## Online Education for RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A

These Solutions are part of RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A.

**Other Exercises**

- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13A
- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13B
- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13C
- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13D

**Question 1.**

**Solution:**

(i) Length of cuboid (l) = 12cm

Breadth (b) = 8cm

and height (h) = 4.5cm

**Question 2.
**

**Solution:**

Length of closed rectangular cistern (l) = 8m

breadth (b) = 6m

and depth (b) = 2.5m.

(i) .’. Volume of cistern = l.b.h.

= 8 x 6 x 2.5 m³ = 120m³

(ii) Total surface area = 2(lb + bh + hl)

= 2(8 x 6 + 6 x 2.5 + 2.5 x 8) cm²

= 2(48 + 15 + 20)

= 2 x 83 m²

= 166 m² Ans.

**Question 3.**

**Solution:**

Length of room (l) = 9m

Breadth (b) = 8m

and height (h) = 6.5m

**Question 4.**

**Solution:**

Length of pit (l) = 20m

Breadth (b) = 6m

**Question 5.**

**Solution:**

Length of wall (l) = 8m.

Width (b) = 22.5 cm = \(\frac { 225 }{ 10X100 } =\frac { 9 }{ 40 } m\)

and height (h) = 6m.

Volume of wall = l.b.h.

**Question 6.**

**Solution:**

Length of wall (l) = 15m.

Width (b) = 30cm = \(\frac { 30 }{ 100 } =\frac { 3 }{ 10 } m\)

Height (h) = 4m

**Question 7.**

**Solution:**

Outer length of opened cistern = 1.35m = 135 cm

Breadth = 1.08 m = 108 cm

Depth = 90cm

Thickness of iron = 2.5cm.

**Question 8.**

**Solution:**

Depth of river = 2m

width = 45m.

Length of current in 60 minutes = 3km

**Question 9.**

**Solution:**

Total cost of box = Rs. 1620

Rate per sq. m = Rs. 30

**Question 10.**

**Solution:**

Length of room (l) = 10m

Breadth (b) = 10m

Height (h) = 5m

**Question 11.**

**Solution:**

Length of hall (l) = 20m

Breadth (b) = 16m

and height (h) = 4.5m.

Volume of the air inside the hall

**Question 12.**

**Solution:**

Length of class room (l) = 10m

Width (b) = 6.4 m

Height (h) = 5m.

**Question 13.**

**Solution:**

Volume of cuboid = 1536 m³

Length (l) = 16m

Ratio in breadth and height = 3:2

Let breadth (b) = 3x

their height (h) = 2x

**Question 14.**

**Solution:**

Length of cuboid (l) = 14 cm

Breadth (b) = 11 cm .

Let height (h) =x cm

Surface area = 2(lb + bh + hl)

**Question 15.**

**Solution:**

(a) Edge of cube (a) = 9m .

(i) volume = a³ = (9)³ m³ = 729 m³

(ii) Lateral surface area = 4a²

**Question 16.**

**Solution:**

Total surface area of a cube = 1176 cm²

Let each edge he ‘a’

then 6a² =1176

**Question 17.**

**Solution:**

Lateral surface area of a cube = 900 cm²

Let ‘a’ be the edge of the cube

**Question 18.**

**Solution:**

Volume of a cube = 512 cm³

Let ‘a’ be its edge, then

**Question 19.**

**Solution:**

Edge of first-cube = 3 cm.

Volume = (3)³ = 27 cm³

**Question 20.**

**Solution:**

Area of ground = 2 hectares

= 2 x 10000 = 20000 m²

Height of rain falls 5cm = \(\frac { 5 }{ 100 } \)m

∴ Volume of rain water = 20000 x \(\frac { 5 }{ 100 } \) m³

= 1000 m³ Ans.

Hope given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A are helpful to complete your math homework.

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