+ 5) : (2x + 5) = 15 : 7

⇒ \(\frac { 5x+ 5 }{ 2x + 5 }\) = \(\frac { 15 }{ 7 }\)

Cross multiplying; we get:

⇒ 35x + 35 = 30x + 75

⇒ 5x = 40

⇒ x = 8

Then, the present age of A is 5 x 8 = 40 yrs.

**Question 16.**

**Solution:**

(a) 896

Suppose that the number of boys in the school is x

Then, x : 320 = 9 : 5

⇒ 5x = 2880

⇒ x = 576

Hence, total strength of the school = 576 + 320 = 896

**Question 17.**

**Solution:**

**Question 18.**

**Solution:**

(i) True

Suppose that the men proportional is x

Then, 0.4 : x :: x : 0.9

⇒ 0.9 x 0.4 = x x x (Product of extremes = Product of means)

⇒ x² = 0.36

⇒ x = 0.6

(ii) False

Suppose that the third proportional is x.

Then, 9: 12 :: 12 : x

⇒ 9x = 144 (Product of extremes = Product of means)

⇒ x = 16

(iii) True

8 : x :: 48 : 18

⇒ 144 = 48x (Product of extremes = Product of means)

⇒ x = 3

(iv) True

Hope given RS Aggarwal Solutions Class 7 Chapter 8 Ratio and Proportion CCE Test Paper are helpful to complete your math homework.

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