Online Education for RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B

These Solutions are part of Online Education RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B.

Other Exercises

Question 1.
Solution:
Radius of the base of a cylinder (r) = 5cm.
and height (h) = 21cm

Question 2.
Solution:
Diameter of the base of the cylinder = 28cm
Radius = $$\frac { 1 }{ 2 }$$ x 28 = 14 cm
Height (h) = 40cm.

Question 3.
Solution:
Radius of cylinder (r) = 10.5cm
Height (h) = 60cm.

Question 4.
Solution:
Diameter of cylinder = 20cm
Radius (r) = $$\frac { 20 }{ 2 }$$ = 10cm

Question 5.
Solution:
Curved surface area of cylinder = 4400 cm²
Circumference of its base = 110 cm

Question 6.
Solution:
The ratio of the radius and height of a cylinder = 2:3
Volume =1617 cm³
and height = 3x.

Question 7.
Solution:
Total surface area of the cylinder = 462 cm²
Curved surface area = $$\frac { 1 }{ 3 }$$ x 462 = 154

Question 8.
Solution:
Total surface area of solid
cylinder = 231 cm²

Question 9.
Solution:
Sum of radius and height = 37m.
and total surface area = 1628 m²

Question 10.
Solution:
Total surface area = 616 cm²
Curved surface area = $$\frac { 616X1 }{ 2 }$$ = 308

Question 11.
Solution:
Volume of gold = 1 cm³
diameter of wire = 0.1 mn

Question 12.
Solution:
Ratio in the radii of two cylinders = 2:3
and ratio in the heights = 5:3
If r1 and r2 and the radii and h1 and h2 are the heights, then

Question 13.
Solution:
Side of square = 12cm
and height = 17.5cm

Question 14.
Solution:
Diameter of cylindrical bucket = 28cm
Radius (r) = $$\frac { 28 }{ 8 }$$ = 14cm
Height (h) = 72cm.

Question 15.
Solution:
Length of pipe (l) = 1m = 100cm
diameter of pipe = 3cm.
Inner radius = $$\frac { 3 }{ 2 }$$ cm

Question 16.
Solution:
Internal diameter of cylindrical tube = 10.4 cm
Radius (r) = $$\frac { 10.4 }{ 2 }$$ = 5.2cm.

Question 17.
Solution:
Length of barrel (h) = 7cm
Diameter = 5mm.

Question 18.
Solution:
Diameter of pencil = 7mm
.’. Radius (R) = $$\frac { 7 }{ 2 }$$ mm = $$\frac { 7 }{ 20 }$$ cm.
and diameter of graphite in it = 1mm

Hope given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B are helpful to complete your math homework.

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