## RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1G.

**Other Exercises**

- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1A
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1B
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1C
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1D
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1E
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1F
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1G
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1H

**Question 1.**

**Solution:**

Total length of rope = 11 m.

Sum of lengths of two parts

**Question 2.**

**Solution:**

Total weight of rice and drum

= \(40\frac { 1 }{ 6 } \) kg

= \(13\frac { 3 }{ 4 } \)

**Question 3.**

**Solution:**

Total weight of three types of fruits

= \(19\frac { 1 }{ 3 } \) kg

= \(\\ \frac { 58 }{ 3 } \) kg

**Question 4.**

**Solution:**

Total earnings = Rs 160

**Question 5.**

**Solution:**

Cost of 1m cloth = Rs \(63\frac { 3 }{ 4 } \)

**Question 6.**

**Solution:**

Distance covered in 1 hour

= \(60\frac { 2 }{ 5 } \)

= \(\\ \frac { 302 }{ 5 } \)

**Question 7.**

**Solution:**

Length of rectangular park

= \(36\frac { 3 }{ 5 } \) m

= \(\\ \frac { 183 }{ 5 } \)

and breadth = \(16\frac { 2 }{ 3 } \) = \(\\ \frac { 50 }{ 3 } \) m

**Question 8.**

**Solution:**

Side of a square plot = \(8\frac { 1 }{ 2 } \) m

= \(\\ \frac { 17 }{ 2 } \) m

Area = (Side)² = Side x Side

= \(\\ \frac { 17 }{ 2 } \) x \(\\ \frac { 17 }{ 2 } \) m²

= \(\\ \frac { 289 }{ 4 } \) m²

= \(72\frac { 1 }{ 4 } \) m²

**Question 9.**

**Solution:**

Cost of 1 litre petrol = Rs \(63\frac { 3 }{ 4 } \)

= Rs \(\\ \frac { 255 }{ 4 } \)

Cost of 34 litres of petrol

= \(\\ \frac { 255 }{ 4 } \) x 34

= \(\\ \frac { 255X17 }{ 2 } \)

= \(\\ \frac { 4335 }{ 2 } \)

= Rs \(2167\frac { 1 }{ 2 } \)

**Question 10.**

**Solution:**

Distance covered in 1 hour = 1020 km.

Distance covered in \(4\frac { 1 }{ 6 } \) hours

= 1020 x \(4\frac { 1 }{ 6 } \)

= 1020 x \(\\ \frac { 25 }{ 6 } \) km

= \(\\ \frac { 25500 }{ 6 } \)

= 4250 km. Ans.

**Question 11.**

**Solution:**

Cost of \(3\frac { 1 }{ 2 }\) metres cloth

= Rs \(166\frac { 1 }{ 4 }\)

**Question 12.**

**Solution:**

Total length of piece of chord

= \(71\frac { 1 }{ 2 }\)

No. of pieces = 26

**Question 13.**

**Solution:**

Area of a room = \(65\frac { 1 }{ 4 }\) m²

Breadth = \(5\frac { 7 }{ 16 }\) m

**Question 14.**

**Solution:**

Product of two fractions = \(9\frac { 3 }{ 5 }\)

= \(\\ \frac { 48 }{ 5 } \)

One fraction = \(9\frac { 3 }{ 7 }\) = \(\\ \frac { 66 }{ 7 } \)

**Question 15.**

**Solution:**

Let total number of students =1

and no.of boys = \(\\ \frac { 5 }{ 8 } \)

**Question 16.**

**Solution:**

Let no of pages = 1

Then no. of pages read = \(\\ \frac { 7 }{ 9 } \)

**Question 17.**

**Solution:**

Total amount, Rita has = Rs 300

Amount spent on notebooks = \(\\ \frac { 1 }{ 3 } \) of 300

**Question 18.**

**Solution:**

Total amount earned by Amit = Rs 32000

Amount spent on food = \(\\ \frac { 1 }{ 4 } \) of Rs 32000

**Question 19.**

**Solution:**

Let number = 1

Then difference between \(\\ \frac { 3 }{ 5 } \) and \(\\ \frac { 2 }{ 7 } \)

**Question 20.**

**Solution:**

Let total number of spectators = 1

No. of spectators in covered place = \(\\ \frac { 2 }{ 7 } \) of

1 = \(\\ \frac { 2 }{ 7 } \)

Hope given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1G are helpful to complete your math homework.

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